数字范围的Grep
数字范围的Grep
提问于 2014-03-21 18:13:05
如何在日志文件中搜索日期范围？
日志文件如下所示：
01/14 00:00:01 INFO: received connect request from 10.10.10.10 我需要把日志压缩到10分钟，从8点25分开始，一直到8点35分。
当我使用下面的egrep时，我发现了太多的结果，例如00:08:25 01:08:25 . 08:25:00..。
我怎么才能让08:25:00通过08:35:59
我试过的
cat foo | egrep "08:2[5-9]|08:3[0-5]"
cat foo | egrep "08:2[5-9]:??|08:3[0-5]:??"
cat foo | egrep "08:2[5-9]:[0-9][0-9]|08:3[0-5]:[0-9][0-9]"回答 2
Unix & Linux用户
回答已采纳
发布于 2014-03-21 18:32:47
这将产生预期的结果。
egrep "08:[2][5-9]:[0-5][0-9]|08:[3][0-5]:[0-5][0-9]" foo在这种情况下不需要使用cat。
Unix & Linux用户
发布于 2014-03-21 18:44:47
有了这些投入：
01/15 00:00:01 INFO: received connect request from 10.10.10.10
01/14 00:00:01 INFO: received connect request from 10.10.10.10
01/14 08:25:01 INFO: received connect request from 10.10.10.10
01/14 00:00:01 INFO: received connect request from 10.10.10.10
01/14 00:00:01 INFO: received connect request from 10.10.10.10
01/14 08:35:01 INFO: received connect request from 10.10.10.10
01/14 00:00:01 INFO: received connect request from 10.10.10.10您可以使用awk打印两种模式之间的所有行：
awk -v date='01/14' '$1!=date{next};/08:25/,/08:35/' logfile
01/14 08:25:01 INFO: received connect request from 10.10.10.10
01/14 00:00:01 INFO: received connect request from 10.10.10.10
01/14 00:00:01 INFO: received connect request from 10.10.10.10
01/14 08:35:01 INFO: received connect request from 10.10.10.10页面原文内容由Unix & Linux提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://unix.stackexchange.com/questions/120831
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