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社区首页 >问答首页 >Google API快速入门

Google API快速入门
EN

Stack Overflow用户
提问于 2021-06-08 19:38:58
回答 1查看 241关注 0票数 1

我遇到了Google API快速入门的问题。我无法验证令牌,因为它显示令牌格式无效。最奇怪的是,几个月前我可以在另一个项目上运行它,但现在我什么也做不了。

我的quickstart.php看起来像:

代码语言:javascript
复制
<?php
require __DIR__ . '/vendor/autoload.php';

if (php_sapi_name() != 'cli') {
    throw new Exception('This application must be run on the command line.');
}

/**
 * Returns an authorized API client.
 * @return Google_Client the authorized client object
 */
function getClient()
{
    $client = new Google_Client();
    $client->setApplicationName('Google Sheets API');
    $client->setScopes(Google_Service_Sheets::SPREADSHEETS);
    $client->setAuthConfig('credentials.json');
    $client->setAccessType('offline');
    $client->setPrompt('select_account consent');

    // Load previously authorized token from a file, if it exists.
    // The file token.json stores the user's access and refresh tokens, and is
    // created automatically when the authorization flow completes for the first
    // time.
    $tokenPath = 'token.json';
    if (file_exists($tokenPath)) {
        $accessToken = json_decode(file_get_contents($tokenPath), true);
        $client->setAccessToken($accessToken);
    }

    // If there is no previous token or it's expired.
    if ($client->isAccessTokenExpired()) {
        // Refresh the token if possible, else fetch a new one.
        if ($client->getRefreshToken()) {
            $client->fetchAccessTokenWithRefreshToken($client->getRefreshToken());
        } else {
            // Request authorization from the user.
            $authUrl = $client->createAuthUrl();
            printf("Open the following link in your browser:\n%s\n", $authUrl);
            print 'Enter verification code: ';
            $authCode = trim(fgets(STDIN));

            // Exchange authorization code for an access token.
            $accessToken = $client->fetchAccessTokenWithAuthCode($authCode);
            $client->setAccessToken($accessToken);

            // Check to see if there was an error.
            if (array_key_exists('error', $accessToken)) {
                throw new Exception(join(', ', $accessToken));
            }
        }
        // Save the token to a file.
        if (!file_exists(dirname($tokenPath))) {
            mkdir(dirname($tokenPath), 0700, true);
        }
        file_put_contents($tokenPath, json_encode($client->getAccessToken()));
    }
    return $client;
}


// Get the API client and construct the service object.
$client = getClient();
$service = new Google_Service_Sheets($client);

// Prints the names and majors of students in a sample spreadsheet:
// https://docs.google.com/spreadsheets/d/1BxiMVs0XRA5nFMdKvBdBZjgmUUqptlbs74OgvE2upms/edit
$spreadsheetId = '1BxiMVs0XRA5nFMdKvBdBZjgmUUqptlbs74OgvE2upms';
$range = 'Class Data!A2:E';
$response = $service->spreadsheets_values->get($spreadsheetId, $range);
$values = $response->getValues();

if (empty($values)) {
    print "No data found.\n";
} else {
    print "Name, Major:\n";
    foreach ($values as $row) {
        // Print columns A and E, which correspond to indices 0 and 4.
        printf("%s, %s\n", $row[0], $row[4]);
    }
}

当我尝试输入令牌时,它返回以下错误

代码语言:javascript
复制
Fatal error: Uncaught InvalidArgumentException: Invalid token format in ..\vendor\google\apiclient\src\Google\Client.php:469
Stack trace:
#0 ..\quickstart.php(45): Google_Client->setAccessToken()
#1 ..\quickstart.php(63): getClient()
#2 {main}
  thrown in ..\vendor\google\apiclient\src\Google\Client.php on line 469

我曾尝试手动添加$authCode令牌,但不起作用。

EN

回答 1

Stack Overflow用户

发布于 2021-06-09 01:47:01

所以从字面上来说是我的错误,我们的前置引擎改变了链接“一点”,所以它无法被验证。当我切换到一个随机域并复制令牌时,一切都运行得很好。

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/67886187

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