blocks|key|4255434|text|说真的，除了在单个行上简单地使用s/old/new之外，不要尝试将sed用于任何其他事情。除此之外，对于相同的任务，awk解决方案总是比sed解决方案更清晰、更简单、更高效、更易于增强/维护，并且更易于移植。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4255435|这是建立在my+previous+awk+script之上的|offset|length|4255436|$+cat+tst.awk
BEGIN+{+badLineNrs[5];+badLineNrs[6]+}
{+rec[%2B%2BnumLines]+=+$0+}
/{content-end}/+{
++++for+(lineNr=1;+lineNr<=numLines;+lineNr%2B%2B)+{
++++++++if+(+!(lineNr+in+badLineNrs)+)+{
++++++++++++print+rec[lineNr]
++++++++}
++++}
++++delete+rec
++++numLines+=+0
}

$+awk+-f+tst.awk+file
{content-start}
first1
second1
third1
sixth1
{content-end}
{content-start}
first2
second2
third2
sixth2
{content-end}
{content-start}
first3
second3
third3
sixth3
{content-end}|code-block|syntax|javascript|4255437|或者，如果您喜欢简洁和隐蔽，这也会使用任何awk生成预期的输出，但它更难构建，也更难做一些事情，比如只打印或跳过特定的记录(比如在your+previous+question中)，所以除了可移植性之外，它并不比等效的sed解决方案好多少：|4255438|$+awk+'(NR-5)%258+&&+(NR-6)%258'+file
{content-start}
first1
second1
third1
sixth1
{content-end}
{content-start}
first2
second2
third2
sixth2
{content-end}
{content-start}
first3
second3
third3
sixth3
{content-end}|4255439|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/50668784/1745001|1|https://stackoverflow.com/q/50659831/1745001^0|0|5|M|0|0|0|1T|M|1|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@]|9|@$D|10|E|11|1|12]]|A|$]]|$1|F|3|G|5|H|7|13|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|14|8|@]|9|@$D|15|E|16|1|17]]|A|$]]|$1|M|3|N|5|H|7|18|8|@]|9|@]|A|$I|J]]|$1|O|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|W|$5|R|S|T|A|$U|X]]]]

Seriously, forget trying to use sed for anything other than simply s/old/new on individual lines. For anything else an awk solution will always be some combination of clearer, simpler, more efficient, easier to enhance/maintain, and more portable than a sed solution for the same task.

This just builds on <a href="https://stackoverflow.com/a/50668784/1745001">my previous awk script</a>:

<pre><code>$ cat tst.awk
BEGIN { badLineNrs[5]; badLineNrs[6] }
{ rec[++numLines] = $0 }
/{content-end}/ {
 for (lineNr=1; lineNr&lt;=numLines; lineNr++) {
 if ( !(lineNr in badLineNrs) ) {
 print rec[lineNr]
 }
 }
 delete rec
 numLines = 0
}

$ awk -f tst.awk file
{content-start}
first1
second1
third1
sixth1
{content-end}
{content-start}
first2
second2
third2
sixth2
{content-end}
{content-start}
first3
second3
third3
sixth3
{content-end}
</code></pre>

or if you like brief and cryptic this will also produce the expected output using any awk but it's harder to build on and do things like only print or skip specific records (like in <a href="https://stackoverflow.com/q/50659831/1745001">your previous question</a>) so other than portability it's not much better than an equivalent sed solution:

<pre><code>$ awk '(NR-5)%8 &amp;&amp; (NR-6)%8' file
{content-start}
first1
second1
third1
sixth1
{content-end}
{content-start}
first2
second2
third2
sixth2
{content-end}
{content-start}
first3
second3
third3
sixth3
{content-end}
</code></pre>

blocks|key|4255497|text|在这里，遵循awk可能也会有所帮助。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4255498|awk+'
/%5E{content-start}/{
++++flag=1;
++++print;
++++next}
flag{
++++count%2B%2B}
flag+&&+((count==4)+%7C%7C+(count==5)){
++++next}
flag;
/%5E{content-end}/{
++++flag=count=""}
'++Input_file|code-block|syntax|javascript|4255499|entityMap^0|6|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Following <code>awk</code> may help here too.

<pre><code>awk '
/^{content-start}/{
 flag=1;
 print;
 next}
flag{
 count++}
flag &amp;&amp; ((count==4) || (count==5)){
 next}
flag;
/^{content-end}/{
 flag=count=""}
' Input_file
</code></pre>

blocks|key|4255543|text|Sed用于脑力锻炼|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4255544|sed+-E+'N;N;N;N;N;N;N;s/(([%5E\n]*\n){4})([%5E\n]*\n){2}(.*)/\1\4/'+infile|code-block|syntax|javascript|4255545|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Sed for the mental exercice

<pre><code>sed -E 'N;N;N;N;N;N;N;s/(([^\n]*\n){4})([^\n]*\n){2}(.*)/\1\4/' infile
</code></pre>

blocks|key|4255985|text|这可能适用于您(GNU+sed)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4255986|sed+-n+'/start/,/end/{/start/{x;s/.*//;x};x;/%5Ex\{4,5\}$/!{x;p;x};s/%5E/x/;x;b};p'+file|code-block|syntax|javascript|4255987|通过设置选项-n关闭自动打印。关注start和end分隔符之间的行。如果当前行是start分隔符，则将计数器重置为空。打印除第五行和第六行以外的所有行，不要忘记累计计数器。打印所有其他行。|offset|length|style|CODE|4255988|entityMap^0|0|0|6|2|H|5|N|3|14|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|N|$]]

This might work for you (GNU sed):

<pre><code>sed -n '/start/,/end/{/start/{x;s/.*//;x};x;/^x\{4,5\}$/!{x;p;x};s/^/x/;x;b};p' file
</code></pre>

Turn off automatic printing by setting option <code>-n</code>. Focus on lines between <code>start</code> and <code>end</code> delimiters. Reset a counter to empty if the current line is the <code>start</code> delimiter. Print all lines except the fifth and sixth not forgetting to accumulate the counter. Print all other lines.

Remove only 4th and 5th values(fourth1 and fifth1 in 1st block, fourth2 and fifth2 in 2nd block, fourth3 and fifth3 in 3rd block ) in each block.

Tried this <code>sed -E -e :a -e 's/(.*) ( .*$)/\1 \4 \5/; ta'</code> and not working.

<pre><code>{content-start}
first1
second1
third1
fourth1
fifth1
sixth1
{content-end}
{content-start}
first2
second2
third2
fourth2
fifth2
sixth2
{content-end}
{content-start}
first3
second3
third3
fourth3
fifth3
sixth3
{content-end}
</code></pre>

Remove particular row values in all blocks using sed

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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在每个数据块中仅删除第4和第5个值(第一个数据块中的fourth1和fifth1，第二个数据块中的fourth2和fifth2，第三个数据块中的fourth3和fifth3 )。已尝试此sed -E -e :a -e 's/(.*) ( .*$)/\1 \4 \5/; ta'，但不起作用。{content-start}...

问使用sed删除所有块中的特定行值
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