我有一个来自服务器的JSON字符串,它看起来像这样:
{
"categories": {
"0": {
"term_id": "247",
"name": "Content Curation"
},
"1": {
"term_id": "50",
"name": "Content Marketing"
},
"2": {
"term_id": "2",
"name": "Curation"
},
"3": {
"term_id": "246",
"name": "Inbound Marketing"
},
"4": {
"term_id": "47",
"name": "Marketing"
},
"5": {
"term_id": "4",
"name": "News Curation"
},
"6": {
"term_id": "36",
"name": "SEO"
},
"8": {
"term_id": "248",
"name": "Wordpress Content Curation"
}
}
}
我的任务是获取"term_id“和"name”字段的值。我曾经使用以下代码从当前的JSONObject中获取"categories“对象:
JSONObject jObject = new JSONObject(responceData);
JSONObject categoryObject = jObject.getJSONObject("categories");
JSONArray jarray = new JSONArray("["+categoryObject.toString().substring(1,categoryObject.toString().length() - 1) + "]");
for(int i=0;i<jarray.length();i++)
{
JSONObject jobj = jarray.getJSONObject(i);
String term_id=jobj.getString("term_id");
String name=jobj.getString("name");
}
categoryObject
看起来像这样:
{
"0": {
"term_id": "247",
"name": "Content Curation"
},
"1": {
"term_id": "50",
"name": "Content Marketing"
},
"2": {
"term_id": "2",
"name": "Curation"
},
"3": {
"term_id": "246",
"name": "Inbound Marketing"
},
"4": {
"term_id": "47",
"name": "Marketing"
},
"5": {
"term_id": "4",
"name": "News Curation"
},
"6": {
"term_id": "36",
"name": "SEO"
},
"8": {
"term_id": "248",
"name": "Wordpress Content Curation"
}
}
但在那之后,我不知道如何获得这些字段。有没有办法从JSONObject中获取所有的JSONObject子代?
如果你有一个源代码或可以给我一个例子,请与我分享它。
发布于 2014-03-24 18:39:04
在这里您可以检索所有的json数据,请求一个特定的键和innerKey来获得您想要的,干杯
try
{
String jsonString="";//your json string here
JSONObject jObject= new JSONObject(jsonString).getJSONObject("categories");
Iterator<String> keys = jObject.keys();
while( keys.hasNext() )
{
String key = keys.next();
Log.v("**********", "**********");
Log.v("category key", key);
JSONObject innerJObject = jObject.getJSONObject(key);
Iterator<String> innerKeys = innerJObject.keys();
while( innerKeys.hasNext() )
{
String innerKkey = keys.next();
String value = innerJObject.getString(innerKkey);
Log.v("key = "+key, "value = "+value);
}
}
}
catch (JSONException e)
{ e.printStackTrace(); }
发布于 2014-03-24 18:30:05
检查this answer,这样您就不需要知道键,只需遍历和访问内部对象,但作为JSONArray比作为对象更好,这样您就可以正常地遍历
for(int i = 0; i < array.length(); i++) {
JSONObject obj = myArray.get(i);
....
}
发布于 2014-03-24 18:53:56
非常感谢艾哈迈德·德维克和汤姆·哈特的回答。这是解决方案的代码。
try
{
JSONObject jObject= new JSONObject(responseData).getJSONObject("categories");
Iterator<String> keys = jObject.keys();
while( keys.hasNext() )
{
String key = keys.next();
Log.v("**********", "**********");
Log.v("category key", key);
JSONObject innerJObject = jObject.getJSONObject(key);
String name = innerJObject.getString("name");
String term_id = innerJObject.getString("term_id");
Log.v("name = "+name, "term_id = "+term_id);
}
}
catch (JSONException e){
e.printStackTrace();
}
https://stackoverflow.com/questions/22606572
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