问如何使用JSON正确返回一个短语的函数？

EN

    let networksURL = "https://api.citybik.es/v2/networks/"
    guard let dataURL = URL(string: networksURL) else {return}

    URLSession.shared.dataTask(with: dataURL) { (data, response, err) in

        guard let data = data else {return}
        let dataAsString = String(data: data, encoding: .utf8)

    guard let blog = try? JSONDecoder().decode(Blog.self, from: data) else {
        print("Error: Couldn't decode data")
        return
    }

    print("Networks link:")
    for article in blog.articles {
        print("- \(article.href)")
    }

        func extractStationData() {
            for article in blog.articles {
                article.href
            }
        }

        let stationDataURL = "https://api.citybik.es\(extractStationData())"
        guard let newDataURL = URL(string: stationDataURL) else {return}

        URLSession.shared.dataTask(with: newDataURL) { (data, response, err) in

            guard let data = data else {return}
            let dataAsStringForStation = String(data: data, encoding: .utf8)

            guard let dataFromStation = try? JSONDecoder().decode(Datamain.self, from: data) else {
                print("Error: Couldn't decode station data")
                return
            }

            print("data:")
            for something in dataFromStation.qwerty {
                print("- \(something.empty_slots)")
                print("- \(something.free_bikes)")
                print("- \(something.name)")
                print("- \(something.latitude)")
                print("- \(something.longitude)")

            }

            }.resume()
}.resume()