blocks|key|718614|text|var+s+=+'/Controller/Action?id=11112&value=4444';
s+=+s.substring(0,+s.indexOf('?'));
document.write(s);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|718615|Sample+here|unstyled|offset|length|718616|我还应该提到，原生字符串函数比正则表达式快得多，正则表达式应该只在必要时使用(这不是其中的一种情况)。|718617|更新代码以说明没有'?'：|718618|var+s+=+'/Controller/Action';
var+n+=+s.indexOf('?');
s+=+s.substring(0,+n+!=+-1+?+n+:+s.length);
document.write(s);|718619|Sample+here|718620|entityMap|0|LINK|mutability|MUTABLE|url|http://jsfiddle.net/L4hna/|1|http://jsfiddle.net/L4hna/1/^0|0|0|B|0|0|0|0|0|0|B|1|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|11|8|@]|9|@$G|12|H|13|1|14]]|A|$]]|$1|I|3|J|5|F|7|15|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|16|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|17|8|@]|9|@]|A|$B|C]]|$1|O|3|P|5|F|7|18|8|@]|9|@$G|19|H|1A|1|1B]]|A|$]]|$1|Q|3|-4|5|F|7|1C|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]|Y|$5|T|U|V|A|$W|Z]]]]

<pre><code>var s = '/Controller/Action?id=11112&amp;value=4444';
s = s.substring(0, s.indexOf('?'));
document.write(s);
</code></pre>

<a href="http://jsfiddle.net/L4hna/" rel="noreferrer">Sample here</a>

I should also mention that native string functions are much faster than regular expressions, which should only really be used when necessary (this isn't one of those cases).

Updated code to account for no '?':

<pre><code>var s = '/Controller/Action';
var n = s.indexOf('?');
s = s.substring(0, n != -1 ? n : s.length);
document.write(s);
</code></pre>

<a href="http://jsfiddle.net/L4hna/1/" rel="noreferrer">Sample here</a>

blocks|key|718664|text|var+href+=+"/Controller/Action?id=11112&value=4444";
href+=+href.replace(/\?.*/,'');
href+;+//#+=>+/Controller/Action|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|718665|如果它找到一个'?‘，它就会工作。如果它不能|unstyled|718666|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>var href = "/Controller/Action?id=11112&amp;value=4444";
href = href.replace(/\?.*/,'');
href ; //# =&gt; /Controller/Action
</code></pre>

This will work if it finds a '?' and if it doesn't

blocks|key|934519|text|它可以很容易地完成使用JavaScript作为参考参见链接JS+String|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|934520|编辑它可以很容易地完成。;)|934521|var+url="/Controller/Action?id=11112&value=4444+";
var+parameter_Start_index=url.indexOf('?');
var+action_URL+=+url.substring(0,+parameter_Start_index);
alert('action_URL+:+'%2Baction_URL);|code-block|syntax|javascript|934522|entityMap|0|LINK|mutability|MUTABLE|url|http://www.pageresource.com/jscript/jstring1.htm^0|T|9|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

It can easly be done using JavaScript for reference see link
<a href="http://www.pageresource.com/jscript/jstring1.htm" rel="nofollow">JS String</a>

EDIT 
it can easly done as. ;)

<pre><code>var url="/Controller/Action?id=11112&amp;value=4444 ";
var parameter_Start_index=url.indexOf('?');
var action_URL = url.substring(0, parameter_Start_index);
alert('action_URL : '+action_URL);
</code></pre>

blocks|key|934561|text|您还可以使用split()函数。这似乎是我想到的最简单的一个:)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|934562|url.split('?')[0]|code-block|syntax|javascript|934563|jsFiddle+Demo|934564|一个优点是，即使字符串中没有?，此方法也可以工作-它将返回整个字符串。|934565|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split|1|http://jsfiddle.net/5LmLW/^0|6|7|6|7|0|0|0|0|D|1|0|E|1|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@$9|11|A|12|1|13]]|E|$]]|$1|F|3|G|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|15|8|@]|D|@$9|16|A|17|1|18]]|E|$]]|$1|M|3|N|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|O|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]]]

You can also use the <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split" rel="noreferrer"><code>split()</code></a> function. This seems to be the easiest one that comes to my mind :).

<pre><code>url.split('?')[0]
</code></pre>

<a href="http://jsfiddle.net/5LmLW/" rel="noreferrer">jsFiddle Demo</a>

One advantage is this method will work even if there is no <code>?</code> in the string - it will return the whole string.

blocks|key|934592|text|对我来说很有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|934593|++++++var+first+=+regexLabelOut.replace(/,.*/g,+"");|code-block|syntax|javascript|934594|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Worked for me:

<pre><code> var first = regexLabelOut.replace(/,.*/g, "");
</code></pre>

blocks|key|718974|text|它对我来说非常有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|718975|var+x+=+'/Controller/Action?id=11112&value=4444';
var+remove_after=+x.indexOf('?');
var+result+=++x.substring(0,+remove_after);
alert(result);|code-block|syntax|javascript|718976|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

It works for me very nicely:
<pre><code>var x = '/Controller/Action?id=11112&amp;value=4444';
var remove_after= x.indexOf('?');
var result = x.substring(0, remove_after);
alert(result);
</code></pre>

blocks|key|934655|text|您还可以使用split()方法，对我来说，这是实现此目标的最简单方法。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|934656|例如：|934657|​|934658|let+dummyString+="Hello+Javascript:+This+is+dummy+string"
dummyString+=+dummyString.split(':')[0]
console.log(dummyString)
//+Returns+"Hello+Javascript"|code-block|syntax|javascript|934659|来源：https://thispointer.com/javascript-remove-everything-after-a-certain-character/|934660|934661|entityMap|0|LINK|mutability|MUTABLE|url|https://thispointer.com/javascript-remove-everything-after-a-certain-character/^0|6|7|0|0|0|0|3|27|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|12|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|13|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|14|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|15|8|@]|D|@$9|16|A|17|1|18]]|E|$]]|$1|Q|3|I|5|6|7|19|8|@]|D|@]|E|$]]|$1|R|3|-4|5|6|7|1A|8|@]|D|@]|E|$]]]|S|$T|$5|U|V|W|E|$X|Y]]]]

You can also use the <code>split()</code> method which, to me, is the easiest method for achieving this goal.
For example:
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let dummyString ="Hello Javascript: This is dummy string"
dummyString = dummyString.split(':')[0]
console.log(dummyString)
// Returns "Hello Javascript"</code></pre>
</div>
</div>

Source: <a href="https://thispointer.com/javascript-remove-everything-after-a-certain-character/" rel="nofollow noreferrer">https://thispointer.com/javascript-remove-everything-after-a-certain-character/</a>

blocks|key|719034|text|如果你添加了一些json+syringified对象，那么你也需要修剪空间。所以我也添加了trim()。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|719035|let+x+=+"/Controller/Action?id=11112&value=4444";
let+result+=++x.trim().substring(0,++x.trim().indexOf('?'));++|code-block|syntax|javascript|719036|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

if you add some json syringified objects, then you need to trim the spaces too... so i add the trim() too.
<pre><code>let x = &quot;/Controller/Action?id=11112&amp;value=4444&quot;;
let result = x.trim().substring(0, x.trim().indexOf('?')); 
</code></pre>

Is there a way to remove everything after a certain character or just choose everything up to that character? I'm getting the value from an href and up to the "?", and it's always going to be a different amount of characters.

Like this

<pre><code>/Controller/Action?id=11112&amp;value=4444
</code></pre>

I want the href to be <code>/Controller/Action</code> only, so I want to remove everything after the "?".

I'm using this now:

<pre><code> $('.Delete').click(function (e) {
 e.preventDefault();

 var id = $(this).parents('tr:first').attr('id'); 
 var url = $(this).attr('href');

 console.log(url);
 }
</code></pre>

Remove everything after a certain character

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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有没有一种方法可以删除某个字符之后的所有内容，或者只选择该字符之前的所有内容？我从href中获取值，直到"?"，并且它总是会有不同数量的字符。像这样/Controller/Action?id=11112&value=4444我希望href仅为/Controller/Action，所以我想删除"?“后面的所有内容。我现在...

问删除某个字符后面的所有内容
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