我正在尝试过滤数据框中field_A为null或空字符串的记录,如下所示:
my_df[my_df.editions is not None]
my_df.shape这给了我一个错误:
---------------------------------------------------------------------------
KeyError Traceback (most recent call last)
<ipython-input-40-e1969e0af259> in <module>()
1 my_df['editions'] = my['editions'].astype(str)
----> 2 my_df = my_df[my_df.editions is not None]
3 my_df.shape
/home/edamame/anaconda2/lib/python2.7/site-packages/pandas/core/frame.pyc in __getitem__(self, key)
1995 return self._getitem_multilevel(key)
1996 else:
-> 1997 return self._getitem_column(key)
1998
1999 def _getitem_column(self, key):
/home/edamame/anaconda2/lib/python2.7/site-packages/pandas/core/frame.pyc in _getitem_column(self, key)
2002 # get column
2003 if self.columns.is_unique:
-> 2004 return self._get_item_cache(key)
2005
2006 # duplicate columns & possible reduce dimensionality
/home/edamame/anaconda2/lib/python2.7/site-packages/pandas/core/generic.pyc in _get_item_cache(self, item)
1348 res = cache.get(item)
1349 if res is None:
-> 1350 values = self._data.get(item)
1351 res = self._box_item_values(item, values)
1352 cache[item] = res
/home/edamame/anaconda2/lib/python2.7/site-packages/pandas/core/internals.pyc in get(self, item, fastpath)
3288
3289 if not isnull(item):
-> 3290 loc = self.items.get_loc(item)
3291 else:
3292 indexer = np.arange(len(self.items))[isnull(self.items)]
/home/edamame/anaconda2/lib/python2.7/site-packages/pandas/indexes/base.pyc in get_loc(self, key, method, tolerance)
1945 return self._engine.get_loc(key)
1946 except KeyError:
-> 1947 return self._engine.get_loc(self._maybe_cast_indexer(key))
1948
1949 indexer = self.get_indexer([key], method=method, tolerance=tolerance)
pandas/index.pyx in pandas.index.IndexEngine.get_loc (pandas/index.c:4154)()
pandas/index.pyx in pandas.index.IndexEngine.get_loc (pandas/index.c:4018)()
pandas/hashtable.pyx in pandas.hashtable.PyObjectHashTable.get_item (pandas/hashtable.c:12368)()
pandas/hashtable.pyx in pandas.hashtable.PyObjectHashTable.get_item (pandas/hashtable.c:12322)()
KeyError: True或者
my_df[my_df.editions != None]
my_df.shape这个没有给出错误,但没有过滤掉任何None值。
我也尝试过:
my_df = my_df[my_df.editions.notnull()]这个函数不会给出错误,但也不会过滤掉任何None值。
有人能建议一下如何解决这个问题吗?谢谢!
发布于 2016-09-14 01:45:14
您可以通过过滤创建新的数据帧吗?
之前的数据帧:
a b
1 9
2 10
3 11
4 12
5 13
6 14
7 15
8 null示例:
import pandas
my_df = pandas.DataFrame({"a":[1,2,3,4,5,6,7,8],"b":[9,10,11,12,13,14,15,"null"]})
my_df2= my_df[(my_df['b']!="null")]
print(my_df2)数据帧后:
a b
1 9
2 10
3 11
4 12
5 13
6 14
7 15它所做的就是查找"null“并将其排除。你可以用空字符串做同样的事情。
发布于 2019-09-06 19:02:33
您可以在使用~进行过滤时否定条件。
因此,在您的情况下,您应该这样做:
my_df = my_df[~my_df.editions.isnull()]发布于 2020-09-24 08:23:40
您可以像这样过滤掉数据帧中的空字符串:
df = df[df['str_field'].str.len() > 0]https://stackoverflow.com/questions/39475566
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