entityMap|blocks|key|dbr7c|text|只需将过滤数组的元素映射到它们的name属性：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|ejiho|​|355n8|const+animals+=+[
++{name:+'Fluffy',+species:+'cat'},
++{name:+'Crinkle',+species:+'rabbit'},
++{name:+'Wally',+species:+'dog'},
++{name:+'Roo',+species:+'dog'},
++{name:+'Felix',+species:+'cat'},
]

const+dogArray+=+animals.filter(animal+=>+animal.species+===+'dog');

console.log(dogArray.map(dog+=>+dog.name));|code-block|syntax|javascript|f9835|2vbrg|或者将这两个合并为一个reduce：|3f48n|a55of|const+animals+=+[
++{name:+'Fluffy',+species:+'cat'},
++{name:+'Crinkle',+species:+'rabbit'},
++{name:+'Wally',+species:+'dog'},
++{name:+'Roo',+species:+'dog'},
++{name:+'Felix',+species:+'cat'},
]

let+dogArray+=+animals.reduce((dogs,+animal)+=>+{
++if+(animal.species+===+"dog")+dogs.push(animal.name);
++return+dogs;
},+[]);

console.log(dogArray)|520l7|6ka9r^0|0|0|0|0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|R|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|S|9|@]|A|@]|B|$]]|$2|E|4|F|6|G|8|T|9|@]|A|@]|B|$H|I]]|$2|J|4|D|6|7|8|U|9|@]|A|@]|B|$]]|$2|K|4|L|6|7|8|V|9|@]|A|@]|B|$]]|$2|M|4|D|6|7|8|W|9|@]|A|@]|B|$]]|$2|N|4|O|6|G|8|X|9|@]|A|@]|B|$H|I]]|$2|P|4|D|6|7|8|Y|9|@]|A|@]|B|$]]|$2|Q|4|-4|6|7|8|Z|9|@]|A|@]|B|$]]]]

<p>Just map the elements of the filtered array to their name property:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const animals = [
  {name: 'Fluffy', species: 'cat'},
  {name: 'Crinkle', species: 'rabbit'},
  {name: 'Wally', species: 'dog'},
  {name: 'Roo', species: 'dog'},
  {name: 'Felix', species: 'cat'},
]

const dogArray = animals.filter(animal =&gt; animal.species === 'dog');

console.log(dogArray.map(dog =&gt; dog.name));</code></pre>
</div>
</div>
</p>

<p>Or combine the two into one reduce:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const animals = [
  {name: 'Fluffy', species: 'cat'},
  {name: 'Crinkle', species: 'rabbit'},
  {name: 'Wally', species: 'dog'},
  {name: 'Roo', species: 'dog'},
  {name: 'Felix', species: 'cat'},
]

let dogArray = animals.reduce((dogs, animal) =&gt; {
  if (animal.species === "dog") dogs.push(animal.name);
  return dogs;
}, []);

console.log(dogArray)</code></pre>
</div>
</div>
</p>


entityMap|blocks|key|4k13h|text|创建一个空数组，使用for循环遍历现有的dogArray，将名称推入新的数组，然后返回新的数组。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4g2s9|const+dogArray+=+animals.filter(function(animal)+{
++return+animal.species+===+'dog';
+})

let+dogNames+=+[];

for+(let+i+in+dogArray)+{
++dogNames.push(dogArray[i].name);
}

return+dogNames;|code-block|syntax|javascript|cj293^0|A|3|K|8|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|M|9|@$A|N|B|O|C|D]|$A|P|B|Q|C|D]]|E|@]|F|$]]|$2|G|4|H|6|I|8|R|9|@]|E|@]|F|$J|K]]|$2|L|4|-4|6|7|8|S|9|@]|E|@]|F|$]]]]

<p>Create an empty array, iterate over the existing <code>dogArray</code> using a <code>for</code> loop, push the names into the new array, and return the new array.</p>

<pre><code>const dogArray = animals.filter(function(animal) {
  return animal.species === 'dog';
 })

let dogNames = [];

for (let i in dogArray) {
  dogNames.push(dogArray[i].name);
}

return dogNames;
</code></pre>


entityMap|blocks|key|clomu|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|87vg4|const+animals+=+[
{name:+'Fluffy',+species:+'cat'},
{name:+'Crinkle',+species:+'rabbit'},
{name:+'Wally',+species:+'dog'},
{name:+'Roo',+species:+'dog'},
{name:+'Felix',+species:+'cat'},
]

var+result+=+animals.filter(val=>val.species=="dog").map(({name})=>name);

console.log(result);|code-block|syntax|javascript|9gpbc|c7s7f^0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|J|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|K|9|@]|A|@]|B|$F|G]]|$2|H|4|5|6|7|8|L|9|@]|A|@]|B|$]]|$2|I|4|-4|6|7|8|M|9|@]|A|@]|B|$]]]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const animals = [
{name: 'Fluffy', species: 'cat'},
{name: 'Crinkle', species: 'rabbit'},
{name: 'Wally', species: 'dog'},
{name: 'Roo', species: 'dog'},
{name: 'Felix', species: 'cat'},
]

var result = animals.filter(val=&gt;val.species=="dog").map(({name})=&gt;name);

console.log(result);</code></pre>
</div>
</div>
</p>


entityMap|0|type|LINK|mutability|MUTABLE|data|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Destructuring_assignment|blocks|key|fln6r|text|您可以使用destructuring映射该属性。|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|5hus2|​|1tvec|const
++++animals+=+[{+name:+'Fluffy',+species:+'cat'+},+{+name:+'Crinkle',+species:+'rabbit'+},+{+name:+'Wally',+species:+'dog'+},+{+name:+'Roo',+species:+'dog'+},+{+name:+'Felix',+species:+'cat'+}]
++++dogArray+=+animals
++++++++.filter(({+species+})+=>+species+===+'dog')
++++++++.map(({+name+})+=>+name);

console.log(dogArray);|code-block|syntax|javascript|55qdh|bb5pj^0|5|D|0|0|0|0|0^^$0|$1|$2|3|4|5|6|$7|8]]]|9|@$A|B|C|D|2|E|F|T|G|@]|H|@$I|U|J|V|A|W]]|6|$]]|$A|K|C|L|2|E|F|X|G|@]|H|@]|6|$]]|$A|M|C|N|2|O|F|Y|G|@]|H|@]|6|$P|Q]]|$A|R|C|L|2|E|F|Z|G|@]|H|@]|6|$]]|$A|S|C|-4|2|E|F|10|G|@]|H|@]|6|$]]]]

<p>You could map the property with a <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Destructuring_assignment" rel="nofollow noreferrer">destructuring</a>.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const
    animals = [{ name: 'Fluffy', species: 'cat' }, { name: 'Crinkle', species: 'rabbit' }, { name: 'Wally', species: 'dog' }, { name: 'Roo', species: 'dog' }, { name: 'Felix', species: 'cat' }]
    dogArray = animals
        .filter(({ species }) =&gt; species === 'dog')
        .map(({ name }) =&gt; name);

console.log(dogArray);</code></pre>
</div>
</div>
</p>


entityMap|blocks|key|4d78u|text|您可以先使用.filter()，然后使用.map()|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|9lsbj|​|1liii|const+animals+=+[
++{name:+'Fluffy',+species:+'cat'},
++{name:+'Crinkle',+species:+'rabbit'},
++{name:+'Wally',+species:+'dog'},
++{name:+'Roo',+species:+'dog'},
++{name:+'Felix',+species:+'cat'},
];

const+dogNames+=+animals
++.filter(animal+=>+animal.species+===+'dog')
++.map(dog+=>+dog.name);

console.log(dogNames);|code-block|syntax|javascript|avu4d|3i8s4^0|6|9|K|6|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|P|9|@$A|Q|B|R|C|D]|$A|S|B|T|C|D]]|E|@]|F|$]]|$2|G|4|H|6|7|8|U|9|@]|E|@]|F|$]]|$2|I|4|J|6|K|8|V|9|@]|E|@]|F|$L|M]]|$2|N|4|H|6|7|8|W|9|@]|E|@]|F|$]]|$2|O|4|-4|6|7|8|X|9|@]|E|@]|F|$]]]]

<p>You can use <code>.filter()</code> followed by <code>.map()</code>:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const animals = [
  {name: 'Fluffy', species: 'cat'},
  {name: 'Crinkle', species: 'rabbit'},
  {name: 'Wally', species: 'dog'},
  {name: 'Roo', species: 'dog'},
  {name: 'Felix', species: 'cat'},
];

const dogNames = animals
  .filter(animal =&gt; animal.species === 'dog')
  .map(dog =&gt; dog.name);

console.log(dogNames);</code></pre>
</div>
</div>
</p>


<p>I have an object:</p>

<pre><code>const animals = [
    {name: 'Fluffy', species: 'cat'},
    {name: 'Crinkle', species: 'rabbit'},
    {name: 'Wally', species: 'dog'},
    {name: 'Roo', species: 'dog'},
    {name: 'Felix', species: 'cat'},
]
</code></pre>

<p>I want to use a higher order function such as the filter() method to take the array of animal objects and return an array with just the names of all the dogs i.e. <code>["Wally", "Roo"]</code>. My code at the moment returns an array containing the entire object with the species dog in it. See below:</p>

<pre><code>const dogArray = animals.filter(function(animal) {
  return animal.species === 'dog';
 })

return dogArray;

// returns
// [{name: "Wally", species: "dog"}, 
// { name: "Roo", species: "dog"}]
</code></pre>


Using a higher order function, return one object value if another value is true (JavaScript)

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

 我有一个对象： const animals = [    {name: 'Fluffy', species: 'cat'},    {name: 'Crinkle', species: 'rabbit'},    {name: 'Wally', species: 'dog'},    {name: 'Roo', sp...

问使用高阶函数，如果一个对象值为真，则返回另一个对象值(JavaScript)
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问使用高阶函数，如果一个对象值为真，则返回另一个对象值(JavaScript)EN