entityMap|0|type|LINK|mutability|MUTABLE|data|url|https://stackoverflow.com/questions/11447780/convert-two-dimensional-array-to-list-in-java|blocks|key|dsrtt|text|从二维数组到列表|unstyled|depth|inlineStyleRanges|entityRanges|cqh1q|double[,]+d+=+new+double[,]
{
++++{1.0,+2.0},
++++{3.0,+4.0},
++++{5.0,+6.0},
++++{7.0,+8.0},
++++{9.0,+10.0}
};
List<double>+lst+=+d.Cast<double>().ToList()|code-block|syntax|javascript|109um|从二维数组到二维列表|2hq1v|2D+array+to+2D+List|offset|length|7dabr^0|0|0|0|0|J|0|0^^$0|$1|$2|3|4|5|6|$7|8]]]|9|@$A|B|C|D|2|E|F|U|G|@]|H|@]|6|$]]|$A|I|C|J|2|K|F|V|G|@]|H|@]|6|$L|M]]|$A|N|C|O|2|E|F|W|G|@]|H|@]|6|$]]|$A|P|C|Q|2|E|F|X|G|@]|H|@$R|Y|S|Z|A|10]]|6|$]]|$A|T|C|-4|2|E|F|11|G|@]|H|@]|6|$]]]]

From 2D array to list

<pre><code>double[,] d = new double[,]
{
 {1.0, 2.0},
 {3.0, 4.0},
 {5.0, 6.0},
 {7.0, 8.0},
 {9.0, 10.0}
};
List&lt;double&gt; lst = d.Cast&lt;double&gt;().ToList()
</code></pre>

From 2D array to 2D List

<a href="https://stackoverflow.com/questions/11447780/convert-two-dimensional-array-to-list-in-java">2D array to 2D List</a>

entityMap|0|type|LINK|mutability|MUTABLE|data|url|https://dotnetfiddle.net/kexfMH|blocks|key|7j89p|text|使用Linq可以做到这一点。|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|a3rhv|var+result+list.Cast<string>()+
++++++++++++.Select((x,i)=>+new+{x,+index+=+i/list.GetLength(1)})++//+Use+overloaded+'Select'+and+calculate+row+index.
++++++++++++.GroupBy(x=>x.index)+++++++++++++++++++++++++++++++++++//+Group+on+Row+index
++++++++++++.Select(x=>x.Select(s=>s.x).ToList())++++++++++++++++++//+Create+List+for+each+group.++
++++++++++++.ToList();|code-block|syntax|javascript|8cute|检查此example|2qhlb^0|2|4|0|0|3|7|3|7|0|0^^$0|$1|$2|3|4|5|6|$7|8]]]|9|@$A|B|C|D|2|E|F|U|G|@$H|V|I|W|J|K]]|L|@]|6|$]]|$A|M|C|N|2|O|F|X|G|@]|L|@]|6|$P|Q]]|$A|R|C|S|2|E|F|Y|G|@$H|Z|I|10|J|K]]|L|@$H|11|I|12|A|13]]|6|$]]|$A|T|C|-4|2|E|F|14|G|@]|L|@]|6|$]]]]

Using <code>Linq</code> you could do this.

<pre><code>var result list.Cast&lt;string&gt;() 
 .Select((x,i)=&gt; new {x, index = i/list.GetLength(1)}) // Use overloaded 'Select' and calculate row index.
 .GroupBy(x=&gt;x.index) // Group on Row index
 .Select(x=&gt;x.Select(s=&gt;s.x).ToList()) // Create List for each group. 
 .ToList();
</code></pre>

check this <a href="https://dotnetfiddle.net/kexfMH" rel="noreferrer"><code>example</code></a>

entityMap|blocks|key|cbjq0|text|要生成所需的列表，可以使用以下方式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|co9k0|++public+static+List<List<string>>+GenerateListOfListOfStrings(string[,]+result)
++++{

++++++++string[,]+res+=+result;
++++++++List<List<string>>+listObj+=+new+List<List<string>>();
++++++++var+list+=+new+List<string>();
++++++++foreach+(var+s+in+result)
++++++++{
+++++++++++list.Add(s);
++++++++}
++++++++listObj.Add(list);
++++++++return+listObj;
++++}|code-block|syntax|javascript|8466d^0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|I|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|J|9|@]|A|@]|B|$F|G]]|$2|H|4|-4|6|7|8|K|9|@]|A|@]|B|$]]]]

to generate the required list, can use this way:

<pre><code> public static List&lt;List&lt;string&gt;&gt; GenerateListOfListOfStrings(string[,] result)
 {

 string[,] res = result;
 List&lt;List&lt;string&gt;&gt; listObj = new List&lt;List&lt;string&gt;&gt;();
 var list = new List&lt;string&gt;();
 foreach (var s in result)
 {
 list.Add(s);
 }
 listObj.Add(list);
 return listObj;
 }
</code></pre>

entityMap|blocks|key|e8bgd|text|嗯，你可以用定制的泛型ToList()方法来扩展2d数组：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|bso9f|public+static+class+ArrayHelper+
{
++++public+static+List<List<T>>+ToList<T>(this+T[,]+array)
++++{
++++++++var+result+=+new+List<List<T>>();
++++++++var+lengthX+=+array.GetLength(0);
++++++++var+lengthY+=+array.GetLength(1);

++++++++//+the+reason+why+we+get+lengths+of+dimensions+before+looping+through
++++++++//+is+because+we+would+like+to+use+`List<T>(int+length)`+overload
++++++++//+this+will+prevent+constant+resizing+of+its+underlying+array+and+improve+performance
++++++++for(int+i+=+0;+i+<+lengthX++i%2B%2B)++++++++++++
++++++++{
++++++++++++var+listToAdd+=+new+List<T>(lengthY);

++++++++++++for(int+i2+=+0;+i2+<+lengthY;+i2%2B%2B)
++++++++++++{
++++++++++++++++listToAdd.Add(array[i,+i2]);
++++++++++++}

++++++++++++result.Add(listToAdd);
++++++++}+++++++

++++++++return+result;
++++}+++++++
}|code-block|syntax|javascript|d57rg|只需一行代码就可以相当简单地使用它：|dckjr|public+class+Program
{+++
++++public+static+void+Main()
++++{
++++++++int[,]+array+=+new+int[2,2]+{{5,7},{9,14}};

++++++++var+result+=+array.ToList();++++++++
++++}
}|c42k9^0|B|8|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|Q|9|@$A|R|B|S|C|D]]|E|@]|F|$]]|$2|G|4|H|6|I|8|T|9|@]|E|@]|F|$J|K]]|$2|L|4|M|6|7|8|U|9|@]|E|@]|F|$]]|$2|N|4|O|6|I|8|V|9|@]|E|@]|F|$J|K]]|$2|P|4|-4|6|7|8|W|9|@]|E|@]|F|$]]]]

Well, you could extend 2d array with custom generic <code>ToList()</code> method :

<pre><code>public static class ArrayHelper 
{
 public static List&lt;List&lt;T&gt;&gt; ToList&lt;T&gt;(this T[,] array)
 {
 var result = new List&lt;List&lt;T&gt;&gt;();
 var lengthX = array.GetLength(0);
 var lengthY = array.GetLength(1);

 // the reason why we get lengths of dimensions before looping through
 // is because we would like to use `List&lt;T&gt;(int length)` overload
 // this will prevent constant resizing of its underlying array and improve performance
 for(int i = 0; i &lt; lengthX i++) 
 {
 var listToAdd = new List&lt;T&gt;(lengthY);

 for(int i2 = 0; i2 &lt; lengthY; i2++)
 {
 listToAdd.Add(array[i, i2]);
 }

 result.Add(listToAdd);
 } 

 return result;
 } 
}
</code></pre>

And use it fairly simple with just one line of code :

<pre><code>public class Program
{ 
 public static void Main()
 {
 int[,] array = new int[2,2] {{5,7},{9,14}};

 var result = array.ToList(); 
 }
}
</code></pre>

entityMap|blocks|key|2658n|text|另一种方法是使用LINQ等效于嵌套的for循环：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|7hjch|string[,]+array+=+{+{+"00",+"01",+"02"},+{+"10",+"11",+"12"+}+};

var+list+=+Enumerable.Range(0,+array.GetLength(0))
++++.Select(row+=>+Enumerable.Range(0,+array.GetLength(1))
++++.Select(col+=>+array[row,+col]).ToList()).ToList();|code-block|syntax|javascript|fgipg^0|I|3|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|M|9|@$A|N|B|O|C|D]]|E|@]|F|$]]|$2|G|4|H|6|I|8|P|9|@]|E|@]|F|$J|K]]|$2|L|4|-4|6|7|8|Q|9|@]|E|@]|F|$]]]]

Another way is to use the LINQ equivalent of a nested <code>for</code> loops:

<pre><code>string[,] array = { { "00", "01", "02"}, { "10", "11", "12" } };

var list = Enumerable.Range(0, array.GetLength(0))
 .Select(row =&gt; Enumerable.Range(0, array.GetLength(1))
 .Select(col =&gt; array[row, col]).ToList()).ToList();
</code></pre>

entityMap|0|type|LINK|mutability|MUTABLE|data|url|https://msdn.microsoft.com/en-us/library/bb397926.aspx|1|https://msdn.microsoft.com/en-GB/library/2s05feca.aspx|blocks|key|aburs|text|我更喜欢Hari的回答，但是如果由于某些原因你无法访问Linq+(.NET框架<+3.5)|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|fpjfi|List<List<string>>+lLString+=+new+List<List<string>>();
string[,]+stringArray2D+=+new+string[3,+3]+{
++++{+"a",+"b",+"c"+},+
++++{+"d",+"e",+"f"+},+
++++{+"g",+"h",+"i"+},+
};
for+(int+i+=+0;+i+<+stringArray2D.GetLength(0);+i%2B%2B)+{
++++List<string>+temp+=+new+List<string>();
++++for+(int+j+=+0;+j+<+stringArray2D.GetLength(1);+j%2B%2B)+{+
++++++++temp.Add(stringArray2D[i,j]);
++++}
++++lLString.Add(temp);
}|code-block|syntax|javascript|34qts|第一个循环遍历行，下一个循环遍历列。所有列(strings)都添加到单个List<string>对象中，然后在退出内部循环时添加到父List<List<string>>对象中。|style|CODE|5vulf|我已经包含了这些，以防你所说的2D数组实际上是指jagged+array+(非矩形)。由于这是一个数组数组，您可以简单地通过索引访问内部数组，然后对其调用.ToList()。|a1el7|List<List<string>>+lLString+=+new+List<List<string>>();
string[][]+jaggedStringArray+=+new+string[3][];
jaggedStringArray[0]+=+new+string[]+{+"a",+"b",+"c"+};
jaggedStringArray[1]+=+new+string[]+{+"d",+"e",+"f",+"g",+"h"+};
jaggedStringArray[2]+=+new+string[]+{+"i"+};
for+(int+i+=+0;+i+<+jaggedStringArray.Length;+i%2B%2B)+{
++++lLString.Add(jaggedStringArray[i].ToList());
}|cpqov|如果您使用的是交错数组，并且使用的是LinqFrameworkLinq3.5，则可以将其与>=结合使用，如下所示|4fs22|List<List<string>>+lLString+=+jaggedStringArray.Select(x+=>+x.ToList()).ToList();|3p35f^0|R|4|0|0|0|M|7|10|C|1U|I|0|25|9|O|C|1|0|0|0|0^^$0|$1|$2|3|4|5|6|$7|8]]|9|$2|3|4|5|6|$7|A]]]|B|@$C|D|E|F|2|G|H|14|I|@]|J|@$K|15|L|16|C|17]]|6|$]]|$C|M|E|N|2|O|H|18|I|@]|J|@]|6|$P|Q]]|$C|R|E|S|2|G|H|19|I|@$K|1A|L|1B|T|U]|$K|1C|L|1D|T|U]|$K|1E|L|1F|T|U]]|J|@]|6|$]]|$C|V|E|W|2|G|H|1G|I|@$K|1H|L|1I|T|U]]|J|@$K|1J|L|1K|C|1L]]|6|$]]|$C|X|E|Y|2|O|H|1M|I|@]|J|@]|6|$P|Q]]|$C|Z|E|10|2|G|H|1N|I|@]|J|@]|6|$]]|$C|11|E|12|2|O|H|1O|I|@]|J|@]|6|$P|Q]]|$C|13|E|-4|2|G|H|1P|I|@]|J|@]|6|$]]]]

I prefer Hari's answer, but if for some reason you have no access to <a href="https://msdn.microsoft.com/en-us/library/bb397926.aspx" rel="nofollow">Linq</a> (.NET Framework &lt; 3.5)

<pre><code>List&lt;List&lt;string&gt;&gt; lLString = new List&lt;List&lt;string&gt;&gt;();
string[,] stringArray2D = new string[3, 3] {
 { "a", "b", "c" }, 
 { "d", "e", "f" }, 
 { "g", "h", "i" }, 
};
for (int i = 0; i &lt; stringArray2D.GetLength(0); i++) {
 List&lt;string&gt; temp = new List&lt;string&gt;();
 for (int j = 0; j &lt; stringArray2D.GetLength(1); j++) { 
 temp.Add(stringArray2D[i,j]);
 }
 lLString.Add(temp);
}
</code></pre>

The first loop iterates over rows, the next over columns. All columns (<code>strings</code>) are added to a single <code>List&lt;string&gt;</code> object which is then added to the parent <code>List&lt;List&lt;string&gt;&gt;</code> object upon exiting the inner loop.

I've included these on the off chance that by 2D array you actually mean a <a href="https://msdn.microsoft.com/en-GB/library/2s05feca.aspx" rel="nofollow">jagged array</a> (non-rectangular). As this is an array of arrays you can simply access an inner array by its index and then call <code>.ToList()</code> on it.

<pre><code>List&lt;List&lt;string&gt;&gt; lLString = new List&lt;List&lt;string&gt;&gt;();
string[][] jaggedStringArray = new string[3][];
jaggedStringArray[0] = new string[] { "a", "b", "c" };
jaggedStringArray[1] = new string[] { "d", "e", "f", "g", "h" };
jaggedStringArray[2] = new string[] { "i" };
for (int i = 0; i &lt; jaggedStringArray.Length; i++) {
 lLString.Add(jaggedStringArray[i].ToList());
}
</code></pre>

If you're using a jagged array and do have .NET Framework >= 3.5, you can combine it with Linq like so

<pre><code>List&lt;List&lt;string&gt;&gt; lLString = jaggedStringArray.Select(x =&gt; x.ToList()).ToList();
</code></pre>

entityMap|blocks|key|a3j53|text|使用扩展。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|bcaa6|++++public+static+List<List<T>>+Convert2dToList<T>(this+T[][]+array)
++++{
++++++++if+(array+==+null)+return+null;
++++++++List<List<T>>+mainList+=+new+List<List<T>>();
++++++++for+(int+i+=+0;+i+<+array.Length;+i%2B%2B)
++++++++{
++++++++++++List<T>+list+=+array[i].ToList();
++++++++++++mainList.Add(list);
++++++++}
++++++++return+mainList;
++++}|code-block|syntax|javascript|8h0u6|然后像这样打电话|avmaa|++++static+void+Main(string[]+args)
++++{
++++++++int[][]+list+=+new+int[3][]
++++++++{
++++++++++++new+int[]{+-2,-3,3+},+
++++++++++++new+int[]{+-5,-10,1+},
++++++++++++new+int[]{+10,30,-5+}
++++++++};

++++++++List<List<int>>+A+=+list.Convert2dToList();
++++}|9qf34^0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|M|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|N|9|@]|A|@]|B|$F|G]]|$2|H|4|I|6|7|8|O|9|@]|A|@]|B|$]]|$2|J|4|K|6|E|8|P|9|@]|A|@]|B|$F|G]]|$2|L|4|-4|6|7|8|Q|9|@]|A|@]|B|$]]]]

Use extensions.

<pre><code> public static List&lt;List&lt;T&gt;&gt; Convert2dToList&lt;T&gt;(this T[][] array)
 {
 if (array == null) return null;
 List&lt;List&lt;T&gt;&gt; mainList = new List&lt;List&lt;T&gt;&gt;();
 for (int i = 0; i &lt; array.Length; i++)
 {
 List&lt;T&gt; list = array[i].ToList();
 mainList.Add(list);
 }
 return mainList;
 }
</code></pre>

Then call like this

<pre><code> static void Main(string[] args)
 {
 int[][] list = new int[3][]
 {
 new int[]{ -2,-3,3 }, 
 new int[]{ -5,-10,1 },
 new int[]{ 10,30,-5 }
 };

 List&lt;List&lt;int&gt;&gt; A = list.Convert2dToList();
 }
</code></pre>

I have a 2D string array. I want to convert this into

<pre><code>List&lt;List&lt;string&gt;&gt;
</code></pre>

How do I achieve this in C#?

How to convert a 2D array to a 2D list in C#

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个2D字符串数组。我想把这个转换成 List<List<string>> 如何在C#中实现这一点？

问如何在C#中将二维数组转换为二维列表
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问如何在C#中将二维数组转换为二维列表EN