检测在Tkinter Python中单击的按钮
检测在Tkinter Python中单击的按钮
提问于 2021-08-13 07:46:43
我有这个下拉菜单，我想知道点击了哪个按钮：
btnMenu = Menubutton(f4, text='Select your iPhone:')
contentMenu = Menu(btnMenu)
btnMenu.config(menu=contentMenu)
btnMenu.pack()
btnList = ["iPhone 6", "iPhone 6 Plus","iPhone 6S","iPhone 6S Plus", "iPhone 7", "iPhone 7 Plus","iPhone 8","iPhone 8 Plus","iPhone X"]例如：
if "iPhone 6" was clicked:
Do something
if "iPhone 7" was clicked:
Do something我该怎么做呢？谢谢
回答 1
Stack Overflow用户
发布于 2021-08-13 08:00:24
尝尝这个。在print_函数中使用if...else
from tkinter import *
root = Tk()
root.geometry("300x200")
menubutton = Menubutton(root, text = "Menu")
menu = Menu(menubutton)
menubutton["menu"]=menu
def print_(number):
print(f"Hey! {number} was clicked!")
btnList = ["iPhone 6", "iPhone 6 Plus","iPhone 6S","iPhone 6S Plus", "iPhone 7", "iPhone 7 Plus","iPhone 8","iPhone 8 Plus","iPhone X"]
for i in btnList:
menu.add_command(label=i,command=lambda i=i: print_(i))
menubutton.pack()
root.mainloop()页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/68768583
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