blocks|key|242402|text|直接从the+docs|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|242403|242404|+-fpermissive|blockquote|style|CODE|242405|242406|将一些关于不符合规范的代码的诊断从错误降级为警告。因此，使用-fpermissive将允许编译一些不符合规范的代码。|242407|242408|底线:除非你知道你在做什么，否则不要使用+it！|242409|entityMap|0|LINK|mutability|MUTABLE|url|http://gcc.gnu.org/onlinedocs/gcc-4.0.4/gcc/C_002b_002b-Dialect-Options.html#index-fpermissive-140^0|3|8|0|0|0|1|C|0|0|U|C|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@$A|Y|B|Z|1|10]]|C|$]]|$1|D|3|-4|5|6|7|11|8|@]|9|@]|C|$]]|$1|E|3|F|5|G|7|12|8|@$A|13|B|14|H|I]]|9|@]|C|$]]|$1|J|3|-4|5|6|7|15|8|@]|9|@]|C|$]]|$1|K|3|L|5|6|7|16|8|@$A|17|B|18|H|I]]|9|@]|C|$]]|$1|M|3|-4|5|6|7|19|8|@]|9|@]|C|$]]|$1|N|3|O|5|6|7|1A|8|@]|9|@]|C|$]]|$1|P|3|-4|5|6|7|1B|8|@]|9|@]|C|$]]]|Q|$R|$5|S|T|U|C|$V|W]]]]

Right from <a href="http://gcc.gnu.org/onlinedocs/gcc-4.0.4/gcc/C_002b_002b-Dialect-Options.html#index-fpermissive-140">the docs</a>:

<blockquote>
 <code>-fpermissive</code> 
 Downgrade some diagnostics about nonconformant code from errors to warnings. 
 Thus, using <code>-fpermissive</code> will allow some nonconforming code to compile.
</blockquote>

Bottom line: don't use it unless you know what you are doing!

blocks|key|2913875|text|-fpermissive+flag使编译器报告一些实际上是错误的东西(但某些编译器允许)作为警告，以允许代码编译，即使它不符合语言规则。你真的应该解决根本的问题。发布演示该问题的最小的可编译代码示例。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2913876|2913877|+-fpermissive|blockquote|2913878|2913879|将一些关于不符合规范的代码的诊断从错误降级为警告。因此，使用-fpermissive将允许编译一些不符合要求的代码。|2913880|entityMap|0|LINK|mutability|MUTABLE|url|http://gcc.gnu.org/onlinedocs/gcc-4.0.4/gcc/C_002b_002b-Dialect-Options.html#index-fpermissive-140^0|0|C|0|H|0|0|0|1|C|0|0|U|C|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|-4|5|6|7|10|8|@]|D|@]|E|$]]|$1|G|3|H|5|I|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|J|3|-4|5|6|7|14|8|@]|D|@]|E|$]]|$1|K|3|L|5|6|7|15|8|@$9|16|A|17|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

The <a href="http://gcc.gnu.org/onlinedocs/gcc-4.0.4/gcc/C_002b_002b-Dialect-Options.html#index-fpermissive-140" rel="noreferrer"><code>-fpermissive</code> flag</a> causes the compiler to report some things that are actually errors (but are permitted by some compilers) as warnings, to permit code to compile even if it doesn't conform to the language rules. You really should fix the underlying problem. Post the smallest, compilable code sample that demonstrates the problem.

<blockquote>
 <code>-fpermissive</code> 
 Downgrade some diagnostics about nonconformant code from errors to warnings. 
 Thus, using <code>-fpermissive</code> will allow some nonconforming code to compile.
</blockquote>

blocks|key|242427|text|当你写了一些语言标准不允许的东西(因此不可能是真正定义良好的行为，这是不能这样做的充分理由)，但是如果天真地提供给编译引擎，恰好映射到某种可执行文件，那么-fpermissive就会这样做，而不是停止这个错误消息。在某些情况下，程序将完全按照您最初的预期运行，但您绝对不应该依赖它，除非您有一些非常特殊的原因而不使用其他解决方案。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|242428|entityMap^0|25|C|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

When you've written something that isn't allowed by the language standard (and therefore can't really be well-defined behaviour, which is reason enough to not do it) but happens to map to some kind of executable if fed naïvely to the compiling engine, then <code>-fpermissive</code> will do just that instead of stopping with this error message. In some cases, the program will then behave exactly as you originally intended, but you definitely shouldn't rely on it unless you have some very special reason not to use some other solution.

blocks|key|3128226|text|如果您想要这方面的实际用例，可以尝试编译一个非常旧的X+Window版本--比如说，2004年前后的XFree86或XOrg+--使用“现代”(咳嗽)版本的gcc，比如4.9.3。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3128227|您会注意到，build+CFLAGS同时指定了"-ansi“和"-pedantic”。从理论上讲，这意味着“如果有任何东西稍微违反了语言规范，就会爆炸”。在实践中，gcc的3.x系列并没有捕获太多这类东西，并且使用4.9.3构建它将在地面上留下一个冒烟洞，除非您将CFLAGS和BOOTSTRAPCFLAGS设置为"-fpermissive“。|3128228|使用该标志，大多数C文件将实际构建，让您可以自由地转移到lexer将生成的依赖于版本的残骸。=]|3128229|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

If you want a real-world use case for this, try compiling a very old version of X Windows-- say, either XFree86 or XOrg from aboout 2004, right around the split-- using a "modern" (cough) version of gcc, such as 4.9.3.

You'll notice the build CFLAGS specify both "-ansi" and "-pedantic". In theory, this means, "blow up if anything even slightly violates the language spec". In practice, the 3.x series of gcc didn't catch very much of that kind of stuff, and building it with 4.9.3 will leave a smoking hole in the ground unless you set CFLAGS and BOOTSTRAPCFLAGS to "-fpermissive".

Using that flag, most of those C files will actually build, leaving you free to move on to the version-dependent wreckage the lexer will generate. =]

blocks|key|242466|text|简单地设置-fpermissive而不让它紧张的常见情况是:经过全面测试和工作的第三方库在没有-fpermissive的情况下无法在较新的编译器版本上编译。这些库是存在的，并且很可能不是应用程序开发人员要解决的问题，也不是开发人员要解决的问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|242467|在这种情况下，设置-fpermissive并继续。|242468|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

A common case for simply setting -fpermissive and not sweating it exists: the thoroughly-tested and working third-party library that won't compile on newer compiler versions without -fpermissive. These libraries exist, and are very likely not the application developer's problem to solve, nor in the developer's schedule budget to do it.
Set -fpermissive and move on in that case.

I'm just wondering what the <code>-fpermissive</code> flag does in the g++ compiler? I am getting:

<blockquote>
 error: taking address of temporary [-fpermissive]
</blockquote>

which I can solve by giving the <code>-fpermissive</code> flag to the compiler. 

EDIT:
I just found what was causing the temporary address error part! I'm going to fix that part right now.

What does the fpermissive flag do?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想知道g++编译器中的-fpermissive标志是做什么的？我得到了：错误:获取临时-fpermissive的地址我可以通过给编译器设置-fpermissive标志来解决这个问题。编辑：我刚刚找到了是什么导致了临时地址错误部分！我现在就把那部分修好。

问fpermissive标志的作用是什么？
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