查找列表中最接近的数字

def find_closest_number(target, num_list):
    min_diff = float('inf')  # 初始化最小差值为正无穷大
    closest_num = None  # 初始化最接近的数字为None

    for num in num_list:
        diff = abs(num - target)  # 计算差值的绝对值
        if diff < min_diff:
            min_diff = diff
            closest_num = num

    return closest_num

# 示例用法
target_num = 7
numbers = [1, 4, 6, 8, 10]
closest_number = find_closest_number(target_num, numbers)
print("最接近的数字是:", closest_number)