查询字典以获取前3个最常见的元素

def get_top3_elements(dictionary):
    # 统计元素出现次数
    count_dict = {}
    for key in dictionary:
        if dictionary[key] in count_dict:
            count_dict[dictionary[key]] += 1
        else:
            count_dict[dictionary[key]] = 1
    
    # 按照元素出现次数进行排序
    sorted_dict = sorted(count_dict.items(), key=lambda x: x[1], reverse=True)
    
    # 获取前3个元素
    top3_elements = []
    for i in range(min(3, len(sorted_dict))):
        top3_elements.append(sorted_dict[i][0])
    
    return top3_elements

# 示例字典
dictionary = {'a': 1, 'b': 2, 'c': 1, 'd': 3, 'e': 2, 'f': 2}

# 获取前3个最常见的元素
top3_elements = get_top3_elements(dictionary)
print(top3_elements)