用于查找图表函数交叉点的Python脚本

import numpy as np
import matplotlib.pyplot as plt

# 定义两个函数
def f1(x):
    return x

def f2(x):
    return np.sin(x)

# 生成x轴的数据
x = np.linspace(-np.pi, np.pi, 100)

# 绘制两个函数的图表
plt.plot(x, f1(x), label='f1(x)')
plt.plot(x, f2(x), label='f2(x)')

# 查找交叉点
cross_points = []
for i in range(len(x)-1):
    if f1(x[i]) * f1(x[i+1]) < 0 and f2(x[i]) * f2(x[i+1]) < 0:
        cross_points.append((x[i], f1(x[i])))

# 打印交叉点
for point in cross_points:
    print("交叉点：x = {}, y = {}".format(point[0], point[1]))

# 显示图表
plt.legend()
plt.show()