bool is_leapyear(int year) { if(year<0) { printf("输入错误!")...0,31,28,31,30,31,30,31,31,30,31,30,31}; int totalday=0; for(int year=1990;yearyear;++year) { if(is_leapyear...(p->year)) { totalday+=366; } else { totalday+=365; } } if(is_leapyear(p->year)) {...int day; int month; }date; void init_date(date *p) { p->day=0; p->month=0; p->year=0; } bool is_leapyear...(p->year)) { totalday+=366; } else { totalday+=365; } } if(is_leapyear(p->year)) {
input.nextInt(); int month = 1, day = 0; String monthString = ""; boolean leapYear...= 0) || year % 172800 == 0) leapYear = true; else leapYear = false;...break; case 3: monthString = "March"; if (leapYear...System.out.println(); } } else if (month == 2 && leapYear
KY111 日期差值 1.1 题目分析 日期之间比较可能会出现给的两个年月日都不相同,这个就不好作差,每个月给的天数不同,还有可以是闰年,得先判断一下是不是闰年,这里就写一个判断闰年的函数: bool is_Leapyear...monthDay[13] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }; if (month == 2 && (is_is_Leapyear...1.2 代码 #include using namespace std; bool is_Leapyear(int year) { if (year % 400 == 0...int monthDay[13] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }; if (month == 2 && (is_Leapyear
System.out.println(“—->输入年数(例如2012):”); int year=sc.nextInt(); System.out.println(“你输入的年份是”+year); //leapyear...是闰年”:”不是闰年”; System.out.println(year+is); } //public static void leapyear(int year) { // // if((year
#include int is_leapyear(int year) { if (year % 4 == 0 && year % 100 !...} } int day_of_year(int year, int month, int day) { int days_in_month[] = {0, 31, (is_leapyear
bool is_is_Leapyear(int year) { if (year % 400 == 0 || (year % 4 == 0 && year % 100 !...3.2 代码 #include using namespace std; bool is_Leapyear(int year) { if (year % 400 == 0...31, 30, 31, 30, 31 }; cin >> y >> m >> d;// 注意 while 处理多个 case int sum = d; if (is_is_Leapyear
我们来通过一个判断是否闰年的LeapYear.java例子来看下if…else语句的常规写法。...1 public class LeapYear { 2 public static void main(String args[]) 3 { 4
y h # @File : xiaolianxi.py #输入月份与年份 month,year = eval(input("Enter month an year (5,2004):")) #闰年 leapyear...31 elif month ==4 or month == 6 or month == 8 or month ==9 or month ==11 : month1 =30 elif leapyear
month": "AUGUST", "era": "CE", "dayOfMonth": 1, "dayOfWeek": "TUESDAY", "dayOfYear": 213, "leapYear
now.lengthOfMonth(); System.out.println("本月一共 "+ lengthOfMonth +" 天"); final boolean leapYear...= now.isLeapYear(); System.out.println("今年是否是闰年:"+leapYear); final LocalDate firstDayOfMonth
6d %6d %6d %6d %6d %9.3f\n' % 整数 整数 整数 整数 整数 浮点数 fprintf(f,c); %% 判断闰年 y = c(1) is_leapyear
下一个是闰年的整世纪是 2400 年 1 def leapyear(year): 2 if (year % 4 == 0 and year % 100 !...year 4 return '平年' 5 6 if __name__ == '__main__': 7 year = int(input('输入年份:')) 8 print(leapyear
getMonthDays = (month = THIS_MONTH, year = THIS_YEAR) => { const months30 = [4, 6, 9, 11]; const leapYear...leapYear ? 29 : 28 : months30.includes(month) ?
www.demisto.com/ Drawbridge Networks:https://www.drawbridge.io/ Graphistry:https://www.graphistry.com/ LeapYear...:https://leapyear.io/ SentinelOne:https://sentinelone.com/ Sift Science:https://siftscience.com/ SignalSense
单元格),4)=0,MOD(YEAR(单元格),100)0),MOD(YEAR(单元格),400)=0) ② Java import java.util.Scanner;public class LeapYear
Scanner scanner = new Scanner(System.in); int year = scanner.nextInt(); boolean leapYear...= 0; boolean divisibleBy400 = year % 400 == 0; leapYear = (divisbleBy4 && notDivisbleBy100...) || divisibleBy400; System.out.println("该年份是否是闰年:" + leapYear); } } 自取资料 扩展阅读推荐 Java 基本数据类型
if ($month < 1) { $month += 12; $year--; } $leapyear...= 0 && $year % 4 == 0); $days = $leapyear ?...$result["m"]--; } } else { while ($result["d"] < 0) { $leapyear...= 0 && $year % 4 == 0); $days = $leapyear ?
"id":"ISO", "calendarType":"iso8601" }, "dayOfYear":36, "leapYear..."id":"ISO", "calendarType":"iso8601" }, "dayOfYear":36, "leapYear
int age = DateUtil.ageOfNow("1999-08-08"); System.out.println(age); boolean leapYear = DateUtil.isLeapYear...(2019); System.out.println(leapYear); 运行结果: 20 false IO操作 IO操作是Java中比较重要的操作之一,为此,Java提供了InputStream、OutputStream
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