refold :: Functor s => (sb -> b) -> (a -> s a) -> a -> b
refold f g = go where go a = f (fmap go (gNu (a -> f a) a和newtype Mu f = Mu {unMu :: forall b.(f b -> b) -> b}可以看作是余代数和代数的遗忘函
字符串输入:Python's Programming: is very easy to learn以下是我目前所掌握的不起作用的东西:mystr = "Python's Programming: is very easy to learn"print(re.findall(reg,mystr))
如何从
多个拆包作业的教科书示例如下:M = NP.arange(5)# so of course, a = 0, b = 1, etcM = NP.arange(20).reshape(5, 4) # numpy 5x4 array# here, a = M[0,:], b = M[1,:实际上,我更喜欢纯Python解决方案。)我看到了简单场景中的两个复杂问题:
--我通常不知道M的形状