任务场景的学习：python定义类

有3个小老板开店，分别是辣辣火锅店，中国口味面包店，和7天酒店。现在你要帮他们解决门口招牌的文字供顾客在网上查看。

你在仔细了解需求以后，发现有共同的地方，但酒店不同餐馆，有一个是否有房的判断。如下所示：

描述饮食店的类，包含3个属性：店名、定位和到店客人

class shop():

def __init__(self,name,cuisine):

self.cuisine=cuisine

self.name=name

def describe_shop(self):# 店的招牌

pop = 'welcome to ' + self.name + '' + self.cuisine

return pop

def open_shop(self):# 店“正在营业中”

notice = self.name + ' ' + 'isopening'

return notice

my_shop = shop('lala','hotpot')

your_shop =shop('breadtalk','chinesetyle')

输入：

print (my_shop.name)

print (my_shop.describe_shop())

print (my_shop.open_shop())

print (your_shop.describe_shop())

print (your_shop.open_shop())

输出：

lala

welcome to lala hotpot

lala is opening

welcome to breadtalk chinesetyle

breadtalk is opening

Process finished with exit code 0

7天酒店有一个新的属性需求，需要建新的类，但有店名、客人定位和到店客人都可以继承上面的父类shop。有一个属性是酒店特有的：需要说明是否客满？

假设 number_capacity = 100说明酒店共有100个房间，如果到店的客人预订的房间大于100，那么显示房间全部订出，没有空房，否则可以预定。

class hotel(shop):

def__init__(self,name,cuisine,number_served):

super().__init__(name,cuisine,number_served)

self.number_capacity = 100

def hotel_occupy_status(self):

if self.number_served >self.number_capacity:

occupy_status = 'sorry sir!' +self.name + 's all room be reserved'

else:

occupy_status = 'thank you sir!' +self.name + 'your room is to be reserved'

return occupy_status

输入：

guest_booking = hotel(' 7 days inn','biz',66)

print(guest_booking.hotel_occupy_status())

输出：

thank you sir! 7 days innyour room is to be reserved

输入：

guest_booking = hotel(' 7 days inn','biz',122)

print(guest_booking.hotel_occupy_status())

输出：

sorry sir! 7 days inns all room be reserved