【数据库】MySQL经典面试题二(练习)

【数据库】MySQL经典面试题二(练习)

需要数据库表

1.学生表

Student(SID,Sname,Sage,Ssex) --SID 学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别

2.课程表

Course(CID,Cname,TID) --CID --课程编号,Cname 课程名称,TID 教师编号

3.教师表

Teacher(TID,Tname) --TID 教师编号,Tname 教师姓名

4.成绩表

SC(SID,CID,score) --SID 学生编号,CID 课程编号,score 分数

添加测试数据

1.学生表

create table Student(SID varchar(10),Sname nvarchar(10),Sage datetime,Ssex nvarchar(10)); insert into Student values('01' , '赵雷' , '1990-01-01' , '男'); insert into Student values('02' , '钱电' , '1990-12-21' , '男'); insert into Student values('03' , '孙风' , '1990-05-20' , '男'); insert into Student values('04' , '李云' , '1990-08-06' , '男'); insert into Student values('05' , '周梅' , '1991-12-01' , '女'); insert into Student values('06' , '吴兰' , '1992-03-01' , '女'); insert into Student values('07' , '郑竹' , '1989-07-01' , '女'); insert into Student values('08' , '王菊' , '1990-01-20' , '女');

2.课程表

create table Course(CID varchar(10),Cname nvarchar(10),TID varchar(10)); insert into Course values('01' , '语文' , '02'); insert into Course values('02' , '数学' , '01'); insert into Course values('03' , '英语' , '03');

3.教师表

create table Teacher(TID varchar(10),Tname nvarchar(10)); insert into Teacher values('01' , '张三'); insert into Teacher values('02' , '李四'); insert into Teacher values('03' , '王五');

4.成绩表

create table SC(SID varchar(10),CID varchar(10),score decimal(18,1)); insert into SC values('01' , '01' , 80); insert into SC values('01' , '02' , 90); insert into SC values('01' , '03' , 99); insert into SC values('02' , '01' , 70); insert into SC values('02' , '02' , 60); insert into SC values('02' , '03' , 80); insert into SC values('03' , '01' , 80); insert into SC values('03' , '02' , 80); insert into SC values('03' , '03' , 80); insert into SC values('04' , '01' , 50); insert into SC values('04' , '02' , 30); insert into SC values('04' , '03' , 20); insert into SC values('05' , '01' , 76); insert into SC values('05' , '02' , 87); insert into SC values('06' , '01' , 31); insert into SC values('06' , '03' , 34); insert into SC values('07' , '02' , 89); insert into SC values('07' , '03' , 98);

1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数

1.1、查询同时存在"01"课程和"02"课程的情况

select a.* , b.score 课程01的分数,c.score 课程02的分数 from Student a , SC b , SC c where a.SID = b.SID and a.SID = c.SID and b.CID = '01' and c.CID = '02' and b.score > c.score

1.2、查询同时存在"01"课程和"02"课程的情况和存在"01"课程但可能不存在"02"课程的情况(不存在时显示为null)(以下存在相同内容时不再解释)

select a.* , b.score 课程01的分数,c.score 课程02的分数 from Student a left join SC b on a.SID = b.SID and b.CID = '01' left join SC c on a.SID = c.SID and c.CID = '02' where b.score > isnull(c.score,0)

2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数

2.1、查询同时存在"01"课程和"02"课程的情况

select a.* , b.score 课程01的分数 ,c.score 课程02的分数 from Student a , SC b , SC c where a.SID = b.SID and a.SID = c.SID and b.CID = '01' and c.CID = '02' and b.score < c.score

2.2、查询同时存在"01"课程和"02"课程的情况和不存在"01"课程但存在"02"课程的情况

select a.* , b.score 课程01的分数 ,c.score 课程02的分数 from Student a left join SC b on a.SID = b.SID and b.CID = '01' left join SC c on a.SID = c.SID and c.CID = '02' where isnull(b.score,0) < c.score

3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩

select a.SID , a.Sname , cast(avg(b.score) as decimal(18,2)) avg_score from Student a , sc b where a.SID = b.SID group by a.SID , a.Sname having cast(avg(b.score) as decimal(18,2)) >= 60 order by a.SID

4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩

4.1、查询在sc表存在成绩的学生信息的SQL语句。

select a.SID , a.Sname , cast(avg(b.score) as decimal(18,2)) avg_score from Student a , sc b where a.SID = b.SID group by a.SID , a.Sname having cast(avg(b.score) as decimal(18,2)) < 60 order by a.SID

4.2、查询在sc表中不存在成绩的学生信息的SQL语句。

select a.SID , a.Sname , isnull(cast(avg(b.score) as decimal(18,2)),0) avg_score from Student a left join sc b on a.SID = b.SID group by a.SID , a.Sname having isnull(cast(avg(b.score) as decimal(18,2)),0) < 60 order by a.SID

5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩

5.1、查询所有有成绩的SQL。

select a.SID 学生编号 , a.Sname 学生姓名 , count(b.CID) 选课总数, sum(score) 所有课程的总成绩 from Student a , SC b where a.SID = b.SID group by a.SID,a.Sname order by a.SID

--5.2、查询所有(包括有成绩和无成绩)的SQL。

select a.SID 学生编号 , a.Sname 学生姓名 , count(b.CID) 选课总数, sum(score) 所有课程的总成绩 from Student a left join SC b on a.SID = b.SID group by a.SID,a.Sname order by a.SID

6、查询"李"姓老师的数量

方法1 select count(Tname) 李姓老师的数量 from Teacher where Tname like '李%' 方法2 select count(Tname) 李姓老师的数量 from Teacher where left(Tname,1) = '李'

7、查询学过"张三"老师授课的同学的信息

select distinct Student.* from Student , SC , Course , Teacher where Student.SID = SC.SID and SC.CID = Course.CID and Course.TID = Teacher.TID and Teacher.Tname = '张三' order by Student.SID

8、查询没学过"张三"老师授课的同学的信息

select m.* from Student m where SID not in (select distinct SC.SID from SC , Course , Teacher where SC.CID = Course.CID and Course.TID = Teacher.TID and Teacher.Tname = '张三') order by m.SID

9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息

--方法1 select Student.* from Student , SC where Student.SID = SC.SID and SC.CID = '01' and exists (Select 1 from SC SC_2 where SC_2.SID = SC.SID and SC_2.CID = '02') order by Student.SID --方法2 select Student.* from Student , SC where Student.SID = SC.SID and SC.CID = '02' and exists (Select 1 from SC SC_2 where SC_2.SID = SC.SID and SC_2.CID = '01') order by Student.SID --方法3 select m.* from Student m where SID in ( select SID from ( select distinct SID from SC where CID = '01' union all select distinct SID from SC where CID = '02' ) t group by SID having count(1) = 2 ) order by m.SID

10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息

--方法1 select Student.* from Student , SC where Student.SID = SC.SID and SC.CID = '01' and not exists (Select 1 from SC SC_2 where SC_2.SID = SC.SID and SC_2.CID = '02') order by Student.SID --方法2 select Student.* from Student , SC where Student.SID = SC.SID and SC.CID = '01' and Student.SID not in (Select SC_2.SID from SC SC_2 where SC_2.SID = SC.SID and SC_2.CID = '02') order by Student.SID

11、查询没有学全所有课程的同学的信息

--11.1、 select Student.* from Student , SC where Student.SID = SC.SID group by Student.SID , Student.Sname , Student.Sage , Student.Ssex having count(CID) < (select count(CID) from Course) --11.2 select Student.* from Student left join SC on Student.SID = SC.SID group by Student.SID , Student.Sname , Student.Sage , Student.Ssex having count(CID) < (select count(CID) from Course)

12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息

select distinct Student.* from Student , SC where Student.SID = SC.SID and SC.CID in (select CID from SC where SID = '01') and Student.SID <> '01'

13、查询和"01"号的同学学习的课程完全相同的其他同学的信息

select Student.* from Student where SID in (select distinct SC.SID from SC where SID <> '01' and SC.CID in (select distinct CID from SC where SID = '01') group by SC.SID having count(1) = (select count(1) from SC where SID='01'))

14、查询没学过"张三"老师讲授的任一门课程的学生姓名

select student.* from student where student.SID not in (select distinct sc.SID from sc , course , teacher where sc.CID = course.CID and course.TID = teacher.TID and teacher.tname = '张三') order by student.SID

15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩

select student.SID , student.sname , cast(avg(score) as decimal(18,2)) avg_score from student , sc where student.SID = SC.SID and student.SID in (select SID from SC where score < 60 group by SID having count(1) >= 2) group by student.SID , student.sname

16、检索"01"课程分数小于60,按分数降序排列的学生信息

select student.* , sc.CID , sc.score from student , sc where student.SID = SC.SID and sc.score < 60 and sc.CID = '01' order by sc.score desc

17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

--17.1 SQL 2000 静态

select a.SID 学生编号 , a.Sname 学生姓名 , max(case c.Cname when '语文' then b.score else null end) 语文 , max(case c.Cname when '数学' then b.score else null end) 数学 , max(case c.Cname when '英语' then b.score else null end) 英语 , cast(avg(b.score) as decimal(18,2)) 平均分 from Student a left join SC b on a.SID = b.SID left join Course c on b.CID = c.CID group by a.SID , a.Sname order by 平均分 desc

17.2 SQL 2000 动态

declare @sql nvarchar(4000) set @sql = 'select a.SID ' + '学生编号' + ' , a.Sname ' + '学生姓名' select @sql = @sql + ',max(case c.Cname when '''+Cname+''' then b.score else null end) '+Cname+' ' from (select distinct Cname from Course) as t set @sql = @sql + ' , cast(avg(b.score) as decimal(18,2)) ' + '平均分' + ' from Student a left join SC b on a.SID = b.SID left join Course c on b.CID = c.CID group by a.SID , a.Sname order by ' + '平均分' + ' desc' exec(@sql)

18、查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率 --及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90

--方法1 select m.CID 课程编号 , m.Cname 课程名称 , max(n.score) 最高分 , min(n.score) 最低分 , cast(avg(n.score) as decimal(18,2)) 平均分 , cast((select count(1) from SC where CID = m.CID and score >= 60)*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 及格率 , cast((select count(1) from SC where CID = m.CID and score >= 70 and score < 80 )*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 中等率 , cast((select count(1) from SC where CID = m.CID and score >= 80 and score < 90 )*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 优良率 , cast((select count(1) from SC where CID = m.CID and score >= 90)*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 优秀率 from Course m , SC n where m.CID = n.CID group by m.CID , m.Cname order by m.CID --方法2 select m.CID 课程编号 , m.Cname 课程名称 , (select max(score) from SC where CID = m.CID) 最高分 , (select min(score) from SC where CID = m.CID) 最低分 , (select cast(avg(score) as decimal(18,2)) from SC where CID = m.CID) 平均分 , cast((select count(1) from SC where CID = m.CID and score >= 60)*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 及格率, cast((select count(1) from SC where CID = m.CID and score >= 70 and score < 80 )*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 中等率 , cast((select count(1) from SC where CID = m.CID and score >= 80 and score < 90 )*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 优良率 , cast((select count(1) from SC where CID = m.CID and score >= 90)*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 优秀率 from Course m order by m.CID

19、按各科成绩进行排序,并显示排名

--19.1 sql 2000用子查询完成

--Score重复时保留名次空缺 select t.* , px = (select count(1) from SC where CID = t.CID and score > t.score) + 1 from sc t order by t.cid , px --Score重复时合并名次 select t.* , px = (select count(distinct score) from SC where CID = t.CID and score >= t.score) from sc t order by t.cid , px

--19.2 sql 2005用rank,DENSE_RANK完成

--Score重复时保留名次空缺(rank完成) select t.* , px = rank() over(partition by cid order by score desc) from sc t order by t.CID , px --Score重复时合并名次(DENSE_RANK完成) select t.* , px = DENSE_RANK() over(partition by cid order by score desc) from sc t order by t.CID , px

20、查询学生的总成绩并进行排名

--20.1 查询学生的总成绩

select m.SID 学生编号 , m.Sname 学生姓名 , isnull(sum(score),0) 总成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname order by 总成绩 desc

--20.2 查询学生的总成绩并进行排名,sql 2000用子查询完成,分总分重复时保留名次空缺和不保留名次空缺两种。

select t1.* , px = (select count(1) from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(sum(score),0) 总成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t2 where 总成绩 > t1.总成绩) + 1 from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(sum(score),0) 总成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t1 order by px select t1.* , px = (select count(distinct 总成绩) from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(sum(score),0) 总成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t2 where 总成绩 >= t1.总成绩) from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(sum(score),0) 总成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t1 order by px

--20.3 查询学生的总成绩并进行排名,sql 2005用rank,DENSE_RANK完成,分总分重复时保留名次空缺和不保留名次空缺两种。

select t.* , px = rank() over(order by 总成绩 desc) from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(sum(score),0) 总成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t order by px select t.* , px = DENSE_RANK() over(order by 总成绩 desc) from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(sum(score),0) 总成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t order by px

21、查询不同老师所教不同课程平均分从高到低显示

select m.TID , m.Tname , cast(avg(o.score) as decimal(18,2)) avg_score from Teacher m , Course n , SC o where m.TID = n.TID and n.CID = o.CID group by m.TID , m.Tname order by avg_score desc

22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

--22.1 sql 2000用子查询完成

--Score重复时保留名次空缺 select * from (select t.* , px = (select count(1) from SC where CID = t.CID and score > t.score) + 1 from sc t) m where px between 2 and 3 order by m.cid , m.px --Score重复时合并名次 select * from (select t.* , px = (select count(distinct score) from SC where CID = t.CID and score >= t.score) from sc t) m where px between 2 and 3 order by m.cid , m.px

--22.2 sql 2005用rank,DENSE_RANK完成

--Score重复时保留名次空缺(rank完成) select * from (select t.* , px = rank() over(partition by cid order by score desc) from sc t) m where px between 2 and 3 order by m.CID , m.px --Score重复时合并名次(DENSE_RANK完成) select * from (select t.* , px = DENSE_RANK() over(partition by cid order by score desc) from sc t) m where px between 2 and 3 order by m.CID , m.px

23、统计各科成绩各分数段人数:课程编号,课程名称, 100-85 , 85-70 , 70-60 , 0-60 及所占百分比

--23.1 统计各科成绩各分数段人数:课程编号,课程名称, 100-85 , 85-70 , 70-60 , 0-60

--横向显示 select Course.CID 课程编号 , Cname as 课程名称 , sum(case when score >= 85 then 1 else 0 end) 85-100 , sum(case when score >= 70 and score < 85 then 1 else 0 end) 70-85 , sum(case when score >= 60 and score < 70 then 1 else 0 end) 60-70 , sum(case when score < 60 then 1 else 0 end) 0-60 from sc , Course where SC.CID = Course.CID group by Course.CID , Course.Cname order by Course.CID --纵向显示1(显示存在的分数段) select m.CID 课程编号 , m.Cname 课程名称 , 分数段 = ( case when n.score >= 85 then '85-100' when n.score >= 70 and n.score < 85 then '70-85' when n.score >= 60 and n.score < 70 then '60-70' else '0-60' end) , count(1) 数量 from Course m , sc n where m.CID = n.CID group by m.CID , m.Cname , ( case when n.score >= 85 then '85-100' when n.score >= 70 and n.score < 85 then '70-85' when n.score >= 60 and n.score < 70 then '60-70' else '0-60' end) order by m.CID , m.Cname , 分数段 --纵向显示2(显示存在的分数段,不存在的分数段用0显示) select m.CID 课程编号 , m.Cname 课程名称 , 分数段 = ( case when n.score >= 85 then '85-100' when n.score >= 70 and n.score < 85 then '70-85' when n.score >= 60 and n.score < 70 then '60-70' else '0-60' end) , count(1) 数量 from Course m , sc n where m.CID = n.CID group by all m.CID , m.Cname , ( case when n.score >= 85 then '85-100' when n.score >= 70 and n.score < 85 then '70-85' when n.score >= 60 and n.score < 70 then '60-70' else '0-60' end) order by m.CID , m.Cname , 分数段

--23.2 统计各科成绩各分数段人数:课程编号,课程名称, 100-85 , 85-70 , 70-60 , <60 及所占百分比

--横向显示 select m.CID 课程编号, m.Cname 课程名称, (select count(1) from SC where CID = m.CID and score < 60) 0-60 , cast((select count(1) from SC where CID = m.CID and score < 60)*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 百分比 , (select count(1) from SC where CID = m.CID and score >= 60 and score < 70) 60-70 , cast((select count(1) from SC where CID = m.CID and score >= 60 and score < 70)*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 百分比 , (select count(1) from SC where CID = m.CID and score >= 70 and score < 85) 70-85 , cast((select count(1) from SC where CID = m.CID and score >= 70 and score < 85)*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 百分比 , (select count(1) from SC where CID = m.CID and score >= 85) 85-100 , cast((select count(1) from SC where CID = m.CID and score >= 85)*100.0 / (select count(1) from SC where CID = m.CID) as decimal(18,2)) 百分比 from Course m order by m.CID --纵向显示1(显示存在的分数段) select m.CID 课程编号 , m.Cname 课程名称 , 分数段 = ( case when n.score >= 85 then '85-100' when n.score >= 70 and n.score < 85 then '70-85' when n.score >= 60 and n.score < 70 then '60-70' else '0-60' end) , count(1) 数量 , cast(count(1) * 100.0 / (select count(1) from sc where CID = m.CID) as decimal(18,2)) 百分比 from Course m , sc n where m.CID = n.CID group by m.CID , m.Cname , ( case when n.score >= 85 then '85-100' when n.score >= 70 and n.score < 85 then '70-85' when n.score >= 60 and n.score < 70 then '60-70' else '0-60' end) order by m.CID , m.Cname , 分数段 --纵向显示2(显示存在的分数段,不存在的分数段用0显示) select m.CID 课程编号 , m.Cname 课程名称 , 分数段 = ( case when n.score >= 85 then '85-100' when n.score >= 70 and n.score < 85 then '70-85' when n.score >= 60 and n.score < 70 then '60-70' else '0-60' end) , count(1) 数量 , cast(count(1) * 100.0 / (select count(1) from sc where CID = m.CID) as decimal(18,2)) 百分比 from Course m , sc n where m.CID = n.CID group by all m.CID , m.Cname , ( case when n.score >= 85 then '85-100' when n.score >= 70 and n.score < 85 then '70-85' when n.score >= 60 and n.score < 70 then '60-70' else '0-60' end) order by m.CID , m.Cname , 分数段

24、查询学生平均成绩及其名次

--24.1 查询学生的平均成绩并进行排名,sql 2000用子查询完成,分平均成绩重复时保留名次空缺和不保留名次空缺两种。

select t1.* , px = (select count(1) from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(cast(avg(score) as decimal(18,2)),0) 平均成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t2 where 平均成绩 > t1.平均成绩) + 1 from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(cast(avg(score) as decimal(18,2)),0) 平均成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t1 order by px

select t1.* , px = (select count(distinct 平均成绩) from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(cast(avg(score) as decimal(18,2)),0) 平均成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t2 where 平均成绩 >= t1.平均成绩) from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(cast(avg(score) as decimal(18,2)),0) 平均成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t1 order by px

--24.2 查询学生的平均成绩并进行排名,sql 2005用rank,DENSE_RANK完成,分平均成绩重复时保留名次空缺和不保留名次空缺两种。

select t.* , px = rank() over(order by 平均成绩 desc) from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(cast(avg(score) as decimal(18,2)),0) 平均成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t order by px

select t.* , px = DENSE_RANK() over(order by 平均成绩 desc) from ( select m.SID 学生编号 , m.Sname 学生姓名 , isnull(cast(avg(score) as decimal(18,2)),0) 平均成绩 from Student m left join SC n on m.SID = n.SID group by m.SID , m.Sname ) t order by px

25、查询各科成绩前三名的记录

--25.1 分数重复时保留名次空缺

select m.* , n.CID , n.score from Student m, SC n where m.SID = n.SID and n.score in (select top 3 score from sc where CID = n.CID order by score desc) order by n.CID , n.score desc

--25.2 分数重复时不保留名次空缺,合并名次

--sql 2000用子查询实现 select * from (select t.* , px = (select count(distinct score) from SC where CID = t.CID and score >= t.score) from sc t) m where px between 1 and 3 order by m.Cid , m.px --sql 2005用DENSE_RANK实现 select * from (select t.* , px = DENSE_RANK() over(partition by Cid order by score desc) from sc t) m where px between 1 and 3 order by m.CID , m.px

26、查询每门课程被选修的学生数

select Cid , count(SID) 学生数 from sc group by CID

27、查询出只有两门课程的全部学生的学号和姓名

select Student.SID , Student.Sname from Student , SC where Student.SID = SC.SID group by Student.SID , Student.Sname having count(SC.CID) = 2 order by Student.SID

--28、查询男生、女生人数

select count(Ssex) as 男生人数 from Student where Ssex = N'男' select count(Ssex) as 女生人数 from Student where Ssex = N'女' select sum(case when Ssex = N'男' then 1 else 0 end) 男生人数 ,sum(case when Ssex = N'女' then 1 else 0 end) 女生人数 from student select case when Ssex = N'男' then N'男生人数' else N'女生人数' end 男女情况 , count(1) 人数 from student group by case when Ssex = N'男' then N'男生人数' else N'女生人数' end

29、查询名字中含有"风"字的学生信息

select * from student where sname like N'%风%' select * from student where charindex(N'风' , sname) > 0

30、查询同名同性学生名单,并统计同名人数

select Sname 学生姓名 , count(*) 人数 from Student group by Sname having count(*) > 1

31、查询1990年出生的学生名单(注:Student表中Sage列的类型是datetime)

select * from Student where year(sage) = 1990 select * from Student where datediff(yy,sage,'1990-01-01') = 0 select * from Student where datepart(yy,sage) = 1990 select * from Student where convert(varchar(4),sage,120) = '1990'

32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列

select m.CID , m.Cname , cast(avg(n.score) as decimal(18,2)) avg_score from Course m, SC n where m.CID = n.CID group by m.CID , m.Cname order by avg_score desc, m.CID asc

33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩

select a.SID , a.Sname , cast(avg(b.score) as decimal(18,2)) avg_score from Student a , sc b where a.SID = b.SID group by a.SID , a.Sname having cast(avg(b.score) as decimal(18,2)) >= 85 order by a.SID

34、查询课程名称为"数学",且分数低于60的学生姓名和分数

select sname , score from Student , SC , Course where SC.SID = Student.SID and SC.CID = Course.CID and Course.Cname = N'数学' and score < 60

35、查询所有学生的课程及分数情况

select Student.* , Course.Cname , SC.CID , SC.score from Student, SC , Course where Student.SID = SC.SID and SC.CID = Course.CID order by Student.SID , SC.CID

36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数

select Student.* , Course.Cname , SC.CID , SC.score from Student, SC , Course where Student.SID = SC.SID and SC.CID = Course.CID and SC.score >= 70 order by Student.SID , SC.CID

37、查询不及格的课程

select Student.* , Course.Cname , SC.CID , SC.score from Student, SC , Course where Student.SID = SC.SID and SC.CID = Course.CID and SC.score < 60 order by Student.SID , SC.CID

38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名

select Student.* , Course.Cname , SC.CID , SC.score from Student, SC , Course where Student.SID = SC.SID and SC.CID = Course.CID and SC.CID = '01' and SC.score >= 80 order by Student.SID , SC.CID

39、求每门课程的学生人数

select Course.CID , Course.Cname , count(*) 学生人数 from Course , SC where Course.CID = SC.CID group by Course.CID , Course.Cname order by Course.CID , Course.Cname

40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩

40.1 当最高分只有一个时

select top 1 Student.* , Course.Cname , SC.CID , SC.score from Student, SC , Course , Teacher where Student.SID = SC.SID and SC.CID = Course.CID and Course.TID = Teacher.TID and Teacher.Tname = N'张三' order by SC.score desc

40.2 当最高分出现多个时

select Student.* , Course.Cname , SC.CID , SC.score from Student, SC , Course , Teacher where Student.SID = SC.SID and SC.CID = Course.CID and Course.TID = Teacher.TID and Teacher.Tname = N'张三' and SC.score = (select max(SC.score) from SC , Course , Teacher where SC.CID = Course.CID and Course.TID = Teacher.TID and Teacher.Tname = N'张三')

41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

--方法1 select m.* from SC m ,(select CID , score from SC group by CID , score having count(1) > 1) n where m.CID= n.CID and m.score = n.score order by m.CID , m.score , m.SID --方法2 select m.* from SC m where exists (select 1 from (select CID , score from SC group by CID , score having count(1) > 1) n where m.CID= n.CID and m.score = n.score) order by m.CID , m.score , m.SID

42、查询每门功成绩最好的前两名

select t.* from sc t where score in (select top 2 score from sc where CID = T.CID order by score desc) order by t.CID , t.score desc

43、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列

select Course.CID , Course.Cname , count(*) 学生人数 from Course , SC where Course.CID = SC.CID group by Course.CID , Course.Cname having count(*) >= 5 order by 学生人数 desc , Course.CID

44、检索至少选修两门课程的学生学号

select student.SID , student.Sname from student , SC where student.SID = SC.SID group by student.SID , student.Sname having count(1) >= 2 order by student.SID

45、查询选修了全部课程的学生信息

--方法1 根据数量来完成 select student.* from student where SID in (select SID from sc group by SID having count(1) = (select count(1) from course)) --方法2 使用双重否定来完成 select t.* from student t where t.SID not in ( select distinct m.SID from ( select SID , CID from student , course ) m where not exists (select 1 from sc n where n.SID = m.SID and n.CID = m.CID) ) --方法3 使用双重否定来完成 select t.* from student t where not exists(select 1 from ( select distinct m.SID from ( select SID , CID from student , course ) m where not exists (select 1 from sc n where n.SID = m.SID and n.CID = m.CID) ) k where k.SID = t.SID )

46、查询各学生的年龄

--46.1 只按照年份来算

select * , datediff(yy , sage , getdate()) 年龄 from student

--46.2 按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一

select * , case when right(convert(varchar(10),getdate(),120),5) < right(convert(varchar(10),sage,120),5) then datediff(yy , sage , getdate()) - 1 else datediff(yy , sage , getdate()) end 年龄 from student

47、查询本周过生日的学生

select * from student where datediff(week,datename(yy,getdate()) + right(convert(varchar(10),sage,120),6),getdate()) = 0

48、查询下周过生日的学生

select * from student where datediff(week,datename(yy,getdate()) + right(convert(varchar(10),sage,120),6),getdate()) = -1

49、查询本月过生日的学生

select * from student where datediff(mm,datename(yy,getdate()) + right(convert(varchar(10),sage,120),6),getdate()) = 0

50、查询下月过生日的学生

select * from student where datediff(mm,datename(yy,getdate()) + right(convert(varchar(10),sage,120),6),getdate()) = -1

drop table Student,Course,Teacher,SC

原文发布于微信公众号 - Java帮帮(javahelp)

原文发表时间:2017-10-12

本文参与腾讯云自媒体分享计划,欢迎正在阅读的你也加入,一起分享。

发表于

我来说两句

0 条评论
登录 后参与评论

相关文章

来自专栏java一日一条

SQL数据库面试题以及答案

S#:学号;Sname:学生姓名;Sage:学生年龄;Ssex:学生性别 Course(C#,Cname,T#) 课程表

1013
来自专栏WOLFRAM

错觉艺术的巅峰,错觉图形大师M.C. Escher的不可能方块的可能模型

1833
来自专栏WOLFRAM

2016年Wolfram一行代码大赛获奖部分作品

2548
来自专栏牛客网

宜信大数据中心java研发岗面经

在我小时候,我极力装得像个大人,当我已经不再是小孩的时候,我又希望像个孩子。——列夫·托尔斯泰

1392
来自专栏小樱的经验随笔

HDU 2549 壮志难酬

壮志难酬 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java...

27110
来自专栏ml

HDUOJ----2512一卡通大冒险

一卡通大冒险 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Ja...

3519
来自专栏程序员互动联盟

【编程之美】斐波拉契数列

斐波拉契 意大利的数学家列昂那多·斐波那契在1202年研究兔子产崽问题时发现了此数列.设一对大兔子每月生一对小兔子,每对新生兔在出生一个月后又下崽,假若兔子都不...

3555
来自专栏文武兼修ing——机器学习与IC设计

关于空难数据集的探索分析导入数据集伤亡分析机型处理时间分析

写在前面: 这是我见过的最严肃的数据集,几乎每一行数据背后都是生命和鲜血的代价。这次探索分析并不妄图说明什么,仅仅是对数据处理能力的锻炼。因此本次的探索分析...

4355
来自专栏ml

HDUOJ---2110

Crisis of HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/3276...

2517
来自专栏菩提树下的杨过

Flash/Flex学习笔记(39):弹性运动

动画中的弹性运动 从视觉效果上接近 物理经典力学中的单摆运动或弹簧(胡克定律F=Kx)振动 先看下面的模拟演示: 规律: 小球先从出发点(初始为最左侧)向目标点...

2045

扫码关注云+社区

领取腾讯云代金券