前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >POJ 刷题系列:1094. Sorting It All Out

POJ 刷题系列:1094. Sorting It All Out

作者头像
用户1147447
发布2019-05-25 22:15:23
2970
发布2019-05-25 22:15:23
举报
文章被收录于专栏:机器学习入门机器学习入门

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://cloud.tencent.com/developer/article/1433612

POJ 刷题系列:1094. Sorting It All Out

传送门:1094. Sorting It All Out

题意:

给出n个字母,m组大小关系,判断是否能够确定n个字母的唯一顺序,其中不能存在环。

思路:

一开始使用了DFS,每当加入一条关系时,更新邻接表,并判断是否存在环以及能否得到唯一的拓扑序,结果一直超时,不知道歪。实际上如果存在唯一的顺序,那么当且仅当只有一个点入度为0,所以当queue同一时刻存在多个入度为0的点时,说明并非唯一。其次,如果最终输出的拓扑序小于n说明存在环。

代码如下:

代码语言:javascript
复制
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayDeque;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashSet;
import java.util.List;
import java.util.Map;
import java.util.Queue;
import java.util.Set;
import java.util.StringTokenizer;

public class Main{

    String INPUT = "./data/judge/201801/P1094.txt";

    public static void main(String[] args) throws IOException {
        new Main().run();
    }

    int n;

    void read() {

        while (true) {
            n = ni();
            int m = ni();
            if (n + m == 0) break;
            List<Integer>[] graph = new ArrayList[n];
            for (int i = 0; i < n; ++i) graph[i] = new ArrayList<Integer>();

            int[] indegree = new int[n];
            boolean hasAns = false;
            hasCircle = false;
            for (int i = 0; i < m; ++i) {
                String ns = ns();
                int u = ns.charAt(0) - 'A';
                int v = ns.charAt(2) - 'A';
                indegree[v] ++;
                graph[u].add(v);
                if (!hasAns) {
                    if (top(graph, indegree)) {
                        out.println("Sorted sequence determined after " + (i + 1) + " relations: " + ans + ".");
                        hasAns = true;
                    }
                    else {
                        if(hasCircle) {
                            out.println("Inconsistency found after "+ (i + 1) +" relations.");
                            hasAns = true;
                        }
                    }
                }
            }
            if (!hasAns)
                out.println("Sorted sequence cannot be determined.");
        }
    }

    String ans = "";
    boolean hasCircle = false;
    boolean top(List<Integer>[] graph, int[] indegree) {
        int[] copy = new int[n];
        System.arraycopy(indegree, 0, copy, 0, n);

        StringBuilder sb = new StringBuilder();
        Queue<Integer> q = new ArrayDeque<Integer>();
        boolean[] vis = new boolean[n];

        for (int i = 0; i < n; ++i) {
            if (copy[i] == 0) {
                q.offer(i);
                vis[i] = true;
            }
        }

        boolean once = true;
        while (!q.isEmpty()) {
            if (q.size() >= 2) once = false;
            int now = q.poll();
            char c = (char) (now + 'A');
            sb.append(c);
            for (int to : graph[now]) {
                copy[to] --;
            }
            for (int i = 0; i < n; ++i) {
                if (!vis[i] && copy[i] == 0) {
                    q.offer(i);
                    vis[i] = true;
                }
            }
        }
        if (sb.length() == n && once) {
            ans = sb.toString();
            return true;
        }
        else if (sb.length() == n && !once) return false;
        hasCircle = true;
        return false;
    }


    FastScanner in;
    PrintWriter out;

    void run() throws IOException {
        boolean oj;
        try {
            oj = ! System.getProperty("user.dir").equals("F:\\oxygen_workspace\\Algorithm");
        } catch (Exception e) {
            oj = System.getProperty("ONLINE_JUDGE") != null;
        }

        InputStream is = oj ? System.in : new FileInputStream(new File(INPUT));
        in = new FastScanner(is);
        out = new PrintWriter(System.out);
        long s = System.currentTimeMillis();
        read();
        out.flush();
        if (!oj){
            System.out.println("[" + (System.currentTimeMillis() - s) + "ms]");
        }
    }

    public boolean more(){
        return in.hasNext();
    }

    public int ni(){
        return in.nextInt();
    }

    public long nl(){
        return in.nextLong();
    }

    public double nd(){
        return in.nextDouble();
    }

    public String ns(){
        return in.nextString();
    }

    public char nc(){
        return in.nextChar();
    }

    class FastScanner {
        BufferedReader br;
        StringTokenizer st;
        boolean hasNext;

        public FastScanner(InputStream is) throws IOException {
            br = new BufferedReader(new InputStreamReader(is));
            hasNext = true;
        }

        public String nextToken() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (Exception e) {
                    hasNext = false;
                    return "##";
                }
            }
            return st.nextToken();
        }

        String next = null;
        public boolean hasNext(){
            next = nextToken();
            return hasNext;
        }

        public int nextInt() {
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return Integer.parseInt(more);
        }

        public long nextLong() {
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return Long.parseLong(more);
        }

        public double nextDouble() {
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return Double.parseDouble(more);
        }

        public String nextString(){
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return more;
        }

        public char nextChar(){
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return more.charAt(0);
        }
    }

    static class D{

        public static void pp(int[][] board, int row, int col) {
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < row; ++i) {
                for (int j = 0; j < col; ++j) {
                    sb.append(board[i][j] + (j + 1 == col ? "\n" : " "));
                }
            }
            System.out.println(sb.toString());
        }

        public static void pp(char[][] board, int row, int col) {
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < row; ++i) {
                for (int j = 0; j < col; ++j) {
                    sb.append(board[i][j] + (j + 1 == col ? "\n" : " "));
                }
            }
            System.out.println(sb.toString());
        }
    }

    static class ArrayUtils {

        public static void fill(int[][] f, int value) {
            for (int i = 0; i < f.length; ++i) {
                Arrays.fill(f[i], value);
            }
        }

        public static void fill(int[][][] f, int value) {
            for (int i = 0; i < f.length; ++i) {
                fill(f[i], value);
            }
        }

        public static void fill(int[][][][] f, int value) {
            for (int i = 0; i < f.length; ++i) {
                fill(f[i], value);
            }
        }
    }

    static class Num{
        public static <K> void inc(Map<K, Integer> mem, K k) {
            if (!mem.containsKey(k)) mem.put(k, 0);
            mem.put(k, mem.get(k) + 1);
        }
    }
}
本文参与 腾讯云自媒体分享计划,分享自作者个人站点/博客。
原始发表:2018年01月04日,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体分享计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
目录
  • POJ 刷题系列:1094. Sorting It All Out
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档