LeetCode 166. Fraction to Recurring Decimal(模拟)

class Solution {
public:
    map<int,int> m;
    string fractionToDecimal(int numerator, int denominator) {
       long long int numerator_ = numerator;
       long long int denominator_ = denominator;
        int sign = 1;
        if(numerator_<0&&denominator_>0)
        {
            sign = 0;
        }
       
        else if(numerator_>0&&denominator_<0)
        {
            
            sign = 0;
        }
        
         if(numerator_<0)
            numerator_ *= -1;
        
        if(denominator_<0)
            denominator_ *= -1;

       string ans="";
    

       if(numerator_ > denominator_)
       {
           long long int x = numerator_ / denominator_;
           numerator_ = numerator_ % denominator_;  
           ans += to_string(x);
       }
       else
       {
           ans += '0';
       }
        
         m[numerator_] = 1;
        
       if(numerator_!=0) 
        ans+='.';
        
       int tag=1;
       int pos=0;
        
       while(numerator_!=0)
       {
           numerator_ *= 10;
           
           long long int  x = numerator_ / denominator_ ;
           
           ans += (x+'0');

           numerator_ = numerator_ % denominator_;  
           
           if(numerator_==0)
               break;
           
           if(m[numerator_]!=0)
           {
               pos = m[numerator_];
               break;
           }
           else
           {
               m[numerator_]=++tag;
           }
       }
        
        
        string res="";
        if(sign==0)
            res += '-';
        int i;
        tag=-1;
        int tag2=0;
        for(i=0;i<ans.length();i++)
        {
            
            
            if(tag==pos)
            {
                res+='(';
                tag2=1;
            }
            
            res+=ans[i];
            
            if(tag>=1)
            {
                tag++;
            }
            
            if(ans[i]=='.')
            {
                tag=1;
            }
        }
        
        if(tag2==1)
        res+=')';
        
        return res;
        
    }
};