每个节点最多只有两个子节点的树
所有的叶子节点都在最后一层,并且节点总数 2^n-1 n 为层数
所有的叶子节点都在最后一层或者倒数第二层,而且最后一层的叶子节点在左边连续,倒数第二层的叶子节点在右边连续
前序:先输出父节点,再遍历左子树和右子树 中序:先遍历左子树,再输出父节点,再遍历右子树 后序:先遍历左子树,再遍历右子树,最后输出父节点
class BinaryTree {
private HeroNode root;
public void setRoot(HeroNode root) {
this.root = root;
}
//前序遍历
public void preOrder() {
if (this.root != null) {
this.root.preOrder();
}
}
public void infixOrder() {
if (this.root != null) {
this.root.infixOrder();
}
}
public void postOrder() {
if (this.root != null) {
this.root.postOrder();
}
}
//前序查找
public HeroNode preOrderSearch(int no) {
if (root != null) {
return root.preOrderSearch(no);
} else {
return null;
}
}
public HeroNode infixOrderSearch(int no) {
if (root != null) {
return root.infixOrderSearch(no);
} else {
return null;
}
}
public HeroNode postOrderSearch(int no) {
if (root != null) {
return root.postOrderSearch(no);
} else {
return null;
}
}
}
class HeroNode {
private int no;
private String name;
private HeroNode left;
private HeroNode right;
public HeroNode(int no, String name) {
this.no = no;
this.name = name;
}
public int getNo() {
return no;
}
public void setNo(int no) {
this.no = no;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public HeroNode getLeft() {
return left;
}
public void setLeft(HeroNode left) {
this.left = left;
}
public HeroNode getRight() {
return right;
}
public void setRight(HeroNode right) {
this.right = right;
}
@Override
public String toString() {
return "HearNode{" +
"no=" + no +
", name='" + name + '\'' +
'}';
}
//前序遍历
public void preOrder() {
System.out.println(this);
if (this.left != null) {
this.left.preOrder();
}
if (this.right != null) {
this.right.preOrder();
}
}
//中序遍历
public void infixOrder() {
if (this.left != null) {
this.left.infixOrder();
}
System.out.println(this);
if (this.right != null) {
this.right.infixOrder();
}
}
//后序遍历
public void postOrder() {
if (this.left != null) {
this.left.postOrder();
}
if (this.right != null) {
this.right.postOrder();
}
System.out.println(this);
}
//前序查找
public HeroNode preOrderSearch(int no) {
if (this.no == no) {
return this;
}
HeroNode resNode = null;
if (this.left != null) {
resNode = this.left.preOrderSearch(no);
}
if (resNode != null) {
return resNode;
}
/*
1.左递归前序查找,找到节点就返回,否则继续判断
2. 当前节点的右子节点是否为空如果不为空则继续
*/
if (this.right != null) {
resNode = this.right.preOrderSearch(no);
}
return resNode;
}
//中序查找
public HeroNode infixOrderSearch(int no) {
HeroNode resNode = null;
if (this.left != null) {
resNode = this.left.preOrderSearch(no);
}
if (resNode != null) {
return resNode;
}
if (this.no == no) {
return this;
}
if (this.right != null) {
resNode = this.right.preOrderSearch(no);
}
return resNode;
}
//后序查找
public HeroNode postOrderSearch(int no) {
HeroNode resNode = null;
if (this.left != null) {
resNode = this.left.preOrderSearch(no);
}
if (resNode != null) {
return resNode;
}
if (this.right != null) {
resNode = this.right.preOrderSearch(no);
}
if (resNode != null) {
return resNode;
}
if (this.no == no) {
return this;
}
return resNode;
}
}