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社区首页 >专栏 >A Tile Painting(循环节)

A Tile Painting(循环节)

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风骨散人Chiam
发布2020-10-28 11:45:55
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发布2020-10-28 11:45:55
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文章被收录于专栏:CSDN旧文CSDN旧文CSDN旧文

Ujan has been lazy lately, but now has decided to bring his yard to good shape. First, he decided to paint the path from his house to the gate.

The path consists of nn consecutive tiles, numbered from 11 to nn. Ujan will paint each tile in some color. He will consider the path aesthetic if for any two different tiles with numbers ii and jj, such that |j−i||j−i| is a divisor of nn greater than 11, they have the same color. Formally, the colors of two tiles with numbers ii and jj should be the same if |i−j|>1|i−j|>1 and nmod|i−j|=0nmod|i−j|=0 (where xmodyxmody is the remainder when dividing xx by yy).

Ujan wants to brighten up space. What is the maximum number of different colors that Ujan can use, so that the path is aesthetic?

Input

The first line of input contains a single integer nn (1≤n≤10121≤n≤1012), the length of the path.

Output

Output a single integer, the maximum possible number of colors that the path can be painted in.

Examples

Input

4

Output

2

Input

5

Output

5

Note

In the first sample, two colors is the maximum number. Tiles 11 and 33 should have the same color since 4mod|3−1|=04mod|3−1|=0. Also, tiles 22 and 44 should have the same color since 4mod|4−2|=04mod|4−2|=0.

In the second sample, all five colors can be used.

#include<bits/stdc++.h>
using namespace std;
int main()
{
    long long  n,ans;
    bool flag=1;
    scanf("%lld",&n);
    ans=n;
    for(long long i=2;i<=sqrt(n);++i)
    {
        if(n%i==0)
        {
                ans=__gcd(ans,i);
                ans=__gcd(ans,n/i);
        }
    }
    printf("%lld\n",ans);
}
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原始发表:2019-11-19 ,如有侵权请联系 cloudcommunity@tencent.com 删除

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