首页
学习
活动
专区
圈层
工具
发布
首页
学习
活动
专区
圈层
工具
MCP广场
社区首页 >专栏 >37 Number of Steps to Reduce a Number to Zero

37 Number of Steps to Reduce a Number to Zero

作者头像
devi
发布2021-08-18 16:16:26
发布2021-08-18 16:16:26
65600
代码可运行
举报
文章被收录于专栏:搬砖记录搬砖记录
运行总次数:0
代码可运行

题目

Given a non-negative integer num, return the number of steps to reduce it to zero. If the current number is even, you have to divide it by 2, otherwise, you have to subtract 1 from it.

Example 1:

Input: num = 14 Output: 6 Explanation: Step 1) 14 is even; divide by 2 and obtain 7. Step 2) 7 is odd; subtract 1 and obtain 6. Step 3) 6 is even; divide by 2 and obtain 3. Step 4) 3 is odd; subtract 1 and obtain 2. Step 5) 2 is even; divide by 2 and obtain 1. Step 6) 1 is odd; subtract 1 and obtain 0.

Example 2:

Input: num = 8 Output: 4 Explanation: Step 1) 8 is even; divide by 2 and obtain 4. Step 2) 4 is even; divide by 2 and obtain 2. Step 3) 2 is even; divide by 2 and obtain 1. Step 4) 1 is odd; subtract 1 and obtain 0.

Example 3:

Input: num = 123 Output: 12

Constraints:

代码语言:javascript
代码运行次数:0
运行
复制
0 <= num <= 10^6

分析

题意:给定一个非负整数,如果它是偶数,那就除以二,如果是奇数,那就减一,直到该数为0;返回操作步数。

题目简单易懂,直接上手。

解答

代码语言:javascript
代码运行次数:0
运行
复制
class Solution {
    public int numberOfSteps (int num) {
        int res=0;
        while(num!=0){
            if(num%2==0)
                num/=2;
            else
                num-=1;
            res++;
        }
        return res;
    }
}

位运算(参考)

代码语言:javascript
代码运行次数:0
运行
复制
class Solution {
    public int numberOfSteps (int num) {
        
        int firstBitMask = 1;
        int steps = 0;
        while(num>0){
            if((num & firstBitMask) >0){
                num &= ~firstBitMask;
            }else{
                num = num >>1; 
            }
            steps ++;
        }
        return steps;
        
    }
}
本文参与 腾讯云自媒体同步曝光计划,分享自作者个人站点/博客。
原始发表:2020/02/29 ,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体同步曝光计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
目录
  • 题目
  • 分析
  • 解答
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档