java中判断是否为数组[通俗易懂]

public List findByProperty(String propertyName, Object value) {
		List list = new ArrayList();
		String queryString = "from Userinfo as model where model." + propertyName + "= ? order by model.userInfoId DESC";
		
		try {
//			//判断是否为String数组类型
			if ( value instanceof   String[] ){
				//如果为true则强转成String数组
				String [] arr = ( String[] ) value ;
				for ( int i = 0 ; i < arr.length ; i++ ){
					this.getHibernateTemplate().find(queryString, value);
					list.add(this.getHibernateTemplate().find(queryString, arr[i]));
				}
			}else{
				list = this.getHibernateTemplate().find(queryString, value);
			}
		} catch (RuntimeException re) {
			log.error("find by property name failed", re);
			throw re;
		}
		return list;
	}

此代码由Java架构师必看网-架构君整理
/**
   * 对象是否为数组对象
   *
   * @param obj 对象
   * @return 是否为数组对象，如果为{@code null} 返回false
   */
  public static boolean isArray(Object obj) {
      if (null == obj) {
//            throw new NullPointerException("Object check for isArray is null");
          return false;
      }
//        反射 获得类型
      return obj.getClass().isArray();
  }