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社区首页 >专栏 >Leetcode 题目解析之 Ugly Number II

Leetcode 题目解析之 Ugly Number II

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ruochen
发布2022-02-13 15:16:42
发布2022-02-13 15:16:42
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Write a program to find the n-th ugly number.

Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 1, 2, 3, 4, 5, 6, 8, 9, 10, 12 is the sequence of the first 10 ugly numbers.

Note that 1 is typically treated as an ugly number.

Hint:

  1. The naive approach is to call isUgly for every number until you reach the nth one. Most numbers are not ugly. Try to focus your effort on generating only the ugly ones.
  2. An ugly number must be multiplied by either 2, 3, or 5 from a smaller ugly number.
  3. The key is how to maintain the order of the ugly numbers. Try a similar approach of merging from three sorted lists: L1, L2, and L3.
  4. Assume you have Uk, the kth ugly number. Then Uk+1 must be Min(L1 2, L2 3, L3 * 5).

维持一个数组,依次存入丑数序列。

代码语言:javascript
代码运行次数:0
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    public int nthUglyNumber(int n) {
        int[] nums = new int[n];
        nums[0] = 1;
        int i = 0, j = 0, k = 0, t = 1;
        while (t < n) {
            int min = Math.min(Math.min(nums[i] * 2, nums[j] * 3), nums[k] * 5);
            nums[t++] = min;
            if (nums[i] * 2 == min) {
                i++;
            }
            if (nums[j] * 3 == min) {
                j++;
            }
            if (nums[k] * 5 == min) {
                k++;
            }
        }
        return nums[n - 1];
    }

原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。

如有侵权,请联系 cloudcommunity@tencent.com 删除。

原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。

如有侵权,请联系 cloudcommunity@tencent.com 删除。

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