【JavaScript】js对象进行排序（对象转数组,对象转对象）

aaa = {

    "2\_4":{"a":1,"b":2},

    "2\_16":{"a":1,"b":2},

    "2\_12":{"a":1,"b":2},

    "2\_8":{"a":1,"b":2}

}

let aaa = {"2\_4":{"a":2,"b":4},"2\_16":{"a":2,"b":16},"2\_12":{"a":2,"b":12},"2\_8":{"a":2,"b":8}}

let aa = Object.keys(aaa).sort((a,b)=>{

    a\_list = a.split("\_");

    b\_list = b.split("\_");

    return a\_list[0]==b\_list[0]?a\_list[1]-b\_list[1]:a\_list[0]-b\_list[0]

    // return aaa[a].sort-aaa[b].sort;

})

let arr = Object();

for (var sortIndex in aa) {

     arr[aa[sortIndex]] = aaa[aa[sortIndex]]

}

console.log(arr);

    Object.keys(aaa).sort((a,b){

       // 代码逻辑,根据keys排序，如果a>b的排序使用a-b

       // 这里的a,b就会根据return返回排序，如果a-b返回true就是a大b小，所以a在后b在前

       return a-b

    })

# 方法1：把对象转为数组

let aaa = {"2\_4":{"a":2,"b":4},"2\_16":{"a":2,"b":16},"2\_12":{"a":2,"b":12},"2\_8":{"a":2,"b":8}}

let aa = Object.keys(aaa).sort((a,b)=>{

    a\_list = a.split("\_");

    b\_list = b.split("\_");

    return a\_list[0]==b\_list[0]?a\_list[1]-b\_list[1]:a\_list[0]-b\_list[0]

    // return aaa[a].sort-aaa[b].sort;

})

// 把排序好的结果放在新的数组中

let arr = [];

for (var sortIndex in aa) {

      arr.push(aaa[aa[sortIndex]])

    }

console.log(arr);





# 方法2：下面使用数组生成我们想要的排好序的对象



let aaa = {"2\_4":{"a":2,"b":4},"2\_16":{"a":2,"b":16},"2\_12":{"a":2,"b":12},"2\_8":{"a":2,"b":8}}

let aa = Object.keys(aaa).sort((a,b)=>{

    a\_list = a.split("\_");

    b\_list = b.split("\_");

    return a\_list[0]==b\_list[0]?a\_list[1]-b\_list[1]:a\_list[0]-b\_list[0]

    // return aaa[a].sort-aaa[b].sort;

})

let arr = Object();

for (var sortIndex in aa) {

     arr[aa[sortIndex]] = aaa[aa[sortIndex]]

}

console.log(arr);

let aaa = {"2\_4":{"cpu":2,"ram":4},"2\_16":{"cpu":2,"ram":16},"2\_12":{"cpu":2,"ram":12},"2\_8":{"cpu":2,"ram":8}}

let aa = Object.values(aaa).sort((a,b)=>{

    return a["cpu"]==b["cpu"]?a["ram"]-b["ram"]:a["cpu"]-b["cpu"]

})

console.log(aa);