如何使用grid.arrange排列任意数量的ggplot？
如何使用grid.arrange排列任意数量的ggplot？
提问于 2011-07-13 23:10:45
这篇文章被交叉发布在ggplot2 google group上
我的情况是，我是working on a function，它输出任意数量的图(取决于用户提供的输入数据)。该函数返回n个图的列表，我想以2x2的形式排列这些图。我正在与同时存在的问题作斗争：
- 如何才能灵活地处理任意(n)个绘图？
- 我如何还可以指定我想要它们的布局为2 x 2
我当前的策略使用gridExtra包中的grid.arrange。它可能不是最优的，特别是因为，这是关键，它完全不起作用。下面是我的注释样例代码，实验了三个图：
library(ggplot2)
library(gridExtra)
x <- qplot(mpg, disp, data = mtcars)
y <- qplot(hp, wt, data = mtcars)
z <- qplot(qsec, wt, data = mtcars)
# A normal, plain-jane call to grid.arrange is fine for displaying all my plots
grid.arrange(x, y, z)
# But, for my purposes, I need a 2 x 2 layout. So the command below works acceptably.
grid.arrange(x, y, z, nrow = 2, ncol = 2)
# The problem is that the function I'm developing outputs a LIST of an arbitrary
# number plots, and I'd like to be able to plot every plot in the list on a 2 x 2
# laid-out page. I can at least plot a list of plots by constructing a do.call()
# expression, below. (Note: it totally even surprises me that this do.call expression
# DOES work. I'm astounded.)
plot.list <- list(x, y, z)
do.call(grid.arrange, plot.list)
# But now I need 2 x 2 pages. No problem, right? Since do.call() is taking a list of
# arguments, I'll just add my grid.layout arguments to the list. Since grid.arrange is
# supposed to pass layout arguments along to grid.layout anyway, this should work.
args.list <- c(plot.list, "nrow = 2", "ncol = 2")
# Except that the line below is going to fail, producing an "input must be grobs!"
# error
do.call(grid.arrange, args.list)就像我惯常做的那样，我谦虚地挤在角落里，急切地等待着一个比我聪明得多的社区的睿智反馈，特别是如果我让这件事变得比需要的更难。
回答 3
Stack Overflow用户
回答已采纳
发布于 2011-07-13 23:27:05
你就快到了！问题是do.call希望您的args位于一个命名的list对象中。您已将它们放入列表中，但将它们作为字符串，而不是命名列表项。
我认为这应该行得通：
args.list <- c(plot.list, 2,2)
names(args.list) <- c("x", "y", "z", "nrow", "ncol")正如Ben和Joshua在评论中指出的那样，我可以在创建列表时指定名称：
args.list <- c(plot.list,list(nrow=2,ncol=2))或
args.list <- list(x=x, y=y, z=x, nrow=2, ncol=2)Stack Overflow用户
发布于 2011-07-14 08:17:16
尝尝这个,
require(ggplot2)
require(gridExtra)
plots <- lapply(1:11, function(.x) qplot(1:10,rnorm(10), main=paste("plot",.x)))
params <- list(nrow=2, ncol=2)
n <- with(params, nrow*ncol)
## add one page if division is not complete
pages <- length(plots) %/% n + as.logical(length(plots) %% n)
groups <- split(seq_along(plots),
gl(pages, n, length(plots)))
pl <-
lapply(names(groups), function(g)
{
do.call(arrangeGrob, c(plots[groups[[g]]], params,
list(main=paste("page", g, "of", pages))))
})
class(pl) <- c("arrangelist", "ggplot", class(pl))
print.arrangelist = function(x, ...) lapply(x, function(.x) {
if(dev.interactive()) dev.new() else grid.newpage()
grid.draw(.x)
}, ...)
## interactive use; open new devices
pl
## non-interactive use, multipage pdf
ggsave("multipage.pdf", pl)Stack Overflow用户
发布于 2013-08-05 11:56:06
我回答得有点晚，但在R Graphics Cookbook上偶然发现了一个解决方案，它使用一个名为multiplot的自定义函数来做一些非常类似的事情。也许它会帮助其他发现这个问题的人。我还添加了答案，因为这个问题的解决方案可能比其他答案更新。
Multiple graphs on one page (ggplot2)
这是当前的函数，但请使用上面的链接，因为作者指出，它已经在ggplot2 0.9.3中更新，这表明它可能会再次更改。
# Multiple plot function
#
# ggplot objects can be passed in ..., or to plotlist (as a list of ggplot objects)
# - cols: Number of columns in layout
# - layout: A matrix specifying the layout. If present, 'cols' is ignored.
#
# If the layout is something like matrix(c(1,2,3,3), nrow=2, byrow=TRUE),
# then plot 1 will go in the upper left, 2 will go in the upper right, and
# 3 will go all the way across the bottom.
#
multiplot <- function(..., plotlist=NULL, file, cols=1, layout=NULL) {
require(grid)
# Make a list from the ... arguments and plotlist
plots <- c(list(...), plotlist)
numPlots = length(plots)
# If layout is NULL, then use 'cols' to determine layout
if (is.null(layout)) {
# Make the panel
# ncol: Number of columns of plots
# nrow: Number of rows needed, calculated from # of cols
layout <- matrix(seq(1, cols * ceiling(numPlots/cols)),
ncol = cols, nrow = ceiling(numPlots/cols))
}
if (numPlots==1) {
print(plots[[1]])
} else {
# Set up the page
grid.newpage()
pushViewport(viewport(layout = grid.layout(nrow(layout), ncol(layout))))
# Make each plot, in the correct location
for (i in 1:numPlots) {
# Get the i,j matrix positions of the regions that contain this subplot
matchidx <- as.data.frame(which(layout == i, arr.ind = TRUE))
print(plots[[i]], vp = viewport(layout.pos.row = matchidx$row,
layout.pos.col = matchidx$col))
}
}
}其中一个创建绘图对象：
p1 <- ggplot(...)
p2 <- ggplot(...)
# etc.然后将它们传递给multiplot
multiplot(p1, p2, ..., cols = n)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/6681145
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