blocks|key|145771|text|您可以简单地使用substring|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|145772|if(fieldName.endsWith(","))
{
++fieldName+=+fieldName.substring(0,fieldName.length()+-+1);
}|code-block|syntax|javascript|145773|确保在以Strings+are+immutable+in+java身份执行substring后重新分配字段|145774|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/java/lang/String.html^0|8|9|0|0|11|9|4|T|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@$9|11|A|12|1|13]]|E|$]]|$1|M|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

You can simply use <code>substring</code>:

<pre><code>if(fieldName.endsWith(","))
{
 fieldName = fieldName.substring(0,fieldName.length() - 1);
}
</code></pre>

Make sure to reassign your field after performing <code>substring</code> as <a href="http://docs.oracle.com/javase/6/docs/api/java/lang/String.html" rel="noreferrer">Strings are immutable in java</a>

blocks|key|363940|text|要获得所需的结果，您可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|363941|fieldName+=+fieldName.trim();
fieldName+=+fieldName.substring(0,fieldName.length()+-+1);|code-block|syntax|javascript|363942|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To get the required result you can do following:

<pre><code>fieldName = fieldName.trim();
fieldName = fieldName.substring(0,fieldName.length() - 1);
</code></pre>

blocks|key|145678|text|fieldName+=+fieldName.substring(0,+string.length()-1)+%2B+"+";|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|145679|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>fieldName = fieldName.substring(0, string.length()-1) + " ";
</code></pre>

blocks|key|363918|text|首先，字符串在java中是不可变的，你必须将替换的结果赋给一个变量。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|363919|fieldName+=+fieldName.replace("watever","");|code-block|syntax|javascript|363920|您还可以使用正则表达式作为一个选项，使用String#replaceAll(regex,+str)；|offset|length|style|CODE|363921|fieldName+=+fieldName.replaceAll(",$","");|363922|entityMap^0|0|0|K|T|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Firstly Strings are immutable in java, you have to assign the result of the replace to a variable. 

<pre><code>fieldName = fieldName.replace("watever","");
</code></pre>

You can use also use regex as an option using <code>String#replaceAll(regex, str)</code>;

<pre><code>fieldName = fieldName.replaceAll(",$","");
</code></pre>

blocks|key|364052|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|364053|s+=+s.replaceAll("[,]$",+"");|code-block|syntax|javascript|364054|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this:

<pre><code>s = s.replaceAll("[,]$", "");
</code></pre>

blocks|key|364182|text|++++if+(fieldName.endsWith(","))+{
++++++++fieldName+=+fieldName.substring(0,+fieldName.length()-1)+%2B+"+";
++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|364183|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> if (fieldName.endsWith(",")) {
 fieldName = fieldName.substring(0, fieldName.length()-1) + " ";
 }
</code></pre>

blocks|key|145968|text|可以使用StringBuilder+replace方法替换最后一个字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|145969|StringBuilder.replace(startPosition,+endPosition,+newString)|offset|length|style|CODE|145970|StringBuilder+builder+=+new+StringBuilder(fieldName);
builder.replace(builder.length()-1,+builder.length(),+"");
builder.toString();|code-block|syntax|javascript|145971|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html#replace(int,%2520int,%2520java.lang.String)^0|0|0|1O|0|1O|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]]|9|@$D|Y|E|Z|1|10]]|A|$]]|$1|H|3|I|5|J|7|11|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

StringBuilder replace method can be used to replace the last character.

<a href="https://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html#replace(int,%20int,%20java.lang.String)" rel="nofollow noreferrer"><code>StringBuilder.replace(startPosition, endPosition, newString)</code></a>

<pre><code>StringBuilder builder = new StringBuilder(fieldName);
builder.replace(builder.length()-1, builder.length(), "");
builder.toString();
</code></pre>

blocks|key|364048|text|您可以使用正则表达式来标识最后一个逗号(，)并将其替换为“”，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|364049|if(fieldName.endsWith(","))
{+++++++++++++++++++++++++++
fieldName+=+fieldName.replace(/,([%5E,]*)$/,"+");
}|code-block|syntax|javascript|364050|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

you can use regular expressions to identify the last comma (,) and replace it with " " as follow:

<pre><code>if(fieldName.endsWith(","))
{ 
fieldName = fieldName.replace(/,([^,]*)$/," ");
}
</code></pre>

blocks|key|364167|text|您可以简单地使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|364168|if(fieldName.endsWith(","))
{
+++StringUtils.chop(fieldName);
}|code-block|syntax|javascript|364169|来自commons-lang|364170|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can simply use :

<pre><code>if(fieldName.endsWith(","))
{
 StringUtils.chop(fieldName);
}
</code></pre>

from commons-lang

blocks|key|364091|text|@Abubakkar+Rangara已经回答了处理问题的简单方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|364092|另一种选择是：|364093|String[]+result+=+null;
if(fieldName.endsWith(","))+{+++++++++++++++++++++++++++
String[]+result+=+fieldName.split(",");
++++for(int+i+=+1;+i+<+result.length+-+1;+i%2B%2B)+{
++++++++result[0]+=+result[0].concat(result[i]);
++++}
}|code-block|syntax|javascript|364094|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Already @Abubakkar Rangara answered easy way to handle your problem

Alternative is :

<pre><code>String[] result = null;
if(fieldName.endsWith(",")) { 
String[] result = fieldName.split(",");
 for(int i = 1; i &lt; result.length - 1; i++) {
 result[0] = result[0].concat(result[i]);
 }
}
</code></pre>

blocks|key|364016|text|修改代码为fieldName+=+fieldName.replace("，“，”")；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|364017|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Modify the code as fieldName = fieldName.replace("," , " ");

I have a string:

<pre><code>String fieldName = "A=2,B=3 and C=3,";
</code></pre>

Now I want to replace last <code>,</code> with space.

I have used: 

<pre><code>if (fieldName.endsWith(",")) {
 fieldName.replace(",", " ");
 fieldName = fieldName.replace((char) (fieldName.length() - 1), 'r');
}

System.out.println("fieldName = " + fieldName);
</code></pre>

But still I am getting the same old string. How I can get this output instead?

<pre><code>fieldName = A=2,B=3 and C=3
</code></pre>

Replacing last character in a String with java

我有一个字符串：String fieldName = "A=2,B=3 and C=3,";现在我想用空格替换上一个,。我已经使用了：if (fieldName.endsWith(",")) {    fieldName.replace(",", " ");    fieldName = fieldName.replace((char) (fieldName.length() - 1), 'r')

问用java替换字符串中的最后一个字符
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