Spring Security with WebSockets -Formated403
Spring Security with WebSockets -Formated403
提问于 2015-06-02 20:06:23
我已经在Spring中实现了WebSocket。一切都很好，但最近我决定实现Spring Security。
我的MessageBroker看起来像这样：
@Configuration
@EnableWebSocketMessageBroker
@Component("messageBroker")
public class MessageBroker implements WebSocketMessageBrokerConfigurer {
@Override
public void registerStompEndpoints(StompEndpointRegistry stompEndpointRegistry) {
stompEndpointRegistry.addEndpoint("/graphs").withSockJS();
}
@Override
public void configureMessageBroker(MessageBrokerRegistry messageBrokerRegistry) {
}
@Override
public void configureClientInboundChannel(ChannelRegistration channelRegistration) {
}
@Override
public void configureClientOutboundChannel(ChannelRegistration channelRegistration) {
}
@Override
public boolean configureMessageConverters(List<MessageConverter> messageConverters) {
messageConverters.add(new MappingJackson2MessageConverter());
return false;
}
}我的JS客户端看起来像这样：
var socket = new SockJS('/server/graphs');
var client = Stomp.over(socket);
client.connect({}, function (frame) {
client.subscribe("/data", function (message) {
console.log('GET MESSAGE :' + message.body);
var test = JSON.parse(message.body);
var point = [ (new Date()).getTime(), parseInt(25) ];
var shift = randomData.data.length > 60;
randomData.addPoint(point, true, shift);
});
});Spring安全配置：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security.xsd">
<security:http auto-config='true' use-expressions="true" disable-url-rewriting="true">
<security:intercept-url pattern="/login/**" access="isAnonymous()"/>
<security:intercept-url pattern="/index/**" access="isAuthenticated()" />
<security:intercept-url pattern="/volumegraph/**" access="isAuthenticated()" />
<security:intercept-url pattern="/graphs/**" access="permitAll()" />
<security:intercept-url pattern="/graphs/**/**" access="permitAll()" />
<security:form-login login-page="/" login-processing-url="/" authentication-failure-url="/" always-use-default-target="true"/>
<security:csrf/>
<security:logout logout-success-url="/login"/>
<security:headers>
<security:frame-options></security:frame-options>
</security:headers>
</security:http>
<security:authentication-manager>
<security:authentication-provider>
<security:user-service>
<security:user name="user" password="password" authorities="ROLE_USER"/>
</security:user-service>
</security:authentication-provider>
</security:authentication-manager>
</beans>通过我的JS客户端订阅后，我收到：
Opening Web Socket...
sockjs.js:1213 WebSocket connection to 'ws://localhost:8080/server/graphs/651/kyzdihld/websocket' failed: Error during WebSocket handshake: Unexpected response code: 404
sockjs.js:807 POST http://localhost:8080/server/graphs/651/zx7zdre7/xhr_streaming 403 (Forbidden)AbstractXHRObject._start @ sockjs.js:807(anonymous function) @ sockjs.js:834
sockjs.js:807 POST http://localhost:8080/server/graphs/651/o6eg5ikc/xhr 403 (Forbidden)AbstractXHRObject._start @ sockjs.js:807(anonymous function) @ sockjs.js:834
stomp.js:122 Whoops! Lost connection to undefined因此，我决定在Security Config中添加以下代码：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security.xsd">
<security:websocket-message-broker>
<!--<security:intercept-message pattern="/graphs/**" access="permitAll()"/>-->
<security:intercept-message pattern="/**" access="permitAll()"/>
<security:intercept-message type="SUBSCRIBE" access="permitAll()"/>
<security:intercept-message type="CONNECT" access="permitAll()"/>
</security:websocket-message-broker>
</beans>但在那之后，我收到了这样的错误：
NoSuchBeanDefinitionException: No bean named 'springSecurityMessagePathMatcher' is defined我不知道如何定义这样的bean，所以我在下面创建了这个类：
@Configuration
public class WebSocketSecurityConfig extends AbstractSecurityWebSocketMessageBrokerConfigurer {
protected void configureInbound(MessageSecurityMetadataSourceRegistry messages) {
messages.simpDestMatchers("/graphs/*").permitAll();
messages.simpDestMatchers("/**").permitAll();
}
}但是在编译过程中，我收到了这样的错误：
java: cannot access org.springframework.beans.factory.SmartInitializingSingleton
class file for org.springframework.beans.factory.SmartInitializingSingleton not found我真的不知道如何解决这个问题:(我必须补充说，我使用的是Spring Core 4.0.1.RELEASE和Spring Messaging 4.0.1.RELEASE。所有与Spring Security相关的库都是4.0.1.RELEASE版本。
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原文链接：
https://stackoverflow.com/questions/30595631
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