blocks|key|723677|text|您正在寻找模运算符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|723678|a+%25+b|code-block|syntax|javascript|723679|例如：|723680|>>>+26+%25+7
5|723681|当然，也许他们想让你自己实现它，这也不会太难。|723682|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

you are looking for the modulo operator:
<pre><code>a % b
</code></pre>
for example:
<pre><code>&gt;&gt;&gt; 26 % 7
5
</code></pre>
Of course, maybe they wanted you to implement it yourself, which wouldn't be too difficult either.

blocks|key|723847|text|除法的其余部分可以使用运算符%25来发现|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|723848|>>>+26%257
5|code-block|syntax|javascript|723849|如果您同时需要商和模数，可以使用内置的divmod函数：|723850|>>>+seconds=+137
>>>+minutes,+seconds=+divmod(seconds,+60)|723851|entityMap^0|E|1|0|0|J|6|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

The remainder of a division can be discovered using the operator <code>%</code>:

<pre><code>&gt;&gt;&gt; 26%7
5
</code></pre>

In case you need both the quotient and the modulo, there's the builtin <code>divmod</code> function:

<pre><code>&gt;&gt;&gt; seconds= 137
&gt;&gt;&gt; minutes, seconds= divmod(seconds, 60)
</code></pre>

blocks|key|939996|text|26+%25+7+(您将获得余数)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|939997|26+/+7+(你将得到除数，可以是浮点值)|939998|26+//+7+(你将得到除数，只有整数值)|939999|entityMap^0|0|6|0|0|6|0|0|7|0^^$0|@$1|2|3|4|5|6|7|L|8|@$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|J|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|K|$]]

<code>26 % 7</code> (you will get remainder)
<code>26 / 7</code> (you will get divisor, can be float value)
<code>26 // 7</code> (you will get divisor, only integer value)

blocks|key|724045|text|如果你想在一行代码中得到商和余数(更一般的用法)，使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|724046|quotient,+remainder+=+divmod(dividend,+divisor)
#or
divmod(26,+7)|code-block|syntax|javascript|724047|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you want to get quotient and remainder in one line of code (more general usecase), use:

<pre><code>quotient, remainder = divmod(dividend, divisor)
#or
divmod(26, 7)
</code></pre>

blocks|key|939949|text|如果您想要避免模数，您还可以使用四种基本操作的组合:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|939950|26+-+(26+//+7+*+7)+=+5|code-block|syntax|javascript|939951|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you want to avoid modulo, you can also use a combination of the four basic operations :)

<pre><code>26 - (26 // 7 * 7) = 5
</code></pre>

blocks|key|723742|text|除法时使用%25而不是/。这将为您返回剩余部分。所以在你的情况下|type|unstyled|depth|inlineStyleRanges|entityRanges|data|723743|26+%25+7+=+5|code-block|syntax|javascript|723744|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use the % instead of the / when you divide. This will return the remainder for you. So in your case

<pre><code>26 % 7 = 5
</code></pre>

blocks|key|940089|text|我们可以使用模运算符(%25)来解决这个问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|940090|26+%257=+5；|940091|但是26+/7=3，因为它会给出商，但%25运算符会给出余数。|940092|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

We can solve this by using modulus operator (%)

26 % 7 = 5;

but 
26 / 7 = 3 because it will give quotient but % operator will give remainder.

blocks|key|723809|text|Modulo将是正确的答案，但如果您手动操作，这应该是可行的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|723810|num+=+input("Enter+a+number:+")
div+=+input("Enter+a+divisor:+")

while+num+>=+div:
++++num+-=+div
print+num|code-block|syntax|javascript|723811|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Modulo would be the correct answer, but if you're doing it manually this should work.

<pre><code>num = input("Enter a number: ")
div = input("Enter a divisor: ")

while num &gt;= div:
 num -= div
print num
</code></pre>

blocks|key|940175|text|可以使用模运算符Example找到余数|type|unstyled|depth|inlineStyleRanges|entityRanges|data|940176|a=14
b=10
print(a%25b)|code-block|syntax|javascript|940177|它将打印4|940178|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can find remainder using modulo operator
Example
<pre><code>a=14
b=10
print(a%b)
</code></pre>
It will print 4

blocks|key|940026|text|如果你想要除法问题的剩余部分，只需使用实际的剩余部分规则，就像在数学中一样。当然，这不会给出十进制输出。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|940027|valone+=+8
valtwo+=+3
x+=+valone+/+valtwo
r+=+valone+-+(valtwo+*+x)
print+"Answer:+%25s+with+a+remainder+of+%25s"+%25+(x,+r)|code-block|syntax|javascript|940028|如果你想以计算器的格式实现，只需用valone+=+int(input("Value+One"))替换valone+=+8即可。对valtwo+=+3执行相同的操作，但变量明显不同。|offset|length|style|CODE|940029|entityMap^0|0|0|H|W|1F|A|1T|A|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|N|$]]

If you want the remainder of your division problem, just use the actual remainder rules, just like in mathematics. Granted this won't give you a decimal output.

<pre><code>valone = 8
valtwo = 3
x = valone / valtwo
r = valone - (valtwo * x)
print "Answer: %s with a remainder of %s" % (x, r)
</code></pre>

If you want to make this in a calculator format, just substitute <code>valone = 8</code>
with <code>valone = int(input("Value One"))</code>. Do the same with <code>valtwo = 3</code>, but different vairables obviously.

blocks|key|724174|text|下面是Python中余数的整数版本，它应该会给出与C的"%25“运算符相同的结果：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|724175|def+remainder(n,+d):
++++return+(-1+if+n+<+0+else+1)+*+(abs(n)+%25+abs(d))|code-block|syntax|javascript|724176|预期结果：|724177|remainder(123,+10)+++==++3
remainder(123,+-10)++==++3
remainder(-123,+10)++==+-3
remainder(-123,+-10)+==+-3|724178|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Here's an integer version of remainder in Python, which should give the same results as C's &quot;%&quot; operator:
<pre><code>def remainder(n, d):
 return (-1 if n &lt; 0 else 1) * (abs(n) % abs(d))
</code></pre>
Expected results:
<pre><code>remainder(123, 10) == 3
remainder(123, -10) == 3
remainder(-123, 10) == -3
remainder(-123, -10) == -3
</code></pre>

blocks|key|940247|text|您可以定义一个函数并使用2个值调用它，如rem(number1，number2)，返回数字1%25数字2，然后创建一个while并将其设置为true，然后打印出函数的两个输入，保持数字1和2，然后打印(rem(number1，number2)+)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|940248|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

you can define a function and call it remainder with 2 values like rem(number1,number2) that returns number1%number2
then create a while and set it to true then print out two inputs for your function holding number 1 and 2 then print(rem(number1,number2)

How could I go about finding the division remainder of a number in Python?

For example: 
If the number is 26 and divided number is 7, then the division remainder is 5. 
(since 7+7+7=21 and 26-21=5.)

Find the division remainder of a number

Python

如何在Python中找到一个数的除法余数？例如：如果数字是26，除数是7，那么除法余数是5。(由于7+7+7=21和26-21=5。)

问求一个数的除法余数
EN

回答 12

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