我使用的是data.table 1.9.3,也许我错了,但我不记得之前会出现以下情况。
我构建了2个data.tables,dta和dtb
> dta
idx vala fdx
1: 1 2 a
2: 2 4 a
3: 3 6 b
> dtb
idx valb
1: 1 3
2: 4 6
> dput(x = dta)
structure(list(idx = c(1, 2, 3), vala = c(2, 4, 6), fdx = c("a",
"a", "b")), .Names = c("idx", "vala", "fdx"), row.names = c(NA,
-3L), class = c("data.table", "data.frame"), .internal.selfref =
<pointer: 0x0000000000110788>, sorted = "idx")
> dput(x = dtb)
structure(list(idx = c(1, 4), valb = c(3, 6)), .Names = c("idx",
"valb"), row.names = c(NA, -2L), class = c("data.table", "data.frame"
), .internal.selfref = <pointer: 0x0000000000110788>, sorted = "idx")
在这两种情况下,关键字都是idx。
当然,下面的方法是可行的
> dta[dtb, sum(valb)]
[1] 9
然而,这不是
> dta[dtb, sum(valb), by = fdx]
Error in `[.data.table`(dta, dtb, sum(valb), by = fdx) :
object 'valb' not found
但这确实是
> dta[dtb][, sum(valb), by = fdx]
fdx V1
1: a 3
2: NA 6
如果我们看到中间步骤
> dta[dtb]
idx vala fdx valb
1: 1 2 a 3
2: 4 NA NA 6
我早就料到了
dta[dtb, sum(valb), by = fdx] == dta[dtb][, sum(valb), by = fdx]
我哪里错了?
https://stackoverflow.com/questions/24746882
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