blocks|key|285390|text|别忘了|type|unstyled|depth|inlineStyleRanges|entityRanges|data|285391|285392|+context.startService(..);|blockquote|offset|length|style|CODE|285393|285394|entityMap^0|0|0|1|P|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|N|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|O|8|@$F|P|G|Q|H|I]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|L|$]]

Don't forget 

<blockquote>
 <code>context.startService(..);</code>
</blockquote>

blocks|key|3213205|text|应该是这样的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3213206|Intent+i+=+new+Intent(context,+YourServiceName.class);
context.startService(i);|code-block|syntax|javascript|3213207|请确保将服务添加到manifest.xml|3213208|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

should be like that:

<pre><code>Intent i = new Intent(context, YourServiceName.class);
context.startService(i);
</code></pre>

be sure to add the service to manifest.xml

blocks|key|288802|text|使用BroadcastReceiver的onReceive方法中的context启动服务组件。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|288803|@Override
public+void+onReceive(Context+context,+Intent+intent)+{
++++++Intent+serviceIntent+=+new+Intent(context,+YourService.class);
++++++context.startService(serviceIntent);
}|code-block|syntax|javascript|288804|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.android.com/reference/android/content/BroadcastReceiver.html^0|K|9|X|7|2|H|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

use the <code>context</code> from the <code>onReceive</code> method of your <a href="https://developer.android.com/reference/android/content/BroadcastReceiver.html" rel="noreferrer">BroadcastReceiver</a> to start your service component.

<pre><code>@Override
public void onReceive(Context context, Intent intent) {
 Intent serviceIntent = new Intent(context, YourService.class);
 context.startService(serviceIntent);
}
</code></pre>

blocks|key|3213217|text|最佳实践：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3213218|在创建意图时，尤其是从BroadcastReceiver开始时，不要将作为上下文。以下面的context.getApplicationContext()为例|offset|length|style|CODE|3213219|+Intent+intent+=+new+Intent(context.getApplicationContext(),+classNAME);
context.getApplicationContext().startService(intent);|code-block|syntax|javascript|3213220|entityMap^0|0|B|H|19|V|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]|$D|S|E|T|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|U|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

Best Practice :

While creating an intent especially while starting from <code>BroadcastReceiver</code>, dont take this as context.
Take <code>context.getApplicationContext()</code> like below

<pre><code> Intent intent = new Intent(context.getApplicationContext(), classNAME);
context.getApplicationContext().startService(intent);
</code></pre>

blocks|key|2999934|text|+try+{
++++++++Intent+intentService+=+new+Intent(context,+MyNewIntentService.class);
++++++++if+(Build.VERSION.SDK_INT+>=+Build.VERSION_CODES.O)+{
++++++++++++context.startForegroundService(intentService+);
++++++++}+else+{
++++++++++++context.startService(intentService+);
++++++++}
++++}+catch+(Exception+e)+{
++++++++e.printStackTrace();
++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2999935|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> try {
 Intent intentService = new Intent(context, MyNewIntentService.class);
 if (Build.VERSION.SDK_INT &gt;= Build.VERSION_CODES.O) {
 context.startForegroundService(intentService );
 } else {
 context.startService(intentService );
 }
 } catch (Exception e) {
 e.printStackTrace();
 }
</code></pre>

blocks|key|2999928|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2999929|因为接收方的onReceive(Context，Intent)方法在主线程上运行，所以它应该快速执行和返回。如果您需要执行长时间运行的工作，请注意派生线程或启动后台服务，因为系统可能会在onReceive()返回后终止整个进程。有关更多信息，请参阅对流程状态的影响以执行长时间运行的工作，我们建议：|blockquote|2999930|2999931|在接收方的onReceive()方法中调用goAsync()并将BroadcastReceiver.PendingResult传递给后台线程。这使广播在从onReceive()返回后保持活动状态。然而，即使使用这种方法，系统也希望您很快完成广播(不到10秒)。它确实允许您将工作转移到另一个线程，以避免主线程出现故障。使用JobScheduler+developer.android.com计划作业|offset|length|2999932|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.android.com/guide/components/broadcasts#effects-on-process-state^0|0|0|0|4U|L|0|0^^$0|@$1|2|3|-4|4|5|6|Q|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|R|7|@]|8|@]|9|$]]|$1|D|3|-4|4|5|6|S|7|@]|8|@]|9|$]]|$1|E|3|F|4|5|6|T|7|@]|8|@$G|U|H|V|1|W]]|9|$]]|$1|I|3|-4|4|5|6|X|7|@]|8|@]|9|$]]]|J|$K|$4|L|M|N|9|$O|P]]]]

<blockquote>
 Because a receiver's onReceive(Context, Intent) method runs on the main thread, it should execute and return quickly. If you need to perform long running work, be careful about spawning threads or starting background services because the system can kill the entire process after onReceive() returns. For more information, see Effect on process state To perform long running work, we recommend:
 
 Calling goAsync() in your receiver's onReceive() method and passing the BroadcastReceiver.PendingResult to a background thread. This keeps the broadcast active after returning from onReceive(). However, even with this approach the system expects you to finish with the broadcast very quickly (under 10 seconds). It does allow you to move work to another thread to avoid glitching the main thread.
 Scheduling a job with the JobScheduler
 <a href="https://developer.android.com/guide/components/broadcasts#effects-on-process-state" rel="nofollow noreferrer">developer.android.com</a>
</blockquote>

blocks|key|283270|text|最好使用ContextCompat：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|283271|Intent+serviceIntent+=+new+Intent(context,+ForegroundService.class);
ContextCompat.startForegroundService(context,+serviceIntent);|code-block|syntax|javascript|283272|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

It's better to use ContextCompat:
<pre><code>Intent serviceIntent = new Intent(context, ForegroundService.class);
ContextCompat.startForegroundService(context, serviceIntent);
</code></pre>

I have a <code>Service</code> and <code>BroadcastReceiver</code> in my application, but how do I launch the service directly from the <code>BroadcastReceiver</code>? Using

<pre><code>startService(new Intent(this, MyService.class));
</code></pre>

does not work in a <code>BroadcastReceiver</code>, any ideas?

EDIT:

<blockquote>
 context.startService(..);
</blockquote>

works, I forgot the context part

Starting Service from BroadcastReceiver

我的应用程序中有一个Service和BroadcastReceiver，但如何从BroadcastReceiver直接启动该服务？使用startService(new Intent(this, MyService.class));不能在BroadcastReceiver中工作，有什么想法吗？编辑： context.startService(..)；工作时，我忘记了上下文部分

问从BroadcastReceiver启动服务
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