PHP read_exif_data和调整方向?

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如果方向关闭,我正在使用以下代码来旋转上传的jpeg图像。我只在从iPhone和Android上传的图片时遇到问题。

if(move_uploaded_file($_FILES['photo']['tmp_name'], $upload_path . $newfilename)){
            chmod($upload_path . $newfilename, 0755);
            $exif = exif_read_data($upload_path . $newfilename);
            $ort = $exif['IFD0']['Orientation'];
            switch($ort)
            {

                case 3: // 180 rotate left
                    $image->imagerotate($upload_path . $newfilename, 180, -1);
                    break;


                case 6: // 90 rotate right
                    $image->imagerotate($upload_path . $newfilename, -90, -1);
                    break;

                case 8:    // 90 rotate left
                    $image->imagerotate($upload_path . $newfilename, 90, -1);
                    break;
            }
            imagejpeg($image, $upload_path . $newfilename, 100);
            $success_message = 'Photo Successfully Uploaded';
        }else{
            $error_count++;
            $error_message = 'Error: Upload Unsuccessful<br />Please Try Again';
        }

我在阅读JPEG格式的EXIF数据的方式做错了什么?它不会像预期的那样旋转图像。

这是我运行var_dump($ exif)时发生的情况;

array(41) {
    ["FileName"]=> string(36) "126e7c0efcac2b76b3320e6187d03cfd.JPG"
    ["FileDateTime"]=> int(1316545667)
    ["FileSize"]=> int(1312472)
    ["FileType"]=> int(2)
    ["MimeType"]=> string(10) "image/jpeg"
    ["SectionsFound"]=> string(30) "ANY_TAG, IFD0, THUMBNAIL, EXIF"
    ["COMPUTED"]=> array(8) {
        ["html"]=> string(26) "width="2048" height="1536""
        ["Height"]=> int(1536)
        ["Width"]=> int(2048)
        ["IsColor"]=> int(1)
        ["ByteOrderMotorola"]=> int(1)
        ["ApertureFNumber"]=> string(5) "f/2.8"
        ["Thumbnail.FileType"]=> int(2)
        ["Thumbnail.MimeType"]=> string(10) "image/jpeg" }
        ["Make"]=> string(5) "Apple"
        ["Model"]=> string(10) "iPhone 3GS"
        ["Orientation"]=> int(6)
        ["XResolution"]=> string(4) "72/1"
            ["YResolution"]=> string(4) "72/1" ["ResolutionUnit"]=> int(2) ["Software"]=> string(5) "4.3.5" ["DateTime"]=> string(19) "2011:09:16 21:18:46" ["YCbCrPositioning"]=> int(1) ["Exif_IFD_Pointer"]=> int(194) ["THUMBNAIL"]=> array(6) { ["Compression"]=> int(6) ["XResolution"]=> string(4) "72/1" ["YResolution"]=> string(4) "72/1" ["ResolutionUnit"]=> int(2) ["JPEGInterchangeFormat"]=> int(658) ["JPEGInterchangeFormatLength"]=> int(8231) } ["ExposureTime"]=> string(4) "1/15" ["FNumber"]=> string(4) "14/5" ["ExposureProgram"]=> int(2) ["ISOSpeedRatings"]=> int(200) ["ExifVersion"]=> string(4) "0221" ["DateTimeOriginal"]=> string(19) "2011:09:16 21:18:46" ["DateTimeDigitized"]=> string(19) "2011:09:16 21:18:46" ["ComponentsConfiguration"]=> string(4) "" ["ShutterSpeedValue"]=> string(8) "3711/949" ["ApertureValue"]=> string(9) "4281/1441" ["MeteringMode"]=> int(1) ["Flash"]=> int(32) ["FocalLength"]=> string(5) "77/20" ["SubjectLocation"]=> array(4) { [0]=> int(1023) [1]=> int(767) [2]=> int(614) [3]=> int(614) } ["FlashPixVersion"]=> string(4) "0100" ["ColorSpace"]=> int(1) ["ExifImageWidth"]=> int(2048) ["ExifImageLength"]=> int(1536) ["SensingMethod"]=> int(2) ["ExposureMode"]=> int(0) ["WhiteBalance"]=> int(0) ["SceneCaptureType"]=> int(0) ["Sharpness"]=> int(1) }
提问于
用户回答回答于

imagerotate的文档引用的第一个参数的类型与你所使用的不同:

一个图像资源,由图像创建函数之一返回,如imagecreatetruecolor()。

这是一个使用这个函数的小例子:

function resample($jpgFile, $thumbFile, $width, $orientation) {
    // Get new dimensions
    list($width_orig, $height_orig) = getimagesize($jpgFile);
    $height = (int) (($width / $width_orig) * $height_orig);
    // Resample
    $image_p = imagecreatetruecolor($width, $height);
    $image   = imagecreatefromjpeg($jpgFile);
    imagecopyresampled($image_p, $image, 0, 0, 0, 0, $width, $height, $width_orig, $height_orig);
    // Fix Orientation
    switch($orientation) {
        case 3:
            $image_p = imagerotate($image_p, 180, 0);
            break;
        case 6:
            $image_p = imagerotate($image_p, -90, 0);
            break;
        case 8:
            $image_p = imagerotate($image_p, 90, 0);
            break;
    }
    // Output
    imagejpeg($image_p, $thumbFile, 90);
}
用户回答回答于

基于Daniel的代码,我编写了一个函数,可以根据需要简单地旋转图像,而无需重新采样。

GD

function image_fix_orientation(&$image, $filename) {
    $exif = exif_read_data($filename);

    if (!empty($exif['Orientation'])) {
        switch ($exif['Orientation']) {
            case 3:
                $image = imagerotate($image, 180, 0);
                break;

            case 6:
                $image = imagerotate($image, -90, 0);
                break;

            case 8:
                $image = imagerotate($image, 90, 0);
                break;
        }
    }
}

一行版本(GD)

function image_fix_orientation(&$image, $filename) {
    $image = imagerotate($image, array_values([0, 0, 0, 180, 0, 0, -90, 0, 90])[@exif_read_data($filename)['Orientation'] ?: 0], 0);
}

ImageMagick的

function image_fix_orientation($image) {
    if (method_exists($image, 'getImageProperty')) {
        $orientation = $image->getImageProperty('exif:Orientation');
    } else {
        $filename = $image->getImageFilename();

        if (empty($filename)) {
            $filename = 'data://image/jpeg;base64,' . base64_encode($image->getImageBlob());
        }

        $exif = exif_read_data($filename);
        $orientation = isset($exif['Orientation']) ? $exif['Orientation'] : null;
    }

    if (!empty($orientation)) {
        switch ($orientation) {
            case 3:
                $image->rotateImage('#000000', 180);
                break;

            case 6:
                $image->rotateImage('#000000', 90);
                break;

            case 8:
                $image->rotateImage('#000000', -90);
                break;
        }
    }
}

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