blocks|key|537585|text|print(',+'.join(names))|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|537586|听起来，这只是获取列表中的所有元素并使用',+'将它们连接起来。|unstyled|offset|length|style|CODE|537587|entityMap^0|0|K|4|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>print(', '.join(names))
</code></pre>

This, like it sounds, just takes all the elements of the list and joins them with <code>', '</code>.

blocks|key|537682|text|下面是一个简单的例子。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|537683|names+=+["Sam",+"Peter",+"James",+"Julian",+"Ann"]
print(*names,+sep=",+")|code-block|syntax|javascript|537684|星号解压列表并返回列表中的每个元素。|537685|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Here is a simple one. 

<pre><code>names = ["Sam", "Peter", "James", "Julian", "Ann"]
print(*names, sep=", ")
</code></pre>

the star unpacks the list and return every element in the list.

blocks|key|537613|text|一般解决方案，适用于非字符串数组：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|537614|>>>+print+str(names)[1:-1]
'Sam',+'Peter',+'James',+'Julian',+'Ann'|code-block|syntax|javascript|537615|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

General solution, works on arrays of non-strings:

<pre><code>&gt;&gt;&gt; print str(names)[1:-1]
'Sam', 'Peter', 'James', 'Julian', 'Ann'
</code></pre>

blocks|key|537745|text|有两个答案，第一个是使用'sep‘设置|type|unstyled|depth|inlineStyleRanges|entityRanges|data|537746|>>>+print(*names,+sep+=+',+')|code-block|syntax|javascript|537747|另一个在下面|537748|>>>+print(',+'.join(names))|537749|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

There are two answers , First is use 'sep' setting

<pre><code>&gt;&gt;&gt; print(*names, sep = ', ')
</code></pre>

The other is below

<pre><code>&gt;&gt;&gt; print(', '.join(names))
</code></pre>

blocks|key|537589|text|这就是你所需要的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|537590|",+".join(names)|code-block|syntax|javascript|537591|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is what you need

<pre><code>", ".join(names)
</code></pre>

blocks|key|320956|text|只有当列表中的所有项都是字符串时，','.join(list)才会起作用。如果您希望将数字列表转换为逗号分隔的字符串。例如将a+=+[1,+2,+3,+4]添加到'1,2,3,4'中，那么您可以|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|320957|str(a)[1:-1]+#+'1,+2,+3,+4'|code-block|syntax|javascript|320958|或|320959|str(a).lstrip('[').rstrip(']')+#+'1,+2,+3,+4'|320960|尽管这不会删除任何嵌套列表。|320961|将其转换回列表|320962|a+=+'1,2,3,4'
import+ast
ast.literal_eval('['%2Ba%2B']')
#[1,+2,+3,+4]|320963|entityMap^0|H|E|1Q|G|29|9|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|14|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|16|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|17|8|@]|D|@]|E|$]]|$1|S|3|T|5|H|7|18|8|@]|D|@]|E|$I|J]]|$1|U|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|V|$]]

<code>','.join(list)</code> will work only if all the items in the list are strings. If you are looking to convert a list of numbers to a comma separated string. such as <code>a = [1, 2, 3, 4]</code> into <code>'1,2,3,4'</code> then you can either

<pre><code>str(a)[1:-1] # '1, 2, 3, 4'
</code></pre>

or

<pre><code>str(a).lstrip('[').rstrip(']') # '1, 2, 3, 4'
</code></pre>

although this won't remove any nested list.

To convert it back to a list

<pre><code>a = '1,2,3,4'
import ast
ast.literal_eval('['+a+']')
#[1, 2, 3, 4]
</code></pre>

blocks|key|321156|text|尝试在列表的名称with+print语句前使用星号：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|321157|names+=+["Sam",+"Peter",+"James",+"Julian",+"Ann"]++
print(*names)|code-block|syntax|javascript|321158|输出：|321159|Sam+Peter+James+Julian+Ann|321160|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

try to use an asterisk before list's name with print statement:
<pre><code>names = [&quot;Sam&quot;, &quot;Peter&quot;, &quot;James&quot;, &quot;Julian&quot;, &quot;Ann&quot;] 
print(*names)
</code></pre>
output:
<pre><code>Sam Peter James Julian Ann
</code></pre>

blocks|key|320773|text|您需要遍历列表并使用end="+"将其保持在一行上|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|320774|names+=+["Sam",+"Peter",+"James",+"Julian",+"Ann"]
++++index=0
++++for+name+in+names:
++++++++print(names[index],+end=",+")
++++++++index+%2B=+1|code-block|syntax|javascript|320775|entityMap^0|A|7|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You need to loop through the list and use <code>end=" "</code>to keep it on one line

<pre><code>names = ["Sam", "Peter", "James", "Julian", "Ann"]
 index=0
 for name in names:
 print(names[index], end=", ")
 index += 1
</code></pre>

blocks|key|537964|text|对于整数类型的数组，我们需要先将其改为字符串类型，然后使用join函数来获得干净的输出，而不需要使用括号。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|537965|++++arr+=+[1,+2,+3,+4,+5]++++
++++print(',+'.join(map(str,+arr)))|code-block|syntax|javascript|537966|输出-+1、2、3、4、5|537967|对于string类型的数组，我们需要直接使用join函数来获得干净的输出，而不需要使用括号。|537968|++++arr+=+["Ram",+"Mohan",+"Shyam",+"Dilip",+"Sohan"]
++++print(',+'.join(arr)|537969|输出-+Ram，Mohan，Shyam，Dilip，Sohan|537970|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

For array of integer type, we need to change it to string type first and than use join function to get clean output without brackets.
<pre><code> arr = [1, 2, 3, 4, 5] 
 print(', '.join(map(str, arr)))
</code></pre>
OUTPUT - 1, 2, 3, 4, 5
For array of string type, we need to use join function directly to get clean output without brackets.
<pre><code> arr = [&quot;Ram&quot;, &quot;Mohan&quot;, &quot;Shyam&quot;, &quot;Dilip&quot;, &quot;Sohan&quot;]
 print(', '.join(arr)
</code></pre>
OUTPUT - Ram, Mohan, Shyam, Dilip, Sohan

blocks|key|537881|text|下面的函数将接受一个列表，并返回一个列表项目的字符串。然后可以将其用于日志记录或打印目的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|537882|def+listToString(inList):
++++outString+=+''
++++if+len(inList)==1:
++++++++outString+=+outString%2Bstr(inList[0])
++++if+len(inList)>1:
++++++++outString+=+outString%2Bstr(inList[0])
++++++++for+items+in+inList[1:]:
++++++++++++outString+=+outString%2B',+'%2Bstr(items)
++++return+outString|code-block|syntax|javascript|537883|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The following function will take in a list and return a string of the lists' items.
This can then be used for logging or printing purposes.

<pre><code>def listToString(inList):
 outString = ''
 if len(inList)==1:
 outString = outString+str(inList[0])
 if len(inList)&gt;1:
 outString = outString+str(inList[0])
 for items in inList[1:]:
 outString = outString+', '+str(items)
 return outString
</code></pre>

I have a list in Python
e.g.

<pre><code>names = ["Sam", "Peter", "James", "Julian", "Ann"]
</code></pre>

I want to print the array in a single line without the normal " []

<pre><code>names = ["Sam", "Peter", "James", "Julian", "Ann"]
print (names)
</code></pre>

Will give the output as;

<pre><code>["Sam", "Peter", "James", "Julian", "Ann"]
</code></pre>

That is not the format I want instead I want it to be like this;

<pre><code>Sam, Peter, James, Julian, Ann
</code></pre>

Note: It must be in a single row.

Print list without brackets in a single row

Python

我有一个Python的列表。names = ["Sam", "Peter", "James", "Julian", "Ann"]我想在一行中打印数组，而不是正常的“[]”names = ["Sam", "Peter", "James", "Julian", "Ann"]print (names)将给出的输出为；["Sam", "Peter", "James", "Julian", "Ann"]这不

问打印单行中不带括号的列表
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