Jackson JSON和Hibernate JPA问题的无限递归
Jackson JSON和Hibernate JPA问题的无限递归
提问于 2010-07-24 22:00:35
在尝试将具有双向关联的JPA对象转换为JSON时，我总是得到
org.codehaus.jackson.map.JsonMappingException: Infinite recursion (StackOverflowError)我所找到的是this thread，它基本上以建议避免双向关联作为结束。有没有人有解决这个spring bug的办法？
-编辑2010-07-24 16:26:22
代码片段：
业务对象1：
@Entity
@Table(name = "ta_trainee", uniqueConstraints = {@UniqueConstraint(columnNames = {"id"})})
public class Trainee extends BusinessObject {
@Id
@GeneratedValue(strategy = GenerationType.TABLE)
@Column(name = "id", nullable = false)
private Integer id;
@Column(name = "name", nullable = true)
private String name;
@Column(name = "surname", nullable = true)
private String surname;
@OneToMany(mappedBy = "trainee", fetch = FetchType.EAGER, cascade = CascadeType.ALL)
@Column(nullable = true)
private Set<BodyStat> bodyStats;
@OneToMany(mappedBy = "trainee", fetch = FetchType.EAGER, cascade = CascadeType.ALL)
@Column(nullable = true)
private Set<Training> trainings;
@OneToMany(mappedBy = "trainee", fetch = FetchType.EAGER, cascade = CascadeType.ALL)
@Column(nullable = true)
private Set<ExerciseType> exerciseTypes;
public Trainee() {
super();
}
//... getters/setters ...
}业务对象2：
import javax.persistence.*;
import java.util.Date;
@Entity
@Table(name = "ta_bodystat", uniqueConstraints = {@UniqueConstraint(columnNames = {"id"})})
public class BodyStat extends BusinessObject {
@Id
@GeneratedValue(strategy = GenerationType.TABLE)
@Column(name = "id", nullable = false)
private Integer id;
@Column(name = "height", nullable = true)
private Float height;
@Column(name = "measuretime", nullable = false)
@Temporal(TemporalType.TIMESTAMP)
private Date measureTime;
@ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
@JoinColumn(name="trainee_fk")
private Trainee trainee;
}控制器：
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import javax.servlet.http.HttpServletResponse;
import javax.validation.ConstraintViolation;
import java.util.*;
import java.util.concurrent.ConcurrentHashMap;
@Controller
@RequestMapping(value = "/trainees")
public class TraineesController {
final Logger logger = LoggerFactory.getLogger(TraineesController.class);
private Map<Long, Trainee> trainees = new ConcurrentHashMap<Long, Trainee>();
@Autowired
private ITraineeDAO traineeDAO;
/**
* Return json repres. of all trainees
*/
@RequestMapping(value = "/getAllTrainees", method = RequestMethod.GET)
@ResponseBody
public Collection getAllTrainees() {
Collection allTrainees = this.traineeDAO.getAll();
this.logger.debug("A total of " + allTrainees.size() + " trainees was read from db");
return allTrainees;
}
}JPA-实习生DAO的实现：
@Repository
@Transactional
public class TraineeDAO implements ITraineeDAO {
@PersistenceContext
private EntityManager em;
@Transactional
public Trainee save(Trainee trainee) {
em.persist(trainee);
return trainee;
}
@Transactional(readOnly = true)
public Collection getAll() {
return (Collection) em.createQuery("SELECT t FROM Trainee t").getResultList();
}
}persistence.xml
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"
version="1.0">
<persistence-unit name="RDBMS" transaction-type="RESOURCE_LOCAL">
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
<property name="hibernate.hbm2ddl.auto" value="validate"/>
<property name="hibernate.archive.autodetection" value="class"/>
<property name="dialect" value="org.hibernate.dialect.MySQL5InnoDBDialect"/>
<!-- <property name="dialect" value="org.hibernate.dialect.HSQLDialect"/> -->
</properties>
</persistence-unit>
</persistence>回答 19
Stack Overflow用户
回答已采纳
发布于 2010-07-25 22:53:43
你可以使用@JsonIgnore来打破这个循环(reference)。
您需要导入org.codehaus.jackson.annotate.JsonIgnore (传统版本)或com.fasterxml.jackson.annotation.JsonIgnore (当前版本)。
Stack Overflow用户
发布于 2016-09-19 20:31:10
新的注解@JsonIgnoreProperties解决了其他选项的许多问题。
@Entity
public class Material{
...
@JsonIgnoreProperties("costMaterials")
private List<Supplier> costSuppliers = new ArrayList<>();
...
}
@Entity
public class Supplier{
...
@JsonIgnoreProperties("costSuppliers")
private List<Material> costMaterials = new ArrayList<>();
....
}请看这里。它的工作原理与文档中的相同：
http://springquay.blogspot.com/2016/01/new-approach-to-solve-json-recursive.html
Stack Overflow用户
发布于 2013-12-03 05:55:15
此外，在使用Jackson 2.0+时，您还可以使用@JsonIdentityInfo。这对我的hibernate类来说比@JsonBackReference和@JsonManagedReference要好得多，这对我来说有问题，但没有解决问题。只需添加如下内容：
@Entity
@Table(name = "ta_trainee", uniqueConstraints = {@UniqueConstraint(columnNames = {"id"})})
@JsonIdentityInfo(generator=ObjectIdGenerators.IntSequenceGenerator.class, property="@traineeId")
public class Trainee extends BusinessObject {
@Entity
@Table(name = "ta_bodystat", uniqueConstraints = {@UniqueConstraint(columnNames = {"id"})})
@JsonIdentityInfo(generator=ObjectIdGenerators.IntSequenceGenerator.class, property="@bodyStatId")
public class BodyStat extends BusinessObject {它应该是有效的。
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原文链接：
https://stackoverflow.com/questions/3325387
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