blocks|key|2704123|text|可以，可以使用post方法同时发送params和body+:示例服务器端：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2704124|@RequestMapping(value+="test",+method+=+RequestMethod.POST)
@ResponseStatus(HttpStatus.OK)
@ResponseBody
public+Person+updatePerson(@RequestParam("arg1")+String+arg1,
++++++++@RequestParam("arg2")+String+arg2,
++++++++@RequestBody+Person+input)+throws+IOException+{
++++System.out.println(arg1);
++++System.out.println(arg2);
++++input.setName("NewName");
++++return+input;
}|code-block|syntax|javascript|2704125|在你的客户端上：|2704126|curl+-H+"Content-Type:application/json;+charset=utf-8"
+++++-X+POST
+++++'http://localhost:8080/smartface/api/email/test?arg1=ffdfa&arg2=test2'
+++++-d+'{"name":"me","lastName":"me+last"}'|2704127|尽情享受|2704128|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Yes,is possible to send both params and body with a post method:
Example server side: 

<pre><code>@RequestMapping(value ="test", method = RequestMethod.POST)
@ResponseStatus(HttpStatus.OK)
@ResponseBody
public Person updatePerson(@RequestParam("arg1") String arg1,
 @RequestParam("arg2") String arg2,
 @RequestBody Person input) throws IOException {
 System.out.println(arg1);
 System.out.println(arg2);
 input.setName("NewName");
 return input;
}
</code></pre>

and on your client:

<pre><code>curl -H "Content-Type:application/json; charset=utf-8"
 -X POST
 'http://localhost:8080/smartface/api/email/test?arg1=ffdfa&amp;arg2=test2'
 -d '{"name":"me","lastName":"me last"}'
</code></pre>

Enjoy

blocks|key|32692|text|为此，可以使用自动连接的Converter将String中的ObjectMapper注册到您的参数类型|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|32693|import+org.springframework.core.convert.converter.Converter;

@Component
public+class+PersonConverter+implements+Converter<String,+Person>+{

++++private+final+ObjectMapper+objectMapper;

++++public+PersonConverter+(ObjectMapper+objectMapper)+{
++++++++this.objectMapper+=+objectMapper;
++++}

++++@Override
++++public+Person+convert(String+source)+{
++++++++try+{
++++++++++++return+objectMapper.readValue(source,+Person.class);
++++++++}+catch+(IOException+e)+{
++++++++++++throw+new+RuntimeException(e);
++++++++}
++++}
}|code-block|syntax|javascript|32694|entityMap^0|C|9|M|6|U|C|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|L|$]]

You can do this by registering a <code>Converter</code> from <code>String</code> to your parameter type using an auto-wired <code>ObjectMapper</code>:
<pre><code>import org.springframework.core.convert.converter.Converter;

@Component
public class PersonConverter implements Converter&lt;String, Person&gt; {

 private final ObjectMapper objectMapper;

 public PersonConverter (ObjectMapper objectMapper) {
 this.objectMapper = objectMapper;
 }

 @Override
 public Person convert(String source) {
 try {
 return objectMapper.readValue(source, Person.class);
 } catch (IOException e) {
 throw new RuntimeException(e);
 }
 }
}
</code></pre>

blocks|key|31004|text|您可以使用RequestEntity。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|31005|public+Person+getPerson(RequestEntity<Person>+requestEntity)+{
++++return+requestEntity.getBody();
}|code-block|syntax|javascript|31006|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

you can use RequestEntity.

<pre><code>public Person getPerson(RequestEntity&lt;Person&gt; requestEntity) {
 return requestEntity.getBody();
}
</code></pre>

blocks|key|31623|text|用户：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|31624|+@Entity
public+class+User+{
++++@Id
++++@GeneratedValue(strategy=GenerationType.AUTO)
++++private+Integer+userId;
++++private+String+name;
++++private+String+password;
++++private+String+email;


++++//getter,+setter+...
}|code-block|syntax|javascript|31625|JSON：|31626|{"name":"Sam","email":"sam@gmail.com","password":"1234"}|31627|您可以使用@RequestBody|offset|length|style|BOLD|31628|@PostMapping(path="/add")
public+String+addNewUser+(@RequestBody+User+user)+{
++++User+u+=+new+User(user.getName(),user.getPassword(),user.getEmail());
++++userRepository.save(u);
++++return+"User+saved";
}|31629|entityMap^0|0|0|0|0|5|C|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@$M|Z|N|10|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

User:

<pre><code> @Entity
public class User {
 @Id
 @GeneratedValue(strategy=GenerationType.AUTO)
 private Integer userId;
 private String name;
 private String password;
 private String email;


 //getter, setter ...
}
</code></pre>

JSON:

<pre><code>{"name":"Sam","email":"sam@gmail.com","password":"1234"}
</code></pre>

You can use @RequestBody:

<pre><code>@PostMapping(path="/add")
public String addNewUser (@RequestBody User user) {
 User u = new User(user.getName(),user.getPassword(),user.getEmail());
 userRepository.save(u);
 return "User saved";
}
</code></pre>

I'm using Spring Boot (latest version, 1.3.6) and I want to create a REST endpoint which accepts a bunch of arguments and a JSON object. Something like:

<pre><code>curl -X POST http://localhost:8080/endpoint \
-d arg1=hello \
-d arg2=world \
-d json='{"name":"john", "lastNane":"doe"}'
</code></pre>

In the Spring controller I'm currently doing:

<pre><code>public SomeResponseObject endpoint(
@RequestParam(value="arg1", required=true) String arg1, 
@RequestParam(value="arg2", required=true) String arg2,
@RequestParam(value="json", required=true) Person person) {

 ...
}
</code></pre>

The <code>json</code> argument doesn't get serialized into a Person object. 
I get a 

<pre><code>400 error: the parameter json is not present.
</code></pre>

Obviously, I can make the <code>json</code> argument as String and parse the payload inside the controller method, but that kind of defies the point of using Spring MVC.

It all works if I use <code>@RequestBody</code>, but then I loose the possibility to POST separate arguments outside the JSON body.

Is there a way in Spring MVC to "mix" normal POST arguments and JSON objects?

How to POST a JSON payload to a @RequestParam in Spring MVC

服务器

JSON

我正在使用JSON (最新版本，1.3.6)，我想创建一个JSON端点，它接受一堆参数和一个JSON。类似于：curl -X POST http://localhost:8080/endpoint \-d arg1=hello \-d arg2=world \-d json='{"name":"john", "last...

问如何将JSON有效负载发布到Spring MVC中的@RequestParam
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