blocks|key|4403430|text|通常(有文档记录的)实现您所描述的(仅适用于Python+3)的方法是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4403431|print('Iteration',+i,+'Score:',+uniform(0,+1),+end='\r')|code-block|syntax|javascript|4403432|在Python2中，我们必须在打印后执行sys.stdout.flush()，如下面的answer所示|offset|length|style|CODE|4403433|print('Iteration',+i,+'Score:',+uniform(0,+1),+end='\r')
sys.stdout.flush()|4403434|使用IPython+notebook时，我必须连接字符串才能使其工作：|4403435|print('Iteration+'+%2B+str(i)+%2B+',+Score:+'+%2B+str(uniform(0,+1)),+end='\r')|4403436|最后，为了让它与Jupyter一起工作，我使用了以下代码：|4403437|print('\r',+'Iteration',+i,+'Score:',+uniform(0,+1),+end='')|4403438|或者，如果更有意义，您可以在time.sleep之前和之后拆分print，或者您需要更明确：|4403439|print('Iteration',+i,+'Score:',+uniform(0,+1),+end='')
time.sleep(1)
print('',+end='\r')+#+or+even+print('\r',+end='')|4403440|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/11018255/2757226^0|0|0|K|I|17|6|0|0|0|0|0|0|0|E|A|V|5|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1A|8|@$I|1B|J|1C|K|L]]|9|@$I|1D|J|1E|1|1F]]|A|$]]|$1|M|3|N|5|D|7|1G|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1H|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1I|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1J|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|1K|8|@]|9|@]|A|$E|F]]|$1|W|3|X|5|6|7|1L|8|@$I|1M|J|1N|K|L]|$I|1O|J|1P|K|L]]|9|@]|A|$]]|$1|Y|3|Z|5|D|7|1Q|8|@]|9|@]|A|$E|F]]|$1|10|3|-4|5|6|7|1R|8|@]|9|@]|A|$]]]|11|$12|$5|13|14|15|A|$16|17]]]]

The usual (documented) way to do what you describe (that only works with Python 3) is:

<pre><code>print('Iteration', i, 'Score:', uniform(0, 1), end='\r')
</code></pre>

In Python 2 we have to <code>sys.stdout.flush()</code> after the print, as it shows in this <a href="https://stackoverflow.com/a/11018255/2757226">answer</a>:

<pre><code>print('Iteration', i, 'Score:', uniform(0, 1), end='\r')
sys.stdout.flush()
</code></pre>

Using IPython notebook I had to concatenate the string to make it work:

<pre><code>print('Iteration ' + str(i) + ', Score: ' + str(uniform(0, 1)), end='\r')
</code></pre>

And finally, to make it work with Jupyter, I used this:

<pre><code>print('\r', 'Iteration', i, 'Score:', uniform(0, 1), end='')
</code></pre>

Or you could split the <code>print</code>s before and after the <code>time.sleep</code> if it makes more sense, or you need to be more explicit:

<pre><code>print('Iteration', i, 'Score:', uniform(0, 1), end='')
time.sleep(1)
print('', end='\r') # or even print('\r', end='')
</code></pre>

blocks|key|4403465|text|@cel是对的：ipython+notebook+clear+cell+output+in+code|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4403466|不过，使用clear_output()函数会让你的Notebook感到不安。我也推荐使用display()函数，如下所示(Python+2.7)：|4403467|from+random+import+uniform
import+time
from+IPython.display+import+display,+clear_output

def+black_box():
i+=+1
while+True:
++++clear_output(wait=True)
++++display('Iteration+'%2Bstr(i)%2B'+Score:+'%2Bstr(uniform(0,+1)))
++++time.sleep(1)
++++i+%2B=+1|code-block|syntax|javascript|4403468|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/24816237/ipython-notebook-clear-cell-output-in-code^0|8|16|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

@cel is right: <a href="https://stackoverflow.com/questions/24816237/ipython-notebook-clear-cell-output-in-code">ipython notebook clear cell output in code</a>

Using the clear_output() gives makes your Notebook have the jitters, though. I recommend using the display() function as well, like this (Python 2.7):

<pre><code>from random import uniform
import time
from IPython.display import display, clear_output

def black_box():
i = 1
while True:
 clear_output(wait=True)
 display('Iteration '+str(i)+' Score: '+str(uniform(0, 1)))
 time.sleep(1)
 i += 1
</code></pre>

Let's assume I have a part of code that runs for some specific amount of time and each 1 second outputs something like this: <code>iteration X, score Y</code>. I will substitute this function with my black box function:

<pre><code>from random import uniform
import time

def black_box():
 i = 1
 while True:
 print 'Iteration', i, 'Score:', uniform(0, 1)
 time.sleep(1)
 i += 1
</code></pre>

Now when I run it in <a href="https://tmp55.tmpnb.org/user/tqEpj95wJzL3/tree" rel="noreferrer">Jupyter notebook</a>, it output a new line after each second:

<pre><code>Iteration 1 Score: 0.664167449844
Iteration 2 Score: 0.514757592404
...
</code></pre>

Yes, after when the output becomes too big, the html becomes scrollable, but the thing is that I do not need any of these lines except of currently the last one. So instead of having <code>n</code> lines after <code>n</code> seconds, I want to have only <code>1</code> line (the last one) shown. 

I have not found anything like this in documentation or looking through magic. <a href="https://stackoverflow.com/questions/37956788/how-to-overwrite-the-previous-print-line-in-jupyter-ipython">A question</a> with almost the same title but irrelevant.

Overwrite previous output in jupyter notebook

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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让我们假设我有一部分代码运行了一段特定的时间，并且每1秒输出如下：iteration X, score Y。我将用我的黑盒函数替换这个函数：from random import uniformimport timedef black_box():    i = 1    while True:        print...

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