我如何重构这个RXJS / Angular代码？
我如何重构这个RXJS / Angular代码？
提问于 2018-06-02 07:33:50
如何重构这些嵌套数组，以便在所有订阅完成后可以调用某些内容？我确信它与管道、mergeMaps、concatMaps等的组合有关。
this.teams = [
{
Assignments: [{Id: 0, Name: 'assignment', Notes: 'notes'}]
},
{
Assignments: [{Id: 0, Name: 'assignment', Notes: 'notes'}]
}]
this.teams.map((team:any) => {
team.Assignments.map((a: Assignment) => {
return this.videoService.getById(a.VideoId).subscribe(
res => {
let e = new Event();
e.Id = a.Id;
e.title = a.Name;
e.location = '';
e.message = a.Notes;
e.startDate = a.StartDate;
e.endDate = a.EndDate;
e.video = res;
e.team = team.Name;
this.eventList.push(e);
},
err => {
});
})
})回答 1
Stack Overflow用户
发布于 2018-06-02 08:44:30
使用lodash：
Observable.from(
lodash.flatten(
this.teams.map(team => team.Assignments)
)
)
.flatMap(a => this.videoService.getById(a.VideoId))
. subscribe(
res => {
//handle individual responses
},
err => {},
() => {
//handle after all complete
}
)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50652138
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