PHP不显示数据库mysql中的任何数据
PHP不显示数据库mysql中的任何数据
提问于 2018-06-10 21:23:13
最近我正在用php工作，我想要显示数据，但这里没有显示我的代码，我想从数据库中获取数据并显示它，但什么也没有显示
<?php
$name = $_POST["names"] ;
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "phpapp";
// Create connection
$conn = mysql_connect("localhost", "root", "");
$db = mysql_select_db($dbname, $conn);
// Check connection
echo "Connected successfully";
$query = mysql_query("SELECT * FROM `user` WHERE 'name'='$name' " , $conn) or die ('Erreur SQL ! <br />'.mysql_error());
$row = mysql_fetch_array($query) ;
while($row = mysql_fetch_array($query)){
echo "<table>";
echo "<tr>";
echo "<td>".$row['name']."</td>";
echo "<td>".$row['lastname']."</td>";
echo "<td>".$row['email']."</td>";
echo "</tr>";
echo "</table>";
}
mysql_close();
?>回答 1
Stack Overflow用户
发布于 2018-06-11 05:10:38
使用以下使用mysqli_*的代码。你正在使用的东西很久以前就被弃用了。
<?php
$name = $_POST["names"] ;
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "phpapp";
// Create connection
$conn=mysqli_connect($servername ,$username,$password,$dbname);
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result =mysqli_query($con, "SELECT * FROM `user` WHERE `name` = '$name'");
while ($row = mysqli_fetch_array($result)){
echo "<table>";
echo "<tr>";
echo "<td>".$row['name']."</td>";
echo "<td>".$row['lastname']."</td>";
echo "<td>".$row['email']."</td>";
echo "</tr>";
echo "</table>";
}
mysqli_close($conn);?>页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50784141
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