调试期间在lldb中获取类静态成员函数地址:解释器无法在执行期间解析值
调试期间在lldb中获取类静态成员函数地址:解释器无法在执行期间解析值
提问于 2019-08-06 04:40:39
在lldb中调试时，我可以毫无问题地获取全局函数的地址。例如，我有以下代码：
#include <iostream>
void globalDoWork()
{
std::cout << "Global do work call\n";
}
struct Dummy
{
static void doWork()
{
std::cout << "Do work call\n";
}
};
int main(int argc, char* argv[])
{
globalDoWork();
Dummy::doWork();
std::cout << "global: " << (void*)&(globalDoWork) << "\n";
std::cout << "static: " << (void*)&(Dummy::doWork) << "\n";
return 0;
}在构建可执行文件之后，我在lldb下运行此程序：
Process 10759 stopped
* thread #1, queue = 'com.apple.main-thread', stop reason = step over
frame #0: 0x00000001000011a7 ex43`main(argc=1, argv=0x00007ffeefbff8f0) at ex43.cpp:21:15
18 globalDoWork();
19 Dummy::doWork();
20
-> 21 std::cout << "global: " << (void*)&(globalDoWork) << "\n";
22 std::cout << "static: " << (void*)&(Dummy::doWork) << "\n";
23
24 return 0;
Target 0: (ex43) stopped.
(lldb) p globalDoWork
(void (*)()) $0 = 0x0000000100001100 (ex43`globalDoWork() at ex43.cpp:4)
(lldb) next
global: 0x100001100并获取地址，但我不能用类的静态成员函数进行同样的操作：
static: 0x100001220
Process 10765 stopped
* thread #1, queue = 'com.apple.main-thread', stop reason = step over
frame #0: 0x0000000100001208 ex43`main(argc=1, argv=0x00007ffeefbff8f0) at ex43.cpp:24:5
21 std::cout << "global: " << (void*)&(globalDoWork) << "\n";
22 std::cout << "static: " << (void*)&(Dummy::doWork) << "\n";
23
-> 24 return 0;
25 }
Target 0: (ex43) stopped.
(lldb) p Dummy::doWork
error: supposed to interpret, but failed: Interpreter couldn't resolve a value during execution
(lldb) p (void*)&(Dummy::doWork)
error: supposed to interpret, but failed: Interpreter couldn't resolve a value during execution有什么问题吗？我该怎么做呢？
Stack Overflow用户
回答已采纳
发布于 2019-08-06 09:01:45
有意思的。调用该函数是可行的：
(lldb) expr Dummy::doWork()
Do work call但是我们没有正确地将静态方法的值作为函数指针输出。请向http://bugs.llvm.org提交有关此问题的bug。
请注意，lldb确实有更简单的方法来查找符号的地址，如果这是您想要做的全部。这是image lookup命令的工作：
(lldb) image lookup -n Dummy::doWork
1 match found in /tmp/dowork:
Address: dowork[0x0000000100001100] (dowork.__TEXT.__text + 304)
Summary: dowork`Dummy::doWork() at dowork.cpp:11页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/57365820
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