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Python:多处理输出问题
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Stack Overflow用户
提问于 2018-06-24 06:24:56
回答 1查看 59关注 0票数 0

我正在使用多进程运行以下代码。这一切都很好,除了输出似乎比它应该的输出要少。下面我给出了一个自包含的例子。

import pandas as pd
import multiprocessing
from multiprocessing import Pool, cpu_count
from functools import partial
import timeit
import numpy as np

prng = 1234
cpu_cores = cpu_count()-1


temp_df1 = pd.DataFrame({'trip_id':[22186702,22186703,22186704,26777219,26777220,26777221,26777222,26777223],
            'tour_id':[13525325,13525325,13525325,13525328,13525328,13525328,13525328,13525328],
            'start_time':[8,0,0,10.92,0,0,0,0],
            'ttime_mins':[3.810553,4.649286,2.917499,5.415158,3.800613,1.829472,1.829472,8.643289],
            'arrival_time':[8.063509,0,0,11.010253,0,0,0,0],
            'weight_column':['HBO_outbound','HBO_outbound','HBO_inbound','HBO_outbound','HBO_outbound','NHB_outbound','NHB_inbound','HBM_inbound']})

第二,在多进程中运行的时间采样数据名称和函数

time_dist = pd.DataFrame({'Time':[8,9,10,11,12,13,14],
            'HBO_outbound':[1573,419,339,544,600,453,100],
            'HBO_inbound':[1573,419,339,544,100,953,800],
            'HBM_outbound':[1573,419,339,544,640,463,90],
            'HBM_inbound':[1573,419,339,544,320,453,100],
            'WBO_outbound':[1573,419,339,544,600,453,100],
            'WBO_inbound':[1573,419,339,544,450,803,190],
            'NHB_outbound':[1573,419,339,544,901,543,290],
            'NHB_inbound':[1573,419,339,544,863,453,330]})

results_frow = []
result_list_final = []

def func(df, time_dist_df):
    """

    """
    for i in range(0, df.shape[0]):
        if i == 0:
            start_time = df['start_time'].iloc[i]
            arrival_time = df['arrival_time'].iloc[i]
            tour_id = df['tour_id'].iloc[i]
            results_frow.append(start_time)
            results_frow.append(arrival_time)
            results_frow.append(tour_id)

        else:
            tour_id = df['tour_id'].iloc[i]
            arrival_time_prev = results_frow[-2]
            time_dist1 = time_dist.loc[time_dist['Time'] >= arrival_time_prev]
            weight_column = df['weight_column'].iloc[i]

            # sample a time and calculate a new arrival time as a result
            if len(time_dist1) > 0:
                start_time = time_dist1.sample(n=1, weights=time_dist1[weight_column], replace=True, random_state=prng)
                start_time = start_time[['Time']].values  ###
                start_time = start_time[0][0]    
            else:
                start_time = results_frow[-2]

            newarrival_time = start_time + df['ttime_mins'].iloc[i] / 60
            results_frow.append(start_time)
            results_frow.append(newarrival_time)
            results_frow.append(tour_id)

    return results_frow

现在运行多进程并收集结果

def collect_results(result_list):
    return pd.DataFrame({'start_time': result_list[0::3],
                  'arrival_time': result_list[1::3],
                  'tour_id': result_list[2::3]})

# create list of grouped dataframes
grplist = []
for name, group in temp_df1.groupby('tour_id'):
    grplist.append(group)

# use partial to fix the second argument in the function so that multiprocessing does not have an issue
func_partial = partial(func, time_dist_df = time_dist)

if __name__ == '__main__':
    start = timeit.default_timer()
    pool = multiprocessing.Pool(processes=cpu_cores)
    result_list = pool.map(func_partial, grplist)
    result_list_final = result_list[1]

    results_df = collect_results(result_list_final) #### Here lies the problem. Instead of getting back 8 rows, I am only getting back 5 i.e. the last group in the grplist
    stop = timeit.default_timer()
    total_time = stop - start
    print("It took a total of %sec" %total_time)
    results_df.to_csv(r"c:/stimes_parallelized.csv", index=False)

    pool.close()
    pool.join()

该问题存在于多处理代码块中的results_df。它只返回最后一组(5行)的结果,而不是两组或8行。如果我在Pycharm中进入调试模式,我会在results_df中看到所有8行,但当我将文件另存为csv时就不是这样了。

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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/51005528

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