blocks|key|2354045|text|使用@JsonSerialize(using+=+CustomSerializer.class)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2354046|@Entity(name+=+"users")
public+class+User+implements+Serializable+{

++++@Id
++++@GeneratedValue
++++@Column(name+=+"user_id")
++++private+Long+id;

++++@Column(name+=+"first_name")
++++private+String+firstName;

++++@Column(name+=+"last_name")
++++private+String+lastName;


++++@JsonSerialize(using+=+CustomSerializer.class)
++++@Column(name+=+"date_of_birth")
++++private+LocalDateTime+dateOfBirth;++

++++.+.+.

}|code-block|syntax|javascript|2354047|自定义serilizer类：|2354048|public+class+CustomSerializer+extends+JsonSerializer<LocalDateTime>+{
@Override
public+void+serialize(LocalDateTime+value,+JsonGenerator+gen,+SerializerProvider+serializers)+throws+IOException+{
++++//add+your+custom+date+parser
++++gen.writeString(value.atZone(ZoneId.systemDefault()).toInstant().toEpochMilli()%2B"");
}
}|2354049|entityMap^0|2|1A|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

use <code>@JsonSerialize(using = CustomSerializer.class)</code>

<pre><code>@Entity(name = "users")
public class User implements Serializable {

 @Id
 @GeneratedValue
 @Column(name = "user_id")
 private Long id;

 @Column(name = "first_name")
 private String firstName;

 @Column(name = "last_name")
 private String lastName;


 @JsonSerialize(using = CustomSerializer.class)
 @Column(name = "date_of_birth")
 private LocalDateTime dateOfBirth; 

 . . .

}
</code></pre>

custom serilizer class:

<pre><code>public class CustomSerializer extends JsonSerializer&lt;LocalDateTime&gt; {
@Override
public void serialize(LocalDateTime value, JsonGenerator gen, SerializerProvider serializers) throws IOException {
 //add your custom date parser
 gen.writeString(value.atZone(ZoneId.systemDefault()).toInstant().toEpochMilli()+"");
}
}
</code></pre>

blocks|key|2354051|text|为什么不像下面这样存储date属性：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2354052|@Temporal(TemporalType.TIMESTAMP)
private+Date+date+=+new+Date();|code-block|syntax|javascript|2354053|它以毫秒为单位给出日期。将其格式化为所需的输出是应用层的责任。不要在带有注释的实体本身上这样做。|2354054|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Why dont you store date property as below :

<pre><code>@Temporal(TemporalType.TIMESTAMP)
private Date date = new Date();
</code></pre>

It gives date in milliseconds. Formatting it to desired output is responsibility of application layer. Don't do it on entity itself with some annotation.

blocks|key|2242955|text|如果不想用@JsonSerialize修饰所有对象，可以将对象映射器配置为总是为LocalDateTime返回一个long。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2242956|@Bean
public+ObjectMapper+objectMapper()+{
++++ObjectMapper+objectMapper+=+new+ObjectMapper();
++++JavaTimeModule+javaTimeModule+=+new+JavaTimeModule();
++++javaTimeModule.addSerializer(LocalDateTime.class,+new+LocalDateSerializer());
++++javaTimeModule.addDeserializer(LocalDateTime.class,+new+LocalDateDeserializer());
++++objectMapper.registerModule(javaTimeModule);
++++return+objectMapper;
}|code-block|syntax|javascript|2242957|和反序列化程序。|2242958|public+class+LocalDateSerializer+extends+JsonSerializer<LocalDateTime>+{
++++@Override
++++public+void+serialize(LocalDateTime+value,+JsonGenerator+gen,+SerializerProvider+serializers)+throws+IOException+{
++++++++gen.writeString(String.valueOf(value.atZone(ZoneId.systemDefault()).toEpochSecond()));
++++}
}

public+class+LocalDateDeserializer+extends+JsonDeserializer<LocalDateTime>+{
++++@Override
++++public+LocalDateTime+deserialize(JsonParser+p,+DeserializationContext+ctxt)+throws+IOException+{
++++++++return+LocalDateTime.ofInstant(Instant.ofEpochSecond(Long.parseLong(p.getValueAsString())),+ZoneId.systemDefault());
++++}
}|2242959|在您的示例中，您使用了date+of+birth，它可以是一个LocalDate。|2242960|entityMap^0|5|E|14|D|0|0|0|0|V|9|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|R|$]]

If you don't want to decorate all you objects with <code>@JsonSerialize</code> you can configure the object mapper to always return a long for <code>LocalDateTime</code>. 

<pre><code>@Bean
public ObjectMapper objectMapper() {
 ObjectMapper objectMapper = new ObjectMapper();
 JavaTimeModule javaTimeModule = new JavaTimeModule();
 javaTimeModule.addSerializer(LocalDateTime.class, new LocalDateSerializer());
 javaTimeModule.addDeserializer(LocalDateTime.class, new LocalDateDeserializer());
 objectMapper.registerModule(javaTimeModule);
 return objectMapper;
}
</code></pre>

and the de- and serializers.

<pre><code>public class LocalDateSerializer extends JsonSerializer&lt;LocalDateTime&gt; {
 @Override
 public void serialize(LocalDateTime value, JsonGenerator gen, SerializerProvider serializers) throws IOException {
 gen.writeString(String.valueOf(value.atZone(ZoneId.systemDefault()).toEpochSecond()));
 }
}

public class LocalDateDeserializer extends JsonDeserializer&lt;LocalDateTime&gt; {
 @Override
 public LocalDateTime deserialize(JsonParser p, DeserializationContext ctxt) throws IOException {
 return LocalDateTime.ofInstant(Instant.ofEpochSecond(Long.parseLong(p.getValueAsString())), ZoneId.systemDefault());
 }
}
</code></pre>

In your example you are using date of birth which could be a <code>LocalDate</code>.

I have developed a rest service with Spring Boot. I want return a json response with the birthday of the user as milliseconds.
How to serialize a <code>java.time.LocalDateTime</code> object to milliseconds ?

My model class:

<pre><code> @Entity(name = "users")
 public class User implements Serializable {

 @Id
 @GeneratedValue
 @Column(name = "user_id")
 private Long id;

 @Column(name = "first_name")
 private String firstName;

 @Column(name = "last_name")
 private String lastName;



 @Column(name = "date_of_birth")
 private LocalDateTime dateOfBirth; 

 . . .

 }
</code></pre>

current response:

<pre><code>{
 . . .
"dateOfBirth":[2018,7,25,7,0],
. . . 
}
</code></pre>

preferred response:

<pre><code>{
 . . .
"dateOfBirth": 1532786354419,
. . . 
}
</code></pre>

Spring Boot - How to create a custom serialization for " java.time.LocalDateTime" class

Spring Boot

我已经用Spring Boot开发了一个rest服务。我想返回一个以毫秒为单位的用户生日的json响应。如何将java.time.LocalDateTime对象序列化到毫秒？我的模型类：    @Entity(name = "users")    public class User implements Seriali...

问Spring Boot -如何为“java.time.LocalDateTime”类创建自定义序列化
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