在Python语言中创建不和谐的机器人:如何为ChatBot创建切换对话
在Python语言中创建不和谐的机器人:如何为ChatBot创建切换对话
提问于 2018-07-29 08:35:05
我试图在Python语言中创建一个不和谐的ChatBot，但我似乎遇到了一个问题。我做了一个开关来让它说话，但每当我切换开关时，它就会说' talk‘不能被识别为命令。我甚至试着用@client.event代替@client.command，但是不起作用。请帮帮忙。
import discord
from discord.ext.commands import Bot
from discord.ext import commands
import asyncio
import time
Client = discord.Client()
client = commands.Bot(command_prefix = ":")
on_talk = False
@client.event
async def on_ready():
print("You can talk to me now!")
@client.command
async def talk(message):
global on_talk
if message.content.upper().startswith(":TALK"):
on_talk = True
if message.content.upper().startswith(":STOPTALK"):
on_talk = False
if on_talk == False:
print("on_talk is set to False")
if on_talk == True:
print("It works")编辑: talk函数可以工作，但我似乎不能让stoptalk函数工作。我试过这么做。
import discord
from discord.ext.commands import Bot
from discord.ext import commands
import asyncio
import time
Client = discord.Client()
client = commands.Bot(command_prefix = ":")
on_talk = False
@client.event
async def on_ready():
print("You can talk to me now!")
@client.command(pass_context=True)
async def ontalker(message):
global on_talk
if message.content.upper().startswith(":TALK"):
on_talk = True
@client.command(pass_context=True)
async def offtalker(message):
global ontalk
if message.content.upper().startswith(":STOPTALK"):
on_talk = False
@client.command(pass_context=True)
async def stoptalk(ctx):
print("on_talk is False.")
@client.command(pass_context=True)
async def talk(ctx):
everything i want to do有人能帮上忙吗？
回答 1
Stack Overflow用户
回答已采纳
发布于 2018-07-29 08:42:43
client.command返回一个装饰器，所以在装饰协例程时必须调用它。如果您想要传递消息，则必须指定pass_context=True并通过ctx.message访问消息。
@client.command(pass_context=True)
async def talk(ctx):
global on_talk
on_talk = True
@client.command(pass_context=True)
async def stoptalk(ctx):
global on_talk
on_talk = False页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51576304
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