问PHP输出格式错误的html表。

EN

<?php
    $query = $_POST['query']; 
    $min_length = 1;

    if(strlen($query) >= $min_length){ // if query length is more or equal minimum length then

        $query = htmlspecialchars($query); 
        $query = mysql_real_escape_string($query);         
        $raw_results = mysql_query("SELECT * FROM norse5_proov
            WHERE (`model` LIKE '%".$query."%') OR (`year` LIKE '%".$query."%')") or die(mysql_error());

        if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following

            while($results = mysql_fetch_array($raw_results)){
                echo "<table>";
                echo "<tr>";
                        echo "<td>Model name</td>";
                echo "<td>Year</td>";
                echo "</tr>";
                echo "<td>".$results['mudeli_nimetus']."</td>";

                echo "<td>".$results['soetusaasta']."</td>";
                echo "<br>";
                echo "</table>";
            }

        }
        else{
            echo "No results";
        }

    }
?>