在javascript中生成符合要求的随机密码字符串
在javascript中生成符合要求的随机密码字符串
提问于 2012-03-15 20:21:02
我想生成一个随机字符串，它必须有5个字母从a-z和3个数字。
我怎样才能用JavaScript做到这一点？
我有以下脚本，但它不符合我的要求。
var chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
var string_length = 8;
var randomstring = '';
for (var i=0; i<string_length; i++) {
var rnum = Math.floor(Math.random() * chars.length);
randomstring += chars.substring(rnum,rnum+1);
}回答 16
Stack Overflow用户
发布于 2018-07-26 21:50:11
对于正在寻找最简单脚本的人来说。没有while (true)，没有if/else，没有声明。
基于mwag的answer，但这一次使用的是crypto.getRandomValues，一个比Math.random更强的随机性。
var generatePassword = (
length = 20,
wishlist = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz~!@-#$'
) =>
Array.from(crypto.getRandomValues(new Uint32Array(length)))
.map((x) => wishlist[x % wishlist.length])
.join('')
console.log(generatePassword())书签小程序
javascript:prompt("Random password:",((o=20,n="0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz~!@-#$")=>Array.from(crypto.getRandomValues(new Uint32Array(o))).map(o=>n[o%n.length]).join(""))())Node.js
const crypto = require('crypto')
const generatePassword = (
length = 20,
wishlist = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz~!@-#$'
) =>
Array.from(crypto.randomFillSync(new Uint32Array(length)))
.map((x) => wishlist[x % wishlist.length])
.join('')
console.log(generatePassword())Python
#!/usr/bin/env python
import os
def rand(length: int) -> str:
bytes = os.urandom(length)
chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890-"
cl = len(chars)
rs = ''
for i in bytes:
rs += chars[i % cl]
return rs
print(rand(18))去
Stack Overflow用户
发布于 2012-03-15 20:36:30
这并不是完全优化的，但它应该可以工作。
var chars = "ABCDEFGHIJKLMNOPQRSTUVWXTZabcdefghiklmnopqrstuvwxyz";
var string_length = 8;
var randomstring = '';
var charCount = 0;
var numCount = 0;
for (var i=0; i<string_length; i++) {
// If random bit is 0, there are less than 3 digits already saved, and there are not already 5 characters saved, generate a numeric value.
if((Math.floor(Math.random() * 2) == 0) && numCount < 3 || charCount >= 5) {
var rnum = Math.floor(Math.random() * 10);
randomstring += rnum;
numCount += 1;
} else {
// If any of the above criteria fail, go ahead and generate an alpha character from the chars string
var rnum = Math.floor(Math.random() * chars.length);
randomstring += chars.substring(rnum,rnum+1);
charCount += 1;
}
}
alert(randomstring);
这里有一个供您测试的jsfiddle：http://jsfiddle.net/sJGW4/3/
Stack Overflow用户
发布于 2017-03-31 11:11:02
如果您需要生成至少包含1个数字、1个大写字符和1个小写字符的密码：
function generatePassword(passwordLength) {
var numberChars = "0123456789";
var upperChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
var lowerChars = "abcdefghijklmnopqrstuvwxyz";
var allChars = numberChars + upperChars + lowerChars;
var randPasswordArray = Array(passwordLength);
randPasswordArray[0] = numberChars;
randPasswordArray[1] = upperChars;
randPasswordArray[2] = lowerChars;
randPasswordArray = randPasswordArray.fill(allChars, 3);
return shuffleArray(randPasswordArray.map(function(x) { return x[Math.floor(Math.random() * x.length)] })).join('');
}
function shuffleArray(array) {
for (var i = array.length - 1; i > 0; i--) {
var j = Math.floor(Math.random() * (i + 1));
var temp = array[i];
array[i] = array[j];
array[j] = temp;
}
return array;
}
alert(generatePassword(12));如果你想玩/测试，这里是小提琴：http://jsfiddle.net/sJGW4/155/
向@mwag致敬，因为它让我开始创建它。
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原文链接：
https://stackoverflow.com/questions/9719570
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