blocks|key|4080062|text|尽管你使用了'file‘这个词，但在我看来，你已经完成了阅读文件内容的部分。我认为NewFile和OldFile是一些类实例的列表，它们表示文件中一行的内容。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4080063|所以我将它命名为FileItem，看起来像这样。|4080064|public+class+FileItem
{
++++public+int+FileID+{+get;+set;+}
++++public+int+SysCount+{+get;+set;+}
++++public+string+SysName+{+get;+set;+}
}|code-block|syntax|javascript|4080065|我认为你本质上是想找出哪些是OldFile独有的项目，哪些是NewFile独有的项目(也许还有什么是两者的共同点)。|4080066|为此，我将首先编写一个EqualityComparer，以便可以比较两个列表中的项。从您的代码中可以看出，如果该类的三个属性相等，则认为两个项相等。所以我遵循了这个逻辑。|4080067|public+class+FileComparer+:+IEqualityComparer<FileItem>
{
++++public+bool+Equals(FileItem+x,+FileItem+y)
++++{
++++++++return+(x.FileID+==+y.FileID+&&+x.SysCount+==+y.SysCount+&&+x.SysName+==+y.SysName);
++++}

++++public+int+GetHashCode(FileItem+obj)
++++{
++++++++unchecked
++++++++{
++++++++++++int+hash+=+17;
++++++++++++if+(obj+!=+null)
++++++++++++{
++++++++++++++++hash+=+hash+*+23+%2B+obj.FileID.GetHashCode();
++++++++++++++++hash+=+hash+*+23+%2B+obj.SysCount.GetHashCode();
++++++++++++++++hash+=+hash+*+23+%2B+obj.SysName.GetHashCode();
++++++++++++}
++++++++++++return+0;
++++++++}
++++}
}|4080068|现在，只需使用LINQ方法Except()和Intersect()即可获得您想要的内容。|4080069|static+void+Main(string[]+args)
{
++++List<FileItem>+OldFile+=+new+List<FileItem>
++++{
++++++++new+FileItem()+{+FileID+=+1,+SysCount+=+100,+SysName+=+"One"+},
++++++++new+FileItem()+{+FileID+=+2,+SysCount+=+200,+SysName+=+"Two"+},
++++++++new+FileItem()+{+FileID+=+3,+SysCount+=+300,+SysName+=+"Three"+},
++++++++new+FileItem()+{+FileID+=+4,+SysCount+=+400,+SysName+=+"Four"+},
++++++++new+FileItem()+{+FileID+=+5,+SysCount+=+500,+SysName+=+"Five"+}
++++};

++++List<FileItem>+NewFile+=+new+List<FileItem>
++++{
++++++++new+FileItem()+{+FileID+=+1,+SysCount+=+100,+SysName+=+"One"+},
++++++++new+FileItem()+{+FileID+=+200,+SysCount+=+200,+SysName+=+"Two"+},
++++++++new+FileItem()+{+FileID+=+3,+SysCount+=+300,+SysName+=+"Three"+},
++++++++new+FileItem()+{+FileID+=+400,+SysCount+=+400,+SysName+=+"Four"+},
++++++++new+FileItem()+{+FileID+=+5,+SysCount+=+500,+SysName+=+"Five"+}
++++};

++++var+onlyInNew+=+NewFile.Except(OldFile,+new+FileComparer());
++++var+onlyInOld+=+OldFile.Except(NewFile,+new+FileComparer());
++++var+commonToBoth+=+OldFile.Intersect(NewFile,+new+FileComparer());

++++Console.ReadLine();
}|4080070|entityMap^0|15|7|1D|7|0|8|8|0|0|E|7|U|7|0|B|G|0|0|7|4|D|8|M|B|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|16|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|1C|8|@$9|1D|A|1E|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|J|7|1F|8|@]|D|@]|E|$K|L]]|$1|S|3|T|5|6|7|1G|8|@$9|1H|A|1I|B|C]|$9|1J|A|1K|B|C]|$9|1L|A|1M|B|C]]|D|@]|E|$]]|$1|U|3|V|5|J|7|1N|8|@]|D|@]|E|$K|L]]|$1|W|3|-4|5|6|7|1O|8|@]|D|@]|E|$]]]|X|$]]

Even though you use the word 'file' it appears to me that you've already done the part where you read the contents of the files. And I believe that <code>NewFile</code> and <code>OldFile</code> are lists of some class instances that represent the content of a line of a file.

So I'm going to name it <code>FileItem</code>, and will look something like this.

<pre><code>public class FileItem
{
 public int FileID { get; set; }
 public int SysCount { get; set; }
 public string SysName { get; set; }
}
</code></pre>

And I think you essentially want to find out which are the items unique to <code>OldFile</code>, and which are the items unique to <code>NewFile</code> (and maybe what's common to both as well).

For this, I would first write an <code>EqualityComparer</code> so I can compare items in the two lists. From your code it appears that you consider two items equal if three properties of that class are equal. So I'm following along that logic.

<pre><code>public class FileComparer : IEqualityComparer&lt;FileItem&gt;
{
 public bool Equals(FileItem x, FileItem y)
 {
 return (x.FileID == y.FileID &amp;&amp; x.SysCount == y.SysCount &amp;&amp; x.SysName == y.SysName);
 }

 public int GetHashCode(FileItem obj)
 {
 unchecked
 {
 int hash = 17;
 if (obj != null)
 {
 hash = hash * 23 + obj.FileID.GetHashCode();
 hash = hash * 23 + obj.SysCount.GetHashCode();
 hash = hash * 23 + obj.SysName.GetHashCode();
 }
 return 0;
 }
 }
}
</code></pre>

Now it's as easy as using <code>LINQ</code> methods <code>Except()</code> and <code>Intersect()</code> to get what you want.

<pre><code>static void Main(string[] args)
{
 List&lt;FileItem&gt; OldFile = new List&lt;FileItem&gt;
 {
 new FileItem() { FileID = 1, SysCount = 100, SysName = "One" },
 new FileItem() { FileID = 2, SysCount = 200, SysName = "Two" },
 new FileItem() { FileID = 3, SysCount = 300, SysName = "Three" },
 new FileItem() { FileID = 4, SysCount = 400, SysName = "Four" },
 new FileItem() { FileID = 5, SysCount = 500, SysName = "Five" }
 };

 List&lt;FileItem&gt; NewFile = new List&lt;FileItem&gt;
 {
 new FileItem() { FileID = 1, SysCount = 100, SysName = "One" },
 new FileItem() { FileID = 200, SysCount = 200, SysName = "Two" },
 new FileItem() { FileID = 3, SysCount = 300, SysName = "Three" },
 new FileItem() { FileID = 400, SysCount = 400, SysName = "Four" },
 new FileItem() { FileID = 5, SysCount = 500, SysName = "Five" }
 };

 var onlyInNew = NewFile.Except(OldFile, new FileComparer());
 var onlyInOld = OldFile.Except(NewFile, new FileComparer());
 var commonToBoth = OldFile.Intersect(NewFile, new FileComparer());

 Console.ReadLine();
}
</code></pre>

Im doing a comparison of data from two files (an old and new file). The files are similar except that the new file has items from the old file that have changed. I need to add the changed items to a changed list and the unchanged items to an unchanged list. I do this by searching for each item from the new file in the old file and comparing file elements. If the new item is found, it is added to the unchanged list, otherwise it is added to the changed list.

What I am trying to determine now is which item in the new file has changed. How can I determine this if the item was not found? Also, more than one element in the new file could be different from the old file.

Heres the snippet:

<pre><code>foreach (var newfileItem in NewFile)
{
 var checkitem = OldFile.FirstOrDefault(d =&gt; d.fileID == newfileItem.fileID &amp;&amp; d.SysName == newfileItem.Sysname &amp;&amp; d.SysCount == newfileItem.SysCount);
 if (checkitem == null) //item not found therefore something changed
 {
 //which item changed??
 changedlist.Add(checkitem);
 }
 else //item found, therefore unchanged
 {
 unchangedlist.Add(newfileItem);
 }
 checkitem = null;
}
</code></pre>

Comparing Items From Two Files To Determine Which Elements Changed

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在对两个文件(新旧文件)中的数据进行比较。除了新文件具有已更改的旧文件中的项目外，其他文件都是相似的。我需要将已更改的项添加到已更改的列表中，将未更改的项添加到未更改的列表中。为此，我从旧文件中的新文件中搜索每一项，并比较文件元素。如果找到新项目，则将其添加到未更改列表中，否则将其添加到已更改列表中。我现在正在尝试...

比较两个文件中的项以确定哪些元素发生了更改-腾讯云开发者社区-腾讯云

问比较两个文件中的项以确定哪些元素发生了更改
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