blocks|key|4677519|text|延伸Rahul+Gupta所说的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4677520|您可以使用Java函数int+random+=+Random.nextInt(n)。|offset|length|style|CODE|4677521|这将返回[0,+n-1]范围内的随机int。|4677522|也就是说，要获取范围[20,+80]，请使用：|4677523|final+int+random+=+new+Random().nextInt(61)+%2B+20;+//+[0,+60]+%2B+20+=>+[20,+80]|code-block|syntax|javascript|4677524|要概括更多内容：|4677525|final+int+min+=+20;
final+int+max+=+80;
final+int+random+=+new+Random().nextInt((max+-+min)+%2B+1)+%2B+min;|4677526|entityMap^0|0|B|U|0|4|8|I|3|0|A|8|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@$D|Y|E|Z|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|10|8|@$D|11|E|12|F|G]|$D|13|E|14|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|15|8|@$D|16|E|17|F|G]]|9|@]|A|$]]|$1|L|3|M|5|N|7|18|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|6|7|19|8|@]|9|@]|A|$]]|$1|S|3|T|5|N|7|1A|8|@]|9|@]|A|$O|P]]|$1|U|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|V|$]]

To extend what Rahul Gupta said:
You can use Java function <code>int random = Random.nextInt(n)</code>. 
This returns a random <code>int</code> in the range <code>[0, n-1]</code>.
I.e., to get the range <code>[20, 80]</code> use:
<pre><code>final int random = new Random().nextInt(61) + 20; // [0, 60] + 20 =&gt; [20, 80]
</code></pre>
To generalize more:
<pre><code>final int min = 20;
final int max = 80;
final int random = new Random().nextInt((max - min) + 1) + min;
</code></pre>

blocks|key|4677670|text|此外，在API级别21中，这也是可能的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4677671|int+random+=+ThreadLocalRandom.current().nextInt(min,+max);|code-block|syntax|javascript|4677672|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Also, from API level 21 this is possible:

<pre><code>int random = ThreadLocalRandom.current().nextInt(min, max);
</code></pre>

blocks|key|4677592|text|/**
*+min+and+max+are+to+be+understood+inclusively
*/
public+static+int+getRandomNumber(int+min,+int+max)+{
++++return+(new+Random()).nextInt((max+-+min)+%2B+1)+%2B+min;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4677593|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>/**
* min and max are to be understood inclusively
*/
public static int getRandomNumber(int min, int max) {
 return (new Random()).nextInt((max - min) + 1) + min;
}
</code></pre>

blocks|key|171644|text|“用户是选择最大编号和最小编号的用户吗?”你说这行是什么意思？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|171645|您可以使用java函数int+random+=+Random.nextInt(n)。这将返回一个range0中的随机整数，n-1)。|offset|length|style|CODE|171646|并且可以使用setText()方法在文本视图中设置它|171647|entityMap^0|0|B|U|0|6|9|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|K|$]]

" the user is the one who select max no and min no ?"
What do you mean by this line ?

You can use java function <code>int random = Random.nextInt(n)</code>. This returns a random int in range[0, n-1]). 

and you can set it in your textview using the <code>setText()</code> method

blocks|key|4677578|text|因此，您可能需要以下内容：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4677579|int+random;
int+max;
int+min;|code-block|syntax|javascript|4677580|...somewhere在您的代码中放置方法，以便在用户单击submit时获取用户的最小和最大值，然后在下面的代码行中使用它们：|4677581|random+=+Random.nextInt(max-min%2B1)%2Bmin;|4677582|这将随机设置为用户选择的最小值和最大值之间的一个随机数。然后，您将执行以下操作：|4677583|TextView.setText(random.toString());|4677584|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

So you would want the following:

<pre><code>int random;
int max;
int min;
</code></pre>

...somewhere in your code put the method to get the min and max from the user when they click submit and then use them in the following line of code:

<pre><code>random = Random.nextInt(max-min+1)+min;
</code></pre>

This will set random to a random number between the user selected min and max.
Then you will do:

<pre><code>TextView.setText(random.toString());
</code></pre>

blocks|key|171808|text|您可以使用If+Random。例如，这会生成一个介于75到100之间的随机数。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|171809|final+int+random+=+new+Random().nextInt(26)+%2B+75;|code-block|syntax|javascript|171810|entityMap^0|8|6|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can use If <code>Random</code>. For example, this generates a random number between 75 to 100.

<pre><code>final int random = new Random().nextInt(26) + 75;
</code></pre>

blocks|key|4677722|text|下面的代码将帮助您在给定范围内的两个数字之间生成随机数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4677723|private+void+generateRandomNumbers(int+min,+int+max)+{
++++//+min+&+max+will+be+changed+as+per+your+requirement.+In+my+case,+I've+taken+min+=+2+&+max+=+32

++++int+randomNumberCount+=+10;

++++int+dif+=+max+-+min;
++++if+(dif+<+(randomNumberCount+*+3))+{
++++++++dif+=+(randomNumberCount+*+3);
++++}

++++int+margin+=+(int)+Math.ceil((float)+dif+/+randomNumberCount);
++++List<Integer>+randomNumberList+=+new+ArrayList<>();

++++Random+random+=+new+Random();

++++for+(int+i+=+0;+i+<+randomNumberCount;+i%2B%2B)+{
++++++++int+range+=+(margin+*+i)+%2B+min;+//+2,+5,+8

++++++++int+randomNum+=+random.nextInt(margin);
++++++++if+(randomNum+==+0)+{
++++++++++++randomNum+=+1;
++++++++}

++++++++int+number+=+(randomNum+%2B+range);
++++++++randomNumberList.add(number);
++++}
++++Collections.sort(randomNumberList);
++++Log.i("generateRandomNumbers",+"RandomNumberList:+"+%2B+randomNumberList);
}|code-block|syntax|javascript|4677724|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Below code will help you to generate random numbers between two numbers in the given range:

<pre><code>private void generateRandomNumbers(int min, int max) {
 // min &amp; max will be changed as per your requirement. In my case, I've taken min = 2 &amp; max = 32

 int randomNumberCount = 10;

 int dif = max - min;
 if (dif &lt; (randomNumberCount * 3)) {
 dif = (randomNumberCount * 3);
 }

 int margin = (int) Math.ceil((float) dif / randomNumberCount);
 List&lt;Integer&gt; randomNumberList = new ArrayList&lt;&gt;();

 Random random = new Random();

 for (int i = 0; i &lt; randomNumberCount; i++) {
 int range = (margin * i) + min; // 2, 5, 8

 int randomNum = random.nextInt(margin);
 if (randomNum == 0) {
 randomNum = 1;
 }

 int number = (randomNum + range);
 randomNumberList.add(number);
 }
 Collections.sort(randomNumberList);
 Log.i("generateRandomNumbers", "RandomNumberList: " + randomNumberList);
}
</code></pre>

How can I create an app that generates a random number in Android using Eclipse and then show the result in a <code>TextView</code> field? The random number has to be in a range selected by the user. So, the user will input the max and min of the range, and then I will output the answer.

How can I generate a random number in a certain range?

Android

Eclipse

Java

如何在Android中使用Eclipse创建一个生成随机数的应用程序，然后在TextView字段中显示结果？随机数必须在用户选择的范围内。因此，用户将输入范围的最大值和最小值，然后我将输出答案。

问如何在一定范围内生成随机数？
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回答 7

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问如何在一定范围内生成随机数？EN

回答 7

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问如何在一定范围内生成随机数？
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