如何在print (x ,"is" )
中显示偶数和奇数
num_list = list(range(1, 51))
odd_nums = []
even_nums = []
for x in num_list:
if x % 2 == 0:
even_nums.append(x)
else:
odd_nums.append(x)
print (x ,"is" )
发布于 2019-02-14 20:26:44
解决方案1-使用列表理解-
print([("even" if x%2 == 0 else "odd") for x in range(10)])
解决方案2-使用列表理解-
print([x for x in range(10) if x%2 ==0])
Sol 3-使用字典理解-
di = {x:("even" if x%2 == 0 else "odd") for x in range(10)}
print(di)
Sol 4-使用filter() -
li = list(range(20))
print(list(filter(lambda x: x%2 == 0,li)))
print(list(filter(lambda x: x%2 == 1,li)))
发布于 2018-08-21 02:05:18
你已经在检查它了,如果你想显示"Odd“甚至”你可以简单地在if-else语句中放一条print语句;
num_list = list(range(1, 51))
odd_nums = []
even_nums = []
for x in num_list:
if x % 2 == 0:
even_nums.append(x)
print (x ,"is a even number")
else:
odd_nums.append(x)
print (x ,"is a odd number")
发布于 2018-08-21 02:06:12
只需添加以下内容即可:
num_list = list(range(1, 51))
odd_nums = []
even_nums = []
for x in num_list:
if x % 2 == 0:
even_nums.append(x)
print (x ,"is even" )
else:
odd_nums.append(x)
print (x ,"is odd" )
https://stackoverflow.com/questions/51936179
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