使用java客户端传递json对象调用Rest API
使用java客户端传递json对象调用Rest API
提问于 2018-07-30 02:16:04
我是JSON的新手。我正在调用一个公共rest API https://api.gdc.cancer.gov/cases
我想查询特定疾病类型的所有病例(例如下面提到的TCGA-LAML )。
在SOAP Ui中，当我以JSON格式发布以下请求时，.It会给我完美的答案{ "filters"：{"op":" in "，"content":{ "field":"cases.project.project_id"，"value":"TCGA-LAML“}
但我必须通过java客户端调用POST。即使经过努力，我也不能正确地设置输入参数。
我在这里发布我的代码。你能帮我改正代码吗？
package downloadtoolproject;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.net.HttpURLConnection;
import java.net.URL;
public class Newtest {
public static String sendPostRequest(String requestUrl, String payload) {
StringBuffer jsonString = new StringBuffer();
try {
URL url = new URL(requestUrl);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setRequestMethod("POST");
connection.setRequestProperty("Accept", "application/json");
connection.setRequestProperty("Content-Type", "application/json");
OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream());
writer.write(payload);
writer.close();
BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String line;
while ((line = br.readLine()) != null)
{
jsonString.append(line);
System.out.println(line);
}
br.close();
connection.disconnect();
}
catch (Exception e) {
throw new RuntimeException(e.getMessage());
}
return jsonString.toString() ;
}
public static void main(String [] args)
{
String payload = "{\"field\":\"project_id\",\"value\":[\"TCGA-LAML\"]}";
String requestUrl="https://api.gdc.cancer.gov/cases";
sendPostRequest(requestUrl, payload);
}
}回答 1
Stack Overflow用户
回答已采纳
发布于 2018-07-30 03:30:43
我认为下面的解决方案应该对你有效
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.net.HttpURLConnection;
import java.net.URL;
import java.util.ArrayList;
import java.util.List;
public class Newtest {
public static String sendPostRequest(String requestUrl, String payload) {
StringBuffer jsonString = new StringBuffer();
try {
URL url = new URL(requestUrl);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setRequestMethod("POST");
connection.setRequestProperty("Accept", "application/json");
connection.setRequestProperty("Content-Type", "application/json");
OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream());
writer.write(payload);
writer.close();
BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String line;
while ((line = br.readLine()) != null) {
jsonString.append(line);
System.out.println(line);
}
br.close();
connection.disconnect();
} catch (Exception e) {
throw new RuntimeException(e.getMessage());
}
return jsonString.toString();
}
public static void main(String[] args) {
List<String> values = new ArrayList<>();
values.add("TCGA-LAML");
String requestUrl = "https://api.gdc.cancer.gov/cases";
sendPostRequest(requestUrl, preparePayload(values));
}
private static String preparePayload(List<String> values) {
StringBuilder sb = new StringBuilder();
for (String value : values) {
sb.append("\"" + value + "\",");
}
String desiredValue = sb.toString().substring(0, sb.toString().length() - 1);
return "{ \"filters\": {\"op\":\"in\", \"content\":{ \"field\":\"cases.project.project_id\", \"value\":[" + desiredValue + "] } } }";
}
}您只需要添加values列表中的所有输入值，并将其传递给preparePayload方法，它会将其转换为有效负载。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51583206
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