Bootstrap Popover:悬停/单击并关闭外部单击，但恢复为悬停模式
Bootstrap Popover:悬停/单击并关闭外部单击，但恢复为悬停模式
提问于 2018-08-21 01:09:18
在下面的代码片段中，我有一个Bootstrap Popover，它同时支持Hover和Click模式。单击时，窗口将保持打开状态，并应在(1)自单击(再次链接)或(2)任何外部单击时关闭。
问题:在外部单击后，弹出框转到"currently “模式。这意味着如果您再次将鼠标悬停在该窗口上，该窗口将被卡住并且不会消失。应该发生的是，在外部单击之后，当您再次将鼠标悬停在它上面时，您将恢复到原始的悬停并消失模式。这里预期的行为与在单击内部关闭后悬停时的行为相同，这是原始状态。我是不是忘了什么？
$('#linkPopover').popover({
trigger: 'hover click',
content: 'This is my content',
title: 'TITLE'
});
// -----------------
// Just with the above (and no other code), the Hover and Click-Toggle
// works within the SAME Popover window,
// but now I need to also remove the visible Popover on ANY CLICK OUTSIDE.
// However, although the below works, *after* clicking outside the Popover is in the CLICKED
// mode i.e. it doesn't hover anymore
$('body').on('click', function(e) {
$('[data-toggle="popover"]').each(function () {
if (!$(this).is(e.target) && $(this).has(e.target).length === 0 && $('.popover').has(e.target).length === 0) {
// From outside click with the popover open, need to hide
$(this).popover('hide');
}
});
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.7/js/bootstrap.min.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet"/>
<a id="linkPopover" data-toggle="popover">POPOVER</a>
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<br/><br/><br/><br/><br/><br/><br/>
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回答 3
Stack Overflow用户
回答已采纳
发布于 2018-08-21 01:48:55
这段代码可能会对你有所帮助。我更改了条件语句，以检查用户是否在popover触发器之外单击&如果popover可见，则触发popover触发器的click事件。
我之所以考虑这样做，是因为click事件是当您单击触发器本身时发生的事件。
$(document).ready(function(){
$('#linkPopover').popover({
trigger: 'hover click',
content: 'This is my content',
title: 'TITLE'
});
$('body').on('click', function(e) {
$('[data-toggle="popover"]').each(function () {
if(!$(this).is(e.target) && ($("#linkPopover").next('div.popover:visible').length)){
$("#linkPopover").trigger('click');
}
});
});
});<script
src="https://code.jquery.com/jquery-3.3.1.min.js"
integrity="sha256-FgpCb/KJQlLNfOu91ta32o/NMZxltwRo8QtmkMRdAu8="
crossorigin="anonymous"></script>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css" integrity="sha384-MCw98/SFnGE8fJT3GXwEOngsV7Zt27NXFoaoApmYm81iuXoPkFOJwJ8ERdknLPMO" crossorigin="anonymous">
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/js/bootstrap.min.js" integrity="sha384-ChfqqxuZUCnJSK3+MXmPNIyE6ZbWh2IMqE241rYiqJxyMiZ6OW/JmZQ5stwEULTy" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.3/umd/popper.min.js" integrity="sha384-ZMP7rVo3mIykV+2+9J3UJ46jBk0WLaUAdn689aCwoqbBJiSnjAK/l8WvCWPIPm49" crossorigin="anonymous"></script>
<body>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.7/js/bootstrap.min.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet"/>
<a id="linkPopover" data-toggle="popover">POPOVER</a>
<br/><br/><br/><br/><br/><br/><br/>
<br/><br/><br/><br/><br/><br/><br/>
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</body>
Stack Overflow用户
发布于 2018-08-23 00:20:43
实际上，我在body.click中引入了一个自定义标志参数，从而解决了eminememinem原始答案(由于trigger('click'))中的无限循环问题。您可以这样做：
$('body').on('click', function (e, manualClickTriggered) {我们在我们自己重新触发的特殊情况下设置标志。如果是这样，我们就忽略常规逻辑。
完整代码段：
$('[id*="linkPopover"]').popover({
trigger: 'hover click',
content: 'This is my content',
title: 'TITLE'
});
// Close any visible popover if clicked outside
// The "manualClickTriggered" flag indicates that we initiated the special Click event ourselves in order to turn off the popover, in which case skip the regular logic.
$('body').on('click', function (e, manualClickTriggered) {
var linkId = null;
if (e.target.id.indexOf("linkPopover") != -1) {
linkId = e.target.id;
}
if (manualClickTriggered != true) {
if (e.target.id.indexOf("linkPopover") == -1) { // Not coming from any Popover Link (outside click)
$('a[id^="linkPopover"][data-toggle="popover"]').each(function () {
if( !$(this).is(e.target) && ($(this).next('div.popover:visible').length )) {
$(this).trigger('click', true);
}
});
}
else // Coming from some Popover link
{
$('a[id^="linkPopover"][data-toggle="popover"]').each(function () {
if ($(this).attr('id') != linkId && $(this).next('div.popover:visible').length) {
$(this).trigger('click', true);
}
});
}
}
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.7/js/bootstrap.min.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet"/>
<a id="linkPopover1" data-toggle="popover">POPOVER 1</a><br/>
<a id="linkPopover2" data-toggle="popover">POPOVER 2</a><br/>
<a id="linkPopover3" data-toggle="popover">POPOVER 3</a><br/>
<a id="linkPopover4" data-toggle="popover">POPOVER 4</a><br/>
<br/><br/><br/><br/><br/><br/><br/>
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<br/><br/><br/><br/><br/><br/><br/>
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Stack Overflow用户
发布于 2018-08-22 23:34:09
我的第一个答案产生了Maximum call stack size exceeded错误，这是由于存在超过1个弹出窗口时的无限循环造成的(参见我的第一个答案和注释)。
要解决这个问题:每当系统要执行trigger('click')时，我都会在主体单击处理程序上使用.off。之后，我重新初始化了body click处理程序。请参见下面的示例。
$(document).ready(function(){
function initializeClick(){
$('body').on('click', function(e) {
$('[data-toggle="popover"]').each(function () {
if(!$(this).is(e.target) && ($(this).next('div.popover:visible').length)){
$('body').off('click');
$(this).trigger('click');
initializeClick();
}
});
});
}
$('#linkPopover').popover({
trigger: 'hover click',
content: 'This is my content',
title: 'TITLE'
});
$('#linkPopover2').popover({
trigger: 'hover click',
content: 'This is my content',
title: 'TITLE'
});
$('body').on('click', function(e) {
$('[data-toggle="popover"]').each(function () {
if(!$(this).is(e.target) && ($(this).next('div.popover:visible').length)){
$('body').off('click');
$(this).trigger('click');
initializeClick();
}
});
});
}); <script
src="https://code.jquery.com/jquery-3.3.1.min.js"
integrity="sha256-FgpCb/KJQlLNfOu91ta32o/NMZxltwRo8QtmkMRdAu8="
crossorigin="anonymous"></script>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css" integrity="sha384-MCw98/SFnGE8fJT3GXwEOngsV7Zt27NXFoaoApmYm81iuXoPkFOJwJ8ERdknLPMO" crossorigin="anonymous">
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/js/bootstrap.min.js" integrity="sha384-ChfqqxuZUCnJSK3+MXmPNIyE6ZbWh2IMqE241rYiqJxyMiZ6OW/JmZQ5stwEULTy" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.3/umd/popper.min.js" integrity="sha384-ZMP7rVo3mIykV+2+9J3UJ46jBk0WLaUAdn689aCwoqbBJiSnjAK/l8WvCWPIPm49" crossorigin="anonymous"></script>
<body>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.7/js/bootstrap.min.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet"/>
<a id="linkPopover" class="btn btn-light" data-toggle="popover">POPOVER</a>
<a id="linkPopover2" class="btn btn-light" data-toggle="popover">POPOVER2</a>
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</body>
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原文链接：
https://stackoverflow.com/questions/51935548
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